Boolean evaluation: which of the following Boolean OR expressions is incorrect under standard Boolean algebra rules (where 1 represents logic HIGH and “+” denotes OR)?

Introduction / Context:Boolean algebra uses 1 and 0 to denote TRUE and FALSE (or HIGH and LOW). The OR operation (“+”) outputs 1 if any operand is 1. This question asks you to identify which expression violates the standard truth of OR.

Given Data / Assumptions:

• Use standard Boolean OR: 0 + 0 = 0; 0 + 1 = 1; 1 + 0 = 1; 1 + 1 = 1.
• Associativity allows grouping without changing results.
• We assume no XOR; “+” is strictly OR here.

Concept / Approach:Check each option against the OR truth rules. Any sum including a 1 must be 1, including 1 + 1 which equals 1, not 0. Multi-operand OR remains 1 if at least one operand is 1.

Step-by-Step Solution:

Verification / Alternative check:Truth tables confirm 1 OR 1 = 1. No standard Boolean system makes 1 + 1 = 0; that result would correspond to XOR, not OR.

Why Other Options Are Wrong:

Common Pitfalls:Confusing OR with XOR; XOR of 1 and 1 is 0, but this question uses OR (+), not XOR (⊕).

Final Answer:1 + 1 = 0