Difficulty: Easy
Correct Answer: 001011100₂
Explanation:
Introduction / Context:
Octal (base-8) digits map neatly to binary in groups of three bits because 8 = 2^3. Converting octal to binary is therefore a simple table-lookup process per digit.
Given Data / Assumptions:
Concept / Approach:
Translate each octal digit to its 3-bit binary equivalent and concatenate in order. Leading zeros within a group are retained to preserve the 3-bit alignment that reflects the original octal digits.
Step-by-Step Solution:
Map: 1→001, 3→011, 4→100.Concatenate: 001 011 100 → 001011100₂.
Verification / Alternative check:
Convert back by grouping binary in 3s: 001→1, 011→3, 100→4 → 134₈. The cycle validates the result.
Why Other Options Are Wrong:
(a) differs in the middle group, (b) mismaps groups, (d) discards necessary leading zeros and groups incorrectly.
Common Pitfalls:
Omitting leading zeros in the leftmost group and misreading the resulting octal digits.
Final Answer:
001011100₂.
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