Question 1

The temperature at which a solid substance melts and becomes a liquid at standard atmospheric pressure is called its ___________.

Accepted Answer

Introduction / Context: This question concerns basic physical properties of substances, specifically the temperature at which a solid changes to a liquid. Understanding terms like melting point and boiling point is fundamental in chemistry and physics and helps you describe phase changes and identify substances based on characteristic temperatures. Given Data / Assumptions: The process described is a solid melting to form a liquid. It occurs at a defined temperature under atmospheric pressure. Options include crystallisation, melting point, evaporation, galvanisation and boiling point. We assume standard atmospheric pressure, typically one atmosphere. Concept / Approach: The temperature at which a solid and its liquid form coexist in equilibrium at a given pressure is called the melting point. At this temperature, the solid absorbs heat and changes into liquid without any further increase in temperature until the phase change is complete. Crystallisation is the process of forming crystals, evaporation is liquid to gas, galvanisation is coating iron with zinc, and boiling point is the temperature at which liquid turns to gas. Only melting point refers specifically to the temperature where solid becomes liquid. Step-by-Step Solution: Step 1: Identify the direction of change: solid to liquid on heating. Step 2: Recall the definition of melting point: it is the temperature at which a solid turns into a liquid at a specified pressure, usually atmospheric pressure. Step 3: Compare this with boiling point, which is the temperature at which a liquid turns into vapour (gas) at atmospheric pressure. Step 4: Crystallisation describes the process of forming a crystalline solid from a liquid or solution, not the specific temperature of melting. Step 5: Evaporation is a gradual surface phenomenon where liquid molecules escape into the gas phase at temperatures below boiling point. Step 6: Galvanisation is a method of protecting iron by coating it with zinc and is not related to phase changes. Step 7: Therefore, the only option that correctly names the temperature where solid becomes liquid is melting point. Verification / Alternative check: Examples from daily life support this definition. Ice melts to water at 0 degrees Celsius under standard atmospheric pressure, so 0 degrees Celsius is called the melting point of ice. Similarly, pure iron has a melting point of about 1538 degrees Celsius, which is used in metallurgical processes. Boiling points are reported separately, such as water boiling at 100 degrees Celsius. The consistent use of the term melting point in tables of physical constants confirms that this is the correct term for the temperature in question. Why Other Options Are Wrong: Crystallisation refers to the process, not a fixed temperature, and more often describes liquid or solution turning into a solid. Evaporation and boiling point focus on liquid to gas changes, not solid to liquid. Galvanisation is a surface treatment process and has nothing to do with melting. Therefore, none of these terms correctly describe the temperature at which a solid melts to become a liquid at atmospheric pressure. Common Pitfalls: Students sometimes confuse melting point and boiling point because both involve phase changes and are listed in data tables. A helpful tip is to remember that melting always refers to solid to liquid, while boiling refers to liquid to gas. Another pitfall is to think of crystallisation as synonymous with freezing, but crystallisation can occur from solutions as well and does not refer to a single temperature in the same precise way that melting point does. Final Answer: The temperature at which a solid melts and becomes a liquid at atmospheric pressure is called its melting point.

Question 2

Which of the following statements correctly describes alpha particles in the context of radioactivity?

Accepted Answer

Introduction / Context: This question belongs to nuclear chemistry and radioactivity. Alpha particles are one of the three main types of nuclear radiation, along with beta particles and gamma rays. Understanding what alpha particles physically are helps explain their charge, mass, ionizing power and penetration ability. The question asks which statement correctly describes alpha particles, so you must pick the statement that matches their true nature. Given Data / Assumptions: Alpha particles are emitted in some radioactive decays. Options describe their mass, charge, relation to helium nuclei, ionizing power and masslessness. We assume standard textbook definitions. Concept / Approach: An alpha particle consists of two protons and two neutrons bound together, which is exactly the composition of the nucleus of a helium atom. Therefore, an alpha particle is essentially a helium nucleus with a charge of plus two and a relatively large mass compared to electrons and beta particles. It is positively charged, strongly ionizing, and has low penetration power compared to beta and gamma radiation. Any statement that describes alpha particles as negatively charged, massless or less ionizing than gamma rays is incorrect. Step-by-Step Solution: Step 1: Recall that alpha decay occurs when an unstable nucleus emits an alpha particle of two protons and two neutrons. Step 2: The nucleus of a helium atom, also called a helium 4 nucleus, consists of two protons and two neutrons, which matches the composition of an alpha particle. Step 3: Therefore, the statement that alpha particles are just like helium nuclei is correct. Step 4: Examine option A, claiming alpha particles have about twice the mass of beta particles. In reality, an alpha particle is much more massive than a beta particle, which is essentially an electron or positron. The mass difference is far more than a factor of two, so this description is misleading. Step 5: Option B states that alpha particles are negatively charged, which is false; they carry a charge of plus two because of their two protons and no electrons. Step 6: Option D claims they have lower ionizing power than gamma rays, which is the opposite of what is true. Alpha particles are strongly ionizing but have low penetration, while gamma rays are weakly ionizing but highly penetrating. Step 7: Option E describes them as massless neutral particles, which would be closer to photons or neutrinos, not alpha particles. Step 8: Therefore, the only correct description is that alpha particles are just like helium nuclei. Verification / Alternative check: Nuclear equations reinforce this view. For example, when uranium 238 decays to thorium 234, it emits an alpha particle written as 4 2 He, clearly representing a helium nucleus. The notation with mass number 4 and atomic number 2 is standard and directly links alpha particles with helium nuclei. This is widely taught in nuclear chemistry and physics, confirming that identifying alpha particles as helium nuclei is correct. Why Other Options Are Wrong: Alpha particles are not slightly heavier than beta particles; they are thousands of times more massive because beta particles are essentially electrons. They are positively charged, not negatively charged. Their ionizing power is higher, not lower, than that of gamma rays. They certainly are not massless neutral particles like photons. These incorrect descriptions conflict with experimental evidence and standard teaching on radioactivity. Common Pitfalls: Students may misremember the comparison of ionizing and penetrating power of the three types of radiation. A useful rule is that alpha particles are highly ionizing but weakly penetrating (stopped by paper), beta particles have moderate ionizing and penetrating power, and gamma rays are weakly ionizing but highly penetrating. Mixing up these trends can lead to wrong choices in questions like this. Keeping the helium nucleus image in mind helps fix the properties of alpha particles more securely. Final Answer: Alpha particles are correctly described as just like helium nuclei composed of two protons and two neutrons.

Question 3

Among the elements oxygen, gold, silver and manganese, which one has the lowest melting point?

Accepted Answer

Introduction / Context: This question asks you to compare melting points of different elements from both metals and non metals. Melting point is the temperature at which a solid turns into a liquid. Generally, metals with strong metallic bonding have high melting points, whereas molecular substances composed of small molecules often have very low melting points. Recognising that oxygen is a diatomic gas at room temperature while the others are solid metals helps you choose the correct answer. Given Data / Assumptions: Elements to compare: oxygen, gold, silver and manganese. We must identify the one with the lowest melting point. We assume standard atmospheric pressure and pure elements. Concept / Approach: Oxygen at normal conditions exists as O2 molecules and is a gas at room temperature. Its melting point is very low, far below zero degrees Celsius. In contrast, gold, silver and manganese are metallic solids with relatively high melting points due to strong metallic bonding. Therefore, the gaseous element oxygen will have the lowest melting point among the four. Step-by-Step Solution: Step 1: Classify the elements. Oxygen is a non metal that exists as diatomic O2 gas at room temperature. Gold, silver and manganese are solid metals. Step 2: Recall that gases at room temperature must have very low melting and boiling points, because their intermolecular forces are weak. Step 3: Oxygen becomes a pale blue liquid at very low temperatures and then a solid at even lower temperatures, so its melting point is far below the melting points of typical metals. Step 4: Gold and silver are noble metals with strong metallic bonds and have high melting points in the range of hundreds of degrees Celsius. Step 5: Manganese is also a metal and has a high melting point, again much higher than that of molecular oxygen. Step 6: Since oxygen is already a gas at ordinary conditions, its melting point is the lowest among the given elements. Step 7: Therefore, the correct answer is oxygen. Verification / Alternative check: Approximate data from reference tables show that oxygen melts at about minus two hundred degrees Celsius, while the melting points of gold, silver and manganese are all above several hundred or more than one thousand degrees Celsius. Although you are not expected to know the exact numbers in a typical exam, recognising that metals usually melt at high temperatures and gases at very low temperatures is sufficient to compare which is lowest. Why Other Options Are Wrong: Gold, silver and manganese are solid metals at room temperature and require high temperatures to melt. Their metallic bonds involve a lattice of positive metal ions embedded in a sea of delocalised electrons, which requires significant energy to break. Therefore, their melting points are far higher than that of oxygen. The option stating that all have similar melting points is clearly incorrect because one is a gas and the others are solids under normal conditions. Common Pitfalls: A potential mistake is to recall that gold and silver are relatively soft metals and assume that softness means low melting point. In reality, softness refers to mechanical hardness, not melting point. Gold still has a high melting point despite being malleable. Another pitfall is to forget that oxygen is a gas at room temperature and treat it like a solid element. Remembering the physical state of elements at room temperature can help you compare their melting and boiling points more reliably. Final Answer: Among oxygen, gold, silver and manganese, the element with the lowest melting point is oxygen.

Question 4

In materials science and plastics engineering, what is the full form of the abbreviation PVC, which is a widely used synthetic polymer in pipes, cables, flooring, and packaging?

Accepted Answer

Introduction / Context: Polymeric materials are commonly referred to by short abbreviations such as PVC, PET, and HDPE in both industry and everyday life. Understanding the full forms of these abbreviations helps in recognising the underlying monomers and the properties of the plastics we use. PVC is one of the most common and versatile plastics, especially in construction, where it is used for pipes, window frames, cables, and flooring. This question checks whether you can correctly expand the abbreviation PVC into its full chemical name. Given Data / Assumptions: The abbreviation given is PVC. PVC is described as a widely used synthetic polymer. The options provide different possible expansions involving the words “vinyl”, “carbon” or “chloride”. We assume standard naming conventions used in polymer chemistry and industry. Concept / Approach: PVC stands for Polyvinyl Chloride. The term “polyvinyl” indicates that the polymer is formed by the polymerisation of a vinyl based monomer. In this case, the monomer is vinyl chloride (CH2=CHCl). When many vinyl chloride molecules join together in an addition polymerisation reaction, they form the polymer chain known as polyvinyl chloride. The word “chloride” in the name reflects the presence of chlorine atoms in the repeating units, which strongly influence the material's properties such as rigidity, flame resistance, and chemical stability. Step-by-Step Solution: Step 1: Recall where PVC is used in daily life, such as pipes, wires, and vinyl flooring. Step 2: Connect PVC to its monomer, which is vinyl chloride (CH2=CHCl). Step 3: Recognise that when many vinyl chloride molecules polymerise, the resulting material is polyvinyl chloride. Step 4: Among the given options, identify the one that exactly matches this correct expansion: “Polyvinyl Chloride”. Step 5: Confirm that the other expansions either misuse the word “vinyl” or incorrectly introduce “carbonate” instead of “chloride”. Verification / Alternative check: Basic chemistry textbooks and packaging labels for pipes and cables frequently refer to “PVC (Polyvinyl Chloride)”. Safety data sheets and industrial catalogs also consistently expand PVC as polyvinyl chloride. The molecular structure can be represented as repeating –CH2–CHCl– units, clearly showing the chloride component. No reliable source refers to PVC as “polyvinyl carbonate” or “phosphonil vinyl carbonate”. This consistent usage across many real world references confirms that Polyvinyl Chloride is the only valid full form for PVC in this context. Why Other Options Are Wrong: Option A (Phosphonil vinyl Carbonate): This phrase combines terms that do not describe the widely used PVC plastic and is not recognised as a standard polymer name. Option B (Polyvinyl S Carbonate): The inclusion of “S” and “carbonate” is incorrect and does not match any common industrial plastic abbreviated as PVC. Option C (Polyvinyl Carbonate): While it sounds chemically plausible, it is not the established name for PVC and does not reflect the presence of chlorine in the polymer. Common Pitfalls: Some learners misread PVC as being related to “carbonates” because many polymer names end in “-ate”, or they assume that any “polyvinyl” material could be PVC. Others may not realise that the “C” in PVC stands for “Chloride” and instead guess it stands for “Carbonate”. To avoid this, remember that PVC is derived from vinyl chloride and used heavily in the construction industry, and that its full form must therefore include both “polyvinyl” and “chloride”. Final Answer: The full form of PVC is Polyvinyl Chloride.

Question 5

In organic chemistry, aromatic hydrocarbons are compounds that contain at least how many benzene-like rings in their molecules to be classified as aromatic?

Accepted Answer

Introduction / Context: Aromatic hydrocarbons are a special class of organic compounds that contain one or more benzene-like rings and exhibit characteristic stability and reactivity. These compounds play a central role in petrochemicals, dyes, pharmaceuticals, and many other industrial products. Understanding what makes a hydrocarbon aromatic, and the minimum structural requirement for aromaticity, is a basic concept in organic chemistry and is frequently tested in competitive exams. Given Data / Assumptions: The question refers specifically to aromatic hydrocarbons. It mentions “benzene like ring”, indicating a six membered ring with alternating double bonds (delocalised pi system). The options list different integers: 4, 3, 2, and 1. We assume the classical definition of aromatic hydrocarbons as containing one or more benzene-like rings. Concept / Approach: Aromatic hydrocarbons, often called arenes, are defined as hydrocarbons that contain at least one benzene ring or a similar conjugated ring system that follows aromaticity rules (such as Huckel's rule). The simplest aromatic hydrocarbon is benzene itself, which has a single benzene ring and is clearly aromatic. Larger aromatic hydrocarbons such as naphthalene, anthracene, and phenanthrene contain two or more fused benzene rings. However, the minimum requirement for a compound to be called an aromatic hydrocarbon is the presence of at least one benzene-like ring in its structure. Step-by-Step Solution: Step 1: Recall the definition of aromatic hydrocarbon (arene). An aromatic hydrocarbon contains one or more benzene-like rings with delocalised pi electrons. Step 2: Consider the simplest example. Benzene (C6H6) has a single benzene ring and is classified as aromatic, so one ring is sufficient. Step 3: Generalise to other arenes. Compounds like toluene and xylene also have just one benzene ring and are still aromatic hydrocarbons. Step 4: Conclude that “at least one” benzene-like ring is the requirement, corresponding to the option 1. Verification / Alternative check: Standard organic chemistry textbooks define benzene and its derivatives (toluene, chlorobenzene, nitrobenzene, etc.) as aromatic compounds even though they have only one benzene ring. More complex polycyclic aromatics such as naphthalene (two rings) and anthracene (three rings) are also aromatic, but they are not required for the basic definition. The phrase “one or more benzene rings” is repeatedly used in exam oriented material. This confirms that the minimum count is one benzene-like ring, making option 1 correct. Why Other Options Are Wrong: Option A (4): While some polycyclic aromatics do contain multiple rings, four rings are not required for aromaticity. Option B (3): Three fused benzene rings occur in anthracene and phenanthrene, but compounds with fewer rings are still aromatic. Option C (2): Naphthalene has two rings, but benzene and many aromatic derivatives with only one ring exist and are clearly aromatic. Common Pitfalls: Learners sometimes confuse the term “aromatic” with “polycyclic”, assuming that multiple rings are always necessary. Another confusion is caused by the word “aromatic” itself, which historically referred to smell rather than structure. Today, aromaticity is defined by electronic structure and ring current, not by odour. To avoid mistakes, remember the simple rule that any hydrocarbon with at least one benzene-like ring and delocalised pi electrons is aromatic, starting from benzene itself with just a single ring. Final Answer: Aromatic hydrocarbons contain at least 1 benzene-like ring in their molecules.

Question 6

In metallurgy and economic geology, chromite is an important ore or mineral source of which metal that is used in stainless steel and electroplating?

Accepted Answer

Introduction / Context: Ores are naturally occurring rocks or minerals from which metals can be extracted economically. Knowing the major ores of common metals is a standard part of general chemistry and geology, and is frequently tested in competitive exams. Chromite is a dark, iron chromium oxide mineral that serves as the principal ore of chromium, a metal that gives stainless steel its corrosion resistance and is also used in plating and pigments. This question asks you to connect the name of the ore, chromite, with its metal, chromium. Given Data / Assumptions: The ore or mineral mentioned is chromite. The options include four metals: zinc, uranium, chromium, and titanium. We assume standard school level knowledge of important ores and their associated metals. Chromite is chemically an oxide containing chromium and iron. Concept / Approach: Chromite has the approximate chemical formula FeCr2O4 and is an oxide of iron and chromium. It is the main commercial source of chromium metal. The name itself contains the root “chrom”, which is related to chromium and colour. During extraction, chromite is processed to produce chromium compounds and ultimately metallic chromium, which is used in stainless steel, alloys, and electroplating. Zinc, uranium, and titanium all have different primary ores (such as sphalerite for zinc, pitchblende for uranium, and ilmenite or rutile for titanium) and are not derived chiefly from chromite. Step-by-Step Solution: Step 1: Recall the formula and name of chromite. Chromite is often represented as FeCr2O4 and is an iron chromium oxide. Step 2: Identify the key metal present along with iron. The formula clearly shows chromium (Cr) as a major component. Step 3: Connect chromite to industrial uses. Chromite deposits are mined to produce chromium for stainless steel and plating. Step 4: Match this with the options and select “Chromium” as the metal of which chromite is an ore. Verification / Alternative check: Lists of common ores in textbooks usually pair chromite with chromium, just as bauxite is paired with aluminium and haematite with iron. Chromium itself is not found free in nature; it must be extracted from chromite or similar chromium bearing minerals. In contrast, zinc's common ore is zinc blende (sphalerite, ZnS), uranium's ore is often pitchblende (U3O8), and titanium is commonly obtained from ilmenite (FeTiO3) or rutile (TiO2). This consistent association of chromite with chromium confirms that chromium is the correct answer. Why Other Options Are Wrong: Option A (Zinc): Zinc is obtained mainly from ores such as sphalerite (zinc blende), not chromite. Option B (Uranium): Uranium ores include pitchblende and carnotite; chromite is not a significant uranium source. Option D (Titanium): Titanium is commonly extracted from ilmenite and rutile, not from chromite. Common Pitfalls: Students sometimes mix up ore names because many contain similar sounding endings like “-ite” and “-ate”. Another mistake is to guess based on which metal feels more “familiar” rather than recalling the correct ore-metal pair. A simple memory aid is that “chromite” and “chromium” share the same “chrom-” root, making the connection clearer. Regularly revising a table of common ores and their metals is helpful for quickly answering such questions in exams. Final Answer: Chromite is an ore or mineral of Chromium.

Question 7

In nuclear chemistry and radioactivity, which of the following statements about alpha (α) particles is false or incorrect?

Accepted Answer

Introduction / Context: Alpha particles, beta particles, and gamma rays are three main types of nuclear radiation. Each has different mass, charge, speed, ionizing power, and penetrating power. Understanding these differences is crucial in nuclear chemistry, radiotherapy, and radiation safety. This question focuses on alpha particles and asks you to identify which statement about their properties is false, meaning it contradicts the actual behaviour of alpha radiation. Given Data / Assumptions: The radiation type under discussion is the alpha (α) particle. Alpha particles are known to be helium nuclei. The options refer to ionizing power, penetrating power, kinetic energy, and their nuclear identity. We assume standard comparative descriptions relative to beta and gamma radiation. Concept / Approach: An alpha particle is essentially a helium nucleus consisting of two protons and two neutrons, carrying a +2 charge and relatively large mass compared to beta particles and gamma photons. Because of this mass and charge, alpha particles interact strongly with matter, causing very high ionization along a short path. As a result, they lose energy quickly and have low penetrating power: they can be stopped by a sheet of paper or even the outer layer of human skin. They may have high kinetic energy when emitted, and they certainly have high ionizing power, but they do not have high penetrating power. Therefore, any statement claiming high penetrating power for alpha particles is false. Step-by-Step Solution: Step 1: Recall the physical nature of alpha particles. Alpha particles are helium nuclei (2 protons + 2 neutrons) with a +2 charge. Step 2: Examine ionizing power. Due to their large mass and charge, alpha particles cause intense ionization in a short distance; they have high ionizing power. Step 3: Examine penetrating power. Because they interact so strongly, they are stopped quickly and therefore have very low penetrating power. Step 4: Examine kinetic energy. Alpha particles are emitted from nuclei with significant kinetic energy, enough to cause damage along their short path. Step 5: Identify the false statement: the claim that alpha particles have high penetrating power directly contradicts the known low penetration of alpha radiation. Verification / Alternative check: Comparative tables of nuclear radiations usually list alpha particles as “high ionization, low penetration”, beta particles as “moderate ionization, moderate penetration”, and gamma rays as “low ionization, very high penetration”. Practical demonstrations show that a sheet of paper or a few centimetres of air can stop most alpha particles, while beta particles require aluminium and gamma rays need thick lead or concrete shielding. Medical physics discussions also emphasise that alpha radiation is dangerous if ingested or inhaled, but not very dangerous externally precisely because it cannot penetrate the outer dead layer of skin. All of these observations confirm that high penetrating power is not a property of alpha particles. Why Other Options Are Wrong (i.e., actually true statements): Option A (They have high ionizing power): This is true; alpha particles ionize matter very strongly over a short distance. Option C (They have high kinetic energy): Alpha particles are emitted with considerable kinetic energy and can cause severe local damage if they reach living tissue. Option D (They are positively charged helium nuclei): This is the standard definition of an alpha particle. Common Pitfalls: Students often confuse ionizing power with penetrating power, incorrectly thinking that a more ionizing radiation must automatically penetrate more deeply. In reality, high ionization means the radiation loses its energy quickly and is stopped in a short distance, which reduces penetration. Remember the rule of thumb: alpha has high ionization but low penetration, beta is in the middle for both, and gamma has low ionization but very high penetration. Keeping this trio comparison in mind helps avoid such conceptual mistakes. Final Answer: The false statement is that alpha particles have high penetrating power; in reality, their penetrating power is low.

Question 8

In basic redox chemistry, which of the following is not a characteristic feature of an oxidation reaction according to modern definitions?

Accepted Answer

Introduction / Context: Oxidation and reduction reactions are central concepts in chemistry, from corrosion and combustion to metabolism and industrial processes. Over time, the definition of oxidation has been refined, but several equivalent descriptions are still used in textbooks. This question asks you to identify which statement is not a characteristic of oxidation, meaning it actually describes the opposite process, reduction. Recognising these alternative definitions prevents confusion when you encounter redox reactions in different contexts. Given Data / Assumptions: The focus is on oxidation reactions. The options mention addition of hydrogen, addition of oxygen, loss of electrons, and addition of an electronegative element. We assume modern redox definitions that relate oxidation to both electron transfer and changes in element combinations. We also assume basic familiarity with the concept of reduction as the opposite of oxidation. Concept / Approach: Historically, oxidation was defined as a process involving addition of oxygen or removal of hydrogen. Later, a more general electron based definition was adopted: oxidation is the loss of electrons, and reduction is the gain of electrons. Another equivalent way of thinking is that oxidation involves addition of an electronegative element (like oxygen, halogens) or removal of an electropositive element (like hydrogen). Reduction, on the other hand, can involve the addition of hydrogen, loss of oxygen, or gain of electrons. Thus, while addition of oxygen, loss of electrons, and addition of an electronegative element all describe oxidation, addition of hydrogen is characteristic of reduction, not oxidation. Step-by-Step Solution: Step 1: Recall the electron based definition. Oxidation is loss of electrons; reduction is gain of electrons. Step 2: Recall the oxygen and hydrogen based definitions. Oxidation often involves addition of oxygen or removal of hydrogen, while reduction often involves addition of hydrogen or removal of oxygen. Step 3: Examine each option. Addition of oxygen is consistent with oxidation. Loss of electrons is the core modern definition of oxidation. Addition of an electronegative element like oxygen or halogens is also oxidation. Addition of hydrogen, however, is characteristic of reduction, not oxidation. Step 4: Conclude that “It involves addition of hydrogen” is not a characteristic of oxidation. Verification / Alternative check: Consider a simple example: the conversion of ethene (C2H4) to ethane (C2H6) by addition of hydrogen. Here, hydrogen is added, and the carbon atoms become more reduced (they gain electrons in effect); this is a reduction process. In contrast, when iron reacts with oxygen to form rust (iron oxide), oxygen is added and iron is oxidised. Another example is the reaction of hydrogen sulfide with chlorine, where sulfur is oxidised as it loses electrons and the electronegative element chlorine is added. These examples illustrate that addition of hydrogen is linked with reduction, whereas oxidation is linked with oxygen addition, electron loss, or addition of electronegative elements. Why Other Options Are Wrong (i.e., they truly describe oxidation): Option B (It involves addition of oxygen): This matches the classical definition of oxidation in many reactions, especially combustion and metal oxidation. Option C (It involves loss of electrons): This is the core modern definition of oxidation in redox chemistry. Option D (It involves addition of an electronegative element): Adding elements like oxygen or chlorine generally corresponds to oxidation, as these species attract electrons. Common Pitfalls: A frequent problem is mixing up the older oxygen based definition with the hydrogen based one and forgetting which direction corresponds to oxidation versus reduction. Another issue is focusing only on one definition (for example, only “gain of oxygen”) and not being able to recognise oxidation when it occurs through a different mechanism such as electron loss. To avoid these mistakes, remember the summary: oxidation is loss of electrons, gain of oxygen, or loss of hydrogen; reduction is gain of electrons, loss of oxygen, or gain of hydrogen. In that summary, “addition of hydrogen” clearly belongs on the reduction side, not oxidation. Final Answer: The process that is not a characteristic of oxidation is It involves addition of hydrogen, because that describes reduction.

Question 9

In mineralogy and gemstone chemistry, turquoise is an ornamental ore or mineral that serves as a source of which metal?

Accepted Answer

Introduction / Context: Turquoise is a well known blue to green ornamental stone used in jewellery and decorative objects for thousands of years. In addition to its aesthetic value, it is also a mineral containing certain metals in its structure. Questions in general chemistry and geology often ask you to identify which metal is associated with a particular coloured mineral. This question focuses on turquoise and asks which metal it can be considered an ore or mineral of. Given Data / Assumptions: The mineral mentioned is turquoise, a blue-green ornamental stone. The options are metals: copper, manganese, mercury, and tin. Turquoise is known to contain metallic elements in its chemical formula. We assume standard textbook information about turquoise as a copper containing phosphate mineral. Concept / Approach: Turquoise is a hydrated phosphate of copper and aluminium, typically represented by a formula such as CuAl6(PO4)4(OH)8·4H2O. The characteristic blue to green colour of turquoise is largely due to the presence of copper ions in its structure. Although aluminium is also present, in ore classification and exam oriented questions turquoise is commonly described as a copper bearing mineral. Manganese, mercury, and tin have other common ores and are not primarily associated with turquoise in basic geology or chemistry references. Step-by-Step Solution: Step 1: Recall the colour and composition of turquoise. Turquoise is typically blue or blue-green, indicating the presence of copper. Step 2: Connect colour with metal content. Many blue and green minerals, such as malachite and azurite, owe their colour to copper, and turquoise is no exception. Step 3: Consider the chemical formula. Turquoise includes Cu (copper) and Al (aluminium) along with phosphate groups and water. Step 4: Match this with the options and select copper as the metal of which turquoise is an ore or mineral. Verification / Alternative check: Lists of coloured minerals in introductory geology and chemistry materials often describe turquoise as a hydrous phosphate of copper and aluminium. When classifying ores, copper is associated with several minerals like chalcopyrite, malachite, azurite, and turquoise. Manganese is more typically sourced from minerals like pyrolusite, mercury from cinnabar, and tin from cassiterite. Turquoise is not cited as an important ore for these latter metals. This pattern confirms that turquoise is a copper bearing mineral and is considered an ore of copper in simple exam questions. Why Other Options Are Wrong: Option B (Manganese): Common manganese ores include pyrolusite and psilomelane; turquoise is not listed among them. Option C (Mercury): Mercury is primarily obtained from cinnabar (HgS); turquoise does not contain mercury. Option D (Tin): Tin is usually extracted from cassiterite (SnO2), not from turquoise. Common Pitfalls: Students may be tempted to guess based on random association with colour or confuse turquoise with other green minerals like malachite, which is also a copper ore. While several metals can colour minerals, copper is particularly famous for producing vivid blue and green hues in gemstones and ores. A useful memory trick is to associate turquoise jewellery with other blue copper minerals like azurite; this helps reinforce the idea that turquoise is a copper containing mineral. Final Answer: Turquoise is an ore or mineral of Copper.

Question 10

At very low temperature, lead (Pb) shows a special electrical behaviour. At such low temperatures, lead behaves as which of the following types of materials?

Accepted Answer

Introduction / Context: The electrical properties of materials can change dramatically with temperature. At room temperature, metals such as copper, aluminium, and lead are good conductors, while insulators and semiconductors behave differently. However, at very low temperatures, certain metals undergo a remarkable transition to a superconducting state, in which their electrical resistance drops to nearly zero. This question asks specifically about lead and its behaviour at low temperatures, testing your awareness of superconductivity in basic physics and chemistry. Given Data / Assumptions: The material in question is lead, a heavy metal with symbol Pb. The context is behaviour at low temperature, not at room temperature. The options include semiconductor, superconductor, insulator, and conductor. We assume the concept of superconductivity as understood in school level physics. Concept / Approach: At ordinary temperatures, lead behaves like a normal metal and is a good conductor, though not as good as copper or silver. However, when cooled below a certain critical temperature (a few kelvin), lead undergoes a transition to a superconducting state. In this state, its electrical resistance becomes essentially zero and it can conduct current without energy loss. This phenomenon is called superconductivity and is observed in several elemental metals and many alloys. In contrast, semiconductors like silicon behave differently, insulators do not conduct at all, and ordinary conductors still have some resistance at all practical temperatures. Therefore, the special low temperature behaviour of lead corresponds to it becoming a superconductor. Step-by-Step Solution: Step 1: Recall the normal behaviour of lead at room temperature. Lead is a metal and thus a good electrical conductor under normal conditions. Step 2: Consider what happens at very low temperatures. Some metals, including lead, transition into a superconducting state when cooled below a critical temperature. Step 3: Understand the meaning of “superconductor”. A superconductor has practically zero electrical resistance and can maintain persistent currents without energy loss. Step 4: Match this behaviour with the given options and select “Super conductor”. Verification / Alternative check: Lists of elemental superconductors in standard physics references include metals such as lead, mercury, and tin that become superconducting at temperatures near absolute zero. Each has a specific critical temperature below which superconductivity appears. Experimental data on lead show that at such low temperatures, its resistivity drops sharply to near zero and it exhibits the Meissner effect (expulsion of magnetic fields), confirming its superconducting nature. In contrast, semiconductors like silicon or germanium become less conductive as temperature falls, and insulators never become perfect conductors. This evidence supports the conclusion that low temperature lead behaves as a superconductor. Why Other Options Are Wrong: Option A (Semi conductor): Lead is not a semiconductor; its electronic structure and behaviour at room temperature clearly identify it as a metal. Option C (Insulator): Lead does not become an insulator at low temperature; on the contrary, its resistance drops dramatically. Option D (Conductor): While lead is a conductor at room temperature, the question emphasises the special behaviour at low temperatures, which is more specific than simply “conductor”. Common Pitfalls: Students sometimes think that all materials simply become better conductors as they are cooled, forgetting the special phenomenon of superconductivity. Others may confuse semiconductors with metals and assume that any temperature-dependent behaviour must be semiconductor-like. To avoid such confusion, remember that some metals, including lead, exhibit a unique phase transition into a superconducting state at very low temperatures, characterised by zero resistance and perfect diamagnetism. Final Answer: At low temperature, lead behaves as a Super conductor.

Question 11

In polymer chemistry, which of the following substances is an example of a natural polymer rather than a fully synthetic man-made polymer?

Accepted Answer

Introduction / Context: Polymers are large molecules made up of repeating structural units called monomers. They can be classified into natural polymers, which occur in living organisms, and synthetic polymers, which are manufactured in chemical industries. Understanding this distinction helps in questions about materials used in daily life, such as plastics, fibres, and biomolecules. This question asks you to identify which listed substance is a natural polymer rather than a synthetic, man-made one. Given Data / Assumptions: The options are Bakelite, Nylon, Polythene, and Starch. Bakelite is a well known synthetic thermosetting plastic. Nylon and polythene are classic synthetic polymers. Starch is a carbohydrate found in plants. We assume the standard classification used in basic polymer chemistry. Concept / Approach: Natural polymers are produced by living organisms. Examples include proteins (polypeptides), nucleic acids (DNA, RNA), cellulose, and starch. These biopolymers are synthesised through biological processes such as photosynthesis and metabolism. Synthetic polymers, in contrast, are produced by controlled chemical polymerisation of monomers in industrial settings, often derived from petroleum. Bakelite is a phenol-formaldehyde resin, nylon is a polyamide made from diamines and diacids, and polythene (polyethylene) is formed from ethene monomers; all are synthetic. Starch, however, is a natural polysaccharide made of glucose units and serves as an energy storage material in plants, making it a natural polymer. Step-by-Step Solution: Step 1: Identify which substances are clearly synthetic plastics. Bakelite is a thermosetting plastic used in electrical fittings and handles. Nylon is a synthetic fibre used in textiles, ropes, and plastics. Polythene is a synthetic plastic used in bags, bottles, and containers. Step 2: Consider starch. Starch is a carbohydrate stored in plant tissues such as potatoes, rice, and wheat grains. Step 3: Recall that starch consists of many glucose units joined together, forming a long chain polymer. Step 4: Conclude that starch is the only natural polymer among the options. Verification / Alternative check: Biology and chemistry textbooks describe starch as a polysaccharide composed of alpha glucose units linked through glycosidic bonds, forming amylose and amylopectin chains. It is synthesised in plants by enzymes and is not produced in chemical factories. On the other hand, the manufacturing processes for Bakelite, nylon, and polythene are classic examples of synthetic polymerisation reactions taught in industrial chemistry chapters. These reactions use monomers derived from petrochemicals or simple organic reagents and are controlled in reactors, confirming their synthetic nature. This clear difference confirms that starch is the natural polymer in the list. Why Other Options Are Wrong (synthetic polymers): Option A (Bakelite): A synthetic thermosetting resin formed by condensation of phenol and formaldehyde; not natural. Option B (Nylon): A synthetic polyamide made by condensation polymerisation of diamines and dicarboxylic acids or related monomers. Option C (Polythene): A synthetic addition polymer formed from ethene monomers; a widely used plastic. Common Pitfalls: Students sometimes assume that anything used in everyday objects like food packaging or clothing must be synthetic, and they may forget that starch is a natural carbohydrate. Another confusion arises because the word “polymer” is often associated with plastics, leading to the wrong belief that only industrial materials are polymers. To avoid these mistakes, remember that many biological macromolecules, including starch, cellulose, proteins, and DNA, are natural polymers built from repeating monomer units. Final Answer: The natural polymer among the given options is Starch.

Question 12

Which one of the following nonmetals exhibits allotropy even in its liquid state, showing different liquid forms at different temperatures?

Accepted Answer

Introduction / Context: Allotropy is the phenomenon where an element exists in two or more different structural forms in the same physical state, such as solid carbon existing as diamond, graphite, and fullerene. While solid allotropy is widely discussed, some elements also show interesting behaviour in the liquid state. This question tests whether you know which nonmetal has distinct liquid forms, not just solid allotropes, making it a favourite conceptual point in basic inorganic chemistry. Given Data / Assumptions: The nonmetals listed are carbon, sulphur, phosphorous, and bromine. Allotropy refers to different forms of the same element in the same physical state. We are specifically asked about allotropy in the liquid state. We assume standard descriptions from school level inorganic chemistry regarding sulphur's unusual liquid behaviour. Concept / Approach: Carbon shows allotropy mainly in the solid state (diamond, graphite, amorphous carbon, fullerenes). Phosphorus also has several solid allotropes (white, red, black phosphorus). Bromine is a liquid at room temperature but does not exhibit commonly discussed liquid allotropy; it exists essentially as Br2 molecules. Sulphur, on the other hand, is famous for having multiple forms not only in the solid state (rhombic and monoclinic sulphur) but also in the liquid state. When sulphur is heated, its molecular structure changes: at lower temperatures it mainly contains S8 rings, but at higher temperatures, these rings break and form long chain polymers, leading to different liquid forms with changing viscosity and colour. This is often cited as an example of liquid allotropy. Step-by-Step Solution: Step 1: Recall solid allotropes for each element. Carbon has diamond and graphite; phosphorus has white and red forms; sulphur has rhombic and monoclinic forms. Step 2: Focus on the liquid state. Liquid bromine is simply Br2 molecules; no common liquid allotropes are discussed. Step 3: Examine sulphur's behaviour when heated. As sulphur melts and is further heated, its S8 rings open and form long-chain molecules, changing its viscosity and appearance, indicating different liquid forms. Step 4: Conclude that sulphur is the nonmetal that shows allotropy even in the liquid state. Verification / Alternative check: Textbooks often include a graph or discussion of the viscosity of liquid sulphur as a function of temperature. As temperature rises, the initially low-viscosity liquid becomes much more viscous due to the formation of long chain molecules, then thins again at higher temperatures when the chains break. This behaviour is tied to structural changes in the liquid and is treated as an example of allotropy beyond the solid state. Neither carbon nor phosphorus is normally studied in liquid form in school courses, and bromine is not said to have distinct liquid allotropes. This emphasis on sulphur's unusual liquid properties confirms that it is the correct choice. Why Other Options Are Wrong: Option A (Carbon): Carbon shows solid allotropy (diamond, graphite), but liquid allotropy is not a standard topic at this level. Option C (Phosphorous): Phosphorus has several solid allotropes; liquid allotropy is not commonly mentioned in basic courses. Option D (Bromine): Bromine is a liquid at room temperature but is essentially present as Br2 molecules without distinct liquid allotropes discussed in textbooks. Common Pitfalls: Students often think of carbon first because it is the most famous example of allotropy, but the question specifically asks about the liquid state. Another trap is selecting bromine simply because it is a liquid nonmetal at room temperature, without considering whether it actually has different liquid forms. To avoid such mistakes, read the question carefully and recall the unique case of sulphur, whose liquid state exhibits changing structures and viscosities, making it a textbook example of allotropy beyond solids. Final Answer: The nonmetal that shows allotropy in the liquid state is Sulphur.

Question 13

Which of the following commercially used fertilisers is not classified as a nitrogenous fertiliser, that is, it does not primarily supply nitrogen to plants?

Accepted Answer

Introduction / Context: Plant growth depends on the availability of essential nutrients, especially nitrogen, phosphorus, and potassium. Fertilisers are often classified according to which nutrient they mainly supply, such as nitrogenous, phosphatic, or potassic fertilisers. Understanding these categories helps in agriculture and environmental studies. This question asks you to identify which fertiliser in the list is not a nitrogenous fertiliser, meaning it does not primarily provide nitrogen to crops. Given Data / Assumptions: The fertilisers listed are ammonium sulphate, urea, ammonium nitrate, and superphosphate. Ammonium salts and urea are well known nitrogen sources. Superphosphate is known as a phosphatic fertiliser. We assume standard formulations used in agriculture. Concept / Approach: Nitrogenous fertilisers are those that mainly supply nitrogen, often in the form of ammonium ions, nitrate ions, or amide nitrogen from urea. Ammonium sulphate ((NH4)2SO4) contains ammonium nitrogen, ammonium nitrate (NH4NO3) contains both ammonium and nitrate nitrogen, and urea (CO(NH2)2) is a high nitrogen fertiliser. Single superphosphate, on the other hand, is primarily a phosphatic fertiliser, containing calcium dihydrogen phosphate and gypsum, and is used to supply phosphorus, not nitrogen. Therefore, among the options, superphosphate is not a nitrogenous fertiliser. Step-by-Step Solution: Step 1: Examine ammonium sulphate. Ammonium sulphate contains ammonium ions (NH4+), which provide nitrogen to plants, making it a nitrogenous fertiliser. Step 2: Examine urea. Urea is an organic compound with a very high nitrogen content and is widely used as a nitrogenous fertiliser. Step 3: Examine ammonium nitrate. Ammonium nitrate contains both ammonium and nitrate forms of nitrogen, so it clearly supplies nitrogen. Step 4: Examine superphosphate. Superphosphate is mainly calcium phosphate based and is used to supply phosphorus, not nitrogen, to the soil. Step 5: Conclude that superphosphate is not a nitrogenous fertiliser. Verification / Alternative check: Agricultural chemistry references classify fertilisers into categories such as nitrogenous (urea, ammonium sulphate, ammonium nitrate), phosphatic (single superphosphate, triple superphosphate), and potassic (muriate of potash). Superphosphate is always listed with phosphatic fertilisers and is recommended when soils lack phosphorus. Urea and ammonium based salts are listed under nitrogenous fertilisers and are applied when nitrogen deficiency is diagnosed. This consistent classification confirms that superphosphate is not nitrogenous. Why Other Options Are Wrong (i.e., they are nitrogenous): Option A (Ammonium sulphate): Contains ammonium nitrogen and is widely used as a nitrogen source. Option B (Urea): Has one of the highest nitrogen percentages by weight among solid fertilisers, making it a key nitrogenous fertiliser. Option C (Ammonium nitrate): Contains both NH4+ and NO3- nitrogen and is a classic nitrogenous fertiliser. Common Pitfalls: Students sometimes focus on the presence of “ammonium” or “nitrate” in the name and correctly identify those as nitrogenous, but then guess wrongly between urea and superphosphate. Another confusion arises from the spelling “superphospohate”, but despite minor spelling variations, the meaning remains the same: it is a phosphatic fertiliser. A useful memory aid is that any fertiliser name with “ammonium” or “nitrate” usually indicates nitrogen content, while “phosphate” points to phosphorus. Final Answer: The fertiliser that is not nitrogenous is Superphospohate, which is mainly phosphatic.

Question 14

Who is credited with formulating the modern periodic table in which the properties of elements show periodicity when arranged in order of increasing atomic mass (historically) and which later led to the modern atomic number based table?

Accepted Answer

Introduction / Context: The periodic table is one of the most important organising frameworks in chemistry, summarising the properties of all known elements in a single chart. Its development went through many stages, but one chemist is especially credited with formulating the early modern periodic table based on periodicity of properties. This question tests your knowledge of the history of chemistry and the scientist associated with the first widely accepted periodic table that successfully predicted new elements. Given Data / Assumptions: The question asks “Who invented the modern periodic table?” in the historical sense. The options are Faraday, Mendeleev, Newton, and Bohr. Mendeleev is well known for his 19th century periodic table based on atomic masses. We assume school level coverage of the history of the periodic law. Concept / Approach: Dmitri Ivanovich Mendeleev, a Russian chemist, published a periodic table in 1869 in which elements were arranged in order of increasing atomic mass, and he observed that chemical properties repeated periodically. He left gaps for undiscovered elements and predicted their properties with remarkable accuracy, which was later confirmed when elements like gallium and germanium were discovered. While later work by Moseley refined the basis of periodicity to atomic number, Mendeleev is still credited with inventing the modern form of the periodic table and the original periodic law. Faraday made major contributions to electrochemistry, Newton to classical mechanics, and Bohr to atomic structure, but none of them are primarily associated with inventing the periodic table. Step-by-Step Solution: Step 1: Recall which scientist is linked to the first successful periodic table. Mendeleev arranged elements by atomic mass and noticed periodicity in properties. Step 2: Remember his key achievement. He left gaps for unknown elements and predicted their properties, which were later verified. Step 3: Examine the other names. Faraday worked on electricity and electrolysis; Newton on gravity and motion; Bohr on atomic models and quantised orbits. Step 4: Conclude that Mendeleev is the scientist associated with the modern periodic table. Verification / Alternative check: Histories of chemistry universally credit Mendeleev with the first periodic table that became widely accepted among chemists. His periodic law stated that the properties of the elements are a periodic function of their atomic masses. Later, Moseley showed that atomic number is the true basis of periodicity, but the table's structure and logic are directly descended from Mendeleev's arrangement. Many modern periodic tables still mention Mendeleev by name, and some versions even include his portrait. This strong historical consensus confirms that Mendeleev is the correct answer. Why Other Options Are Wrong: Option A (Faraday): Famous for his work on electromagnetic induction and electrochemistry, not for inventing the periodic table. Option C (Newton): Known primarily for laws of motion and universal gravitation; he did not develop a periodic classification of elements. Option D (Bohr): Developed the Bohr model of the atom and contributed to quantum theory, but the periodic table predates his work. Common Pitfalls: Students sometimes confuse Bohr and Mendeleev because both names appear in chapters dealing with the structure of the atom and the arrangement of elements. Another mistake is to assume that whoever worked on atomic models must also have devised the periodic table. To avoid confusion, remember that Mendeleev's work came earlier and is focused on organising elements, while Bohr's work focuses on electron orbits and explaining spectral lines. Associating Mendeleev with “table” and Moseley with “atomic number” is a useful memory trick. Final Answer: The modern periodic table is historically credited to Mendeleev.

Question 15

The compound commonly used in prickly-heat powders to reduce irritation and help prevent excessive sweating is which of the following acids?

Accepted Answer

Introduction / Context: Prickly heat powders are applied to the skin in hot and humid climates to relieve heat rash, reduce irritation, and help control excessive sweating. These powders usually contain a base like talc along with mild antiseptic or astringent compounds. Understanding which chemical ingredients are used in common medicinal and cosmetic products is useful in applied chemistry and general awareness. This question asks you to identify which acid is commonly used in such powders to help prevent excessive sweating and irritation. Given Data / Assumptions: The product mentioned is prickly-heat powder. The role of the compound is to prevent excessive sweating and soothe the skin. The options given are boric acid, phosphoric acid, carbonic acid, and sulphonic acid. We assume typical formulations in which boric acid is used as a mild antiseptic and astringent. Concept / Approach: Boric acid (H3BO3) is a weak acid used in many topical preparations as a mild antiseptic and astringent. In prickly-heat powders, it helps reduce bacterial growth and has a soothing effect on irritated skin. Its mild astringent properties can also assist in reducing excessive sweating in affected areas. Phosphoric acid is stronger and mainly used in fertilisers and soft drinks; carbonic acid exists only weakly in carbonated beverages; sulphonic acids are strong organic acids used in detergents and industrial applications. These other acids are not typically associated with cosmetic or medicated powders meant for direct application on sensitive skin. Step-by-Step Solution: Step 1: Consider the requirements of a prickly-heat powder. It must be safe for direct application to skin, help reduce irritation, and mildly control sweating. Step 2: Evaluate boric acid. Boric acid is widely used as a mild antiseptic and astringent in topical preparations and powders. Step 3: Evaluate the other acids. Phosphoric acid is too strong and corrosive for direct skin application at effective concentrations. Carbonic acid is weak and unstable, mainly relevant in carbonated drinks, not powders. Sulphonic acids are strong organic acids used primarily in detergents; they are not suitable as soothing skin ingredients. Step 4: Conclude that boric acid is the compound used in prickly-heat powder. Verification / Alternative check: Labels and ingredient lists of traditional prickly-heat powders frequently show boric acid among the active or supporting ingredients, alongside talc, zinc oxide, and sometimes salicylic acid. Pharmacy textbooks describe boric acid as a mild antiseptic and astringent used in dusting powders and eye washes at low concentrations. In contrast, phosphoric and sulphonic acids are usually discussed in industrial or food chemistry contexts, not dermatology. This consistent use of boric acid in skin powders confirms it as the correct choice for this question. Why Other Options Are Wrong: Option B (Phosphoric acid): Primarily used in fertilisers and cola beverages; it is not a standard ingredient in prickly-heat powders. Option C (Carbonic acid): Exists transiently in carbonated water; it is not used in dry powders for skin application. Option D (Sulphonic acid): Strong organic acids derived from sulphuric acid, commonly used in detergents and surfactants, not as soothing skin agents. Common Pitfalls: Some students may be tempted to choose phosphoric acid because it sounds familiar or “pharma-like”, or they may confuse boric acid with borax or other boron compounds. To avoid errors, remember that boric acid is the one traditionally associated with mild antiseptic and astringent skin preparations, especially in dusting powders and eye washes. Its gentle nature at low concentrations makes it suitable for sensitive skin, unlike the stronger mineral or organic acids listed in the other options. Final Answer: The compound used in prickly-heat powders to help prevent excessive sweating is Boric acid.

Question 16

At ordinary conditions near room temperature, which of the following substances has the maximum density among the options given?

Accepted Answer

Introduction / Context: Density is defined as mass per unit volume and is a key physical property used to compare substances, predict floating or sinking behaviour, and design processes in chemistry and physics. Many exam questions test your understanding of relative densities of common substances such as water, ice, organic liquids, and gases. This question asks which of the listed substances has the maximum density under ordinary conditions, highlighting the unusual behaviour of water compared to its solid form and to other organic compounds. Given Data / Assumptions: The substances listed are water, ice, ethylene, and acetone. Water is liquid water near room temperature (or at its maximum density around 4 degrees Celsius). Ice is the solid form of water. Ethylene is a gas at room temperature. Acetone is an organic liquid commonly used as a solvent. We assume standard atmospheric pressure and typical laboratory conditions. Concept / Approach: Most substances become denser when they freeze, but water is anomalous: ice is less dense than liquid water, which is why ice floats. At around 4 degrees Celsius, water attains its maximum density, close to 1 g/cm^3. Common organic liquids such as acetone typically have densities lower than water, making them lighter and causing them to float or mix differently. Ethylene is a gas at room temperature and therefore has a very low density compared to liquids and solids. Among the given options, liquid water is therefore denser than ice, acetone, and gaseous ethylene under ordinary conditions. Step-by-Step Solution: Step 1: Compare water and ice. Ice floats on water, which means ice is less dense than liquid water; thus, water has higher density than ice. Step 2: Consider ethylene. Ethylene is a gas; gases generally have much lower densities than liquids and solids at the same temperature and pressure. Step 3: Consider acetone. Acetone is a volatile organic liquid with a density lower than that of water, so equal volumes of acetone weigh less than water. Step 4: Conclude that water, which is a dense liquid, has the maximum density among the options. Verification / Alternative check: Approximate numerical values support this conclusion. Liquid water at 4 degrees Celsius has a density close to 1 g/cm^3. Ice has a density around 0.9 g/cm^3, which is why it floats. Acetone has a density of less than 1 g/cm^3, often quoted around 0.79 g/cm^3, making it lighter than water. Ethylene, as a gas, has a density of only a few grams per litre, making it orders of magnitude less dense than any of the liquids or solids listed. These values confirm that water has the greatest density among water, ice, ethylene, and acetone under standard conditions. Why Other Options Are Wrong: Option B (Ice): Ice is less dense than water, which is why icebergs and ice cubes float on the liquid surface. Option C (Ethylene): Being a gas, ethylene has very low density compared to liquids and solids. Option D (Acetone): As a typical organic solvent, acetone is less dense than water and would not have the maximum density among the listed substances. Common Pitfalls: A common misconception is that solids are always denser than their corresponding liquids. While this is true for many substances, water is a famous exception due to hydrogen bonding and its open crystal structure in ice. Students may also focus on the word “ice” and assume it must be heavier without recalling that ice floats on water. Another error is ignoring the gaseous nature of ethylene and making a random guess. Remember that the anomaly of water (liquid denser than solid) is a favourite exam concept and helps you quickly identify water as having the maximum density among these options. Final Answer: Among the given substances, Water has the maximum density under ordinary conditions.

Question 17

When sodium bicarbonate (NaHCO3, commonly called baking soda) is heated strongly, which compound is formed as the main solid product of the thermal decomposition reaction?

Accepted Answer

Introduction / Context: Sodium bicarbonate, also known as baking soda, is a common household chemical used in cooking, cleaning, and fire extinguishers. When heated, it undergoes thermal decomposition, producing a different sodium compound, along with gas products. Understanding this reaction helps explain how baking soda works in baking and in extinguishing small fires, and it is a standard question in basic inorganic chemistry. Given Data / Assumptions: The reactant is sodium bicarbonate, NaHCO3. It is heated strongly, causing decomposition. The options include sodium carbonate, sodium hydroxide, sodium peroxide, and sodium monoxide. We assume no other reagents are present, only heat. Concept / Approach: When sodium bicarbonate is heated, it decomposes according to a well known reaction: 2NaHCO3 → Na2CO3 + CO2 + H2O Here, two moles of sodium bicarbonate yield one mole of sodium carbonate (Na2CO3) as the solid residue, with carbon dioxide and water vapour escaping as gases. Sodium hydroxide, sodium peroxide, and sodium monoxide are not formed in this simple thermal decomposition. Sodium carbonate is a common laboratory and industrial chemical known as washing soda (when hydrated), and it often appears as the product of heating sodium bicarbonate. Step-by-Step Solution: Step 1: Write the thermal decomposition equation for sodium bicarbonate. 2NaHCO3 (s) → Na2CO3 (s) + CO2 (g) + H2O (g) Step 2: Identify the solid product on the right side. The solid formed is sodium carbonate, Na2CO3. Step 3: Identify the gaseous products. Carbon dioxide (CO2) and water vapour (H2O) are released. Step 4: Match the solid product to the options and select “Sodium Carbonate”. Verification / Alternative check: In baking, the production of CO2 from sodium bicarbonate when heated or when reacting with acids causes dough to rise. The remaining sodium carbonate can impart a slightly alkaline taste if not balanced. In fire extinguishers, the same decomposition helps produce CO2 to smother flames. Chemistry textbooks and lab manuals consistently list sodium carbonate as the solid residue when sodium bicarbonate is strongly heated. There is no simple thermal route from NaHCO3 directly to sodium hydroxide, sodium peroxide, or sodium monoxide under these conditions, which confirms that sodium carbonate is the correct product. Why Other Options Are Wrong: Option B (Sodium Hydroxide): NaOH is not produced by simple heating of NaHCO3; it usually forms from reactions with water or other processes. Option C (Sodium Peroxide): Na2O2 is an oxidising agent produced by different chemical reactions, not by decomposing sodium bicarbonate. Option D (Sodium Monoxide): Na2O can form by burning sodium metal in oxygen, not by heating sodium bicarbonate. Common Pitfalls: Students sometimes confuse sodium bicarbonate (NaHCO3) with sodium carbonate (Na2CO3) and assume they are interchangeable, or they may think that sodium compounds always go towards sodium hydroxide when heated. Another mistake is not balancing the decomposition equation properly, which can obscure the identification of the correct product. To avoid such errors, memorise the key thermal decomposition: sodium bicarbonate yields sodium carbonate plus CO2 and H2O when heated strongly. Final Answer: When sodium bicarbonate is heated strongly, the main solid product formed is Sodium Carbonate (Na2CO3).

Question 18

Among the following forms of carbon and carbon-rich materials, which is considered the most pure form of elemental carbon?

Accepted Answer

Introduction / Context: Carbon occurs in nature in several allotropic forms and in many carbon-rich materials such as different types of coal and charcoal. The degree of purity of carbon in these forms varies widely, depending on the presence of other elements and the structure of the carbon itself. This question asks you to identify which of the listed substances is the most pure form of elemental carbon, highlighting the distinction between true allotropes and carbon-containing mixtures like coal. Given Data / Assumptions: The options are anthracite, lampblack, graphite, and wood charcoal. Anthracite is the highest grade of coal. Lampblack is a form of amorphous carbon obtained from incomplete combustion. Graphite is a crystalline allotrope of carbon. Wood charcoal is produced by heating wood in limited air and contains carbon plus some impurities. Concept / Approach: Anthracite is a very high carbon coal but still contains other substances such as moisture, volatile matter, and mineral impurities; it is not pure carbon. Wood charcoal is also mostly carbon but retains some inorganic ash and trapped gases. Lampblack is a fine form of amorphous carbon produced by incomplete combustion of hydrocarbons, yet it too can contain traces of hydrogen and other impurities. Graphite, on the other hand, is an allotrope of carbon in which atoms are arranged in layers of hexagonal lattices. As an allotrope, it is composed of carbon atoms only and is considered a pure form of carbon, like diamond. Therefore, among the options, graphite is the most pure form of elemental carbon. Step-by-Step Solution: Step 1: Consider anthracite. Anthracite has a high percentage of carbon compared to other coals but still contains noncarbon impurities and is not a pure element. Step 2: Consider lampblack. Lampblack is a soot-like amorphous carbon; although rich in carbon, it may contain hydrogen and other impurities. Step 3: Consider wood charcoal. Wood charcoal is obtained from wood and contains carbon plus ash and other inorganic residues. Step 4: Consider graphite. Graphite is a crystalline allotrope consisting of layers of pure carbon atoms arranged in hexagonal patterns. Step 5: Conclude that graphite, being an elemental allotrope, is the most pure form of carbon among the given choices. Verification / Alternative check: In discussions of carbon allotropes, both diamond and graphite are emphasised as pure forms of carbon with different structures and properties. Coal, charcoal, and lampblack are described as forms of amorphous carbon but also as mixtures with varying amounts of noncarbon materials. Analytical measurements show that even high grade anthracite may contain several percent of other substances, whereas ideal graphite is purely carbon. This distinction is reflected in exam oriented material that often asks which is the purest form of carbon; when diamond is not among the options, graphite is typically the correct one, especially when compared with coal or charcoal derivatives. Why Other Options Are Wrong: Option A (Anthracite): Although it is the purest variety of coal with high carbon content, it still contains noncarbon impurities and is not an elemental allotrope. Option B (Lampblack): Lampblack is largely carbon but is an amorphous product of incomplete combustion and may contain other elements. Option D (Wood Charcoal): Charcoal contains carbon plus ash and other residual components from the original wood. Common Pitfalls: Students sometimes confuse “purest form of coal” with “purest form of carbon”. Anthracite is indeed the purest coal but not the purest elemental carbon. Another confusion is treating all black, carbon-rich materials as equally pure carbon. To avoid these mistakes, remember that allotropes like diamond and graphite are structurally pure forms of the element, while coal and charcoal are natural mixtures with varying compositions. When diamond is missing from the options and graphite appears alongside coal-like materials, graphite is typically the correct answer. Final Answer: The most pure form of carbon among the given options is Graphite.

Question 19

The chemical reactions in which oxidation and reduction processes occur simultaneously within the same overall reaction are collectively called what?

Accepted Answer

Introduction / Context: In chemistry, many reactions involve the transfer of electrons between species. When one species loses electrons and another gains them in the same reaction, we say that oxidation and reduction occur together. Such reactions are extremely common in nature and industry, from respiration and combustion to metal extraction and corrosion. This question tests whether you know the standard term used to describe reactions in which oxidation and reduction happen simultaneously. Given Data / Assumptions: The question explicitly mentions reactions where oxidation and reduction both occur. The options include unusual names and one familiar term: feral reactions, redox reactions, demug reactions, and kerol reactions. We assume the standard IUPAC-consistent terminology used in textbooks. Oxidation is loss of electrons; reduction is gain of electrons. Concept / Approach: The word “redox” is a combination of “reduction” and “oxidation”. Any reaction in which one species is oxidised (loses electrons) while another is reduced (gains electrons) is called a redox reaction. A classic example is the reaction between zinc and copper sulphate, where zinc is oxidised to zinc ions and copper ions are reduced to metallic copper. Terms like “feral reactions”, “demug reactions”, and “kerol reactions” do not correspond to standard classifications in chemistry and appear to be distractors. Therefore, the correct technical term for such reactions is redox reactions. Step-by-Step Solution: Step 1: Recall the definitions. Oxidation involves loss of electrons, and reduction involves gain of electrons. Step 2: Understand that both processes must occur together. Electrons lost by one species must be gained by another in the same reaction, so oxidation and reduction are paired. Step 3: Identify the combined name. Reactions with simultaneous oxidation and reduction are called “redox” reactions. Step 4: Examine the options and select “Redox reactions” as the only meaningful chemical term. Verification / Alternative check: Textbooks covering electrochemistry, corrosion, and energy production repeatedly use the term redox reactions to refer to processes in which electrons are transferred. The word appears in topics such as redox titrations, redox couples, and redox potentials. In these reactions, half-reactions are written separately for oxidation and reduction, and then combined. No accepted term “feral reactions” or “demug reactions” appears in standard chemistry literature. This consistent usage confirms that the question is referring to redox reactions. Why Other Options Are Wrong: Option A (Feral reactions): This is not a recognised term in chemistry for any specific type of reaction. Option C (Demug reactions): This name has no standard meaning in chemical classification. Option D (Kerol reactions): Again, this is not a standard chemical term; it appears only as a distractor. Common Pitfalls: Because three of the options are unfamiliar, some students may think the question is testing knowledge of an obscure term and second-guess the familiar “redox reactions”. Another mistake is to associate redox only with specific topics like electrochemical cells and forget that the definition of redox applies broadly, including combustion, rusting, and metabolism. To avoid confusion, remember that any reaction involving electron transfer with simultaneous oxidation and reduction is, by definition, a redox reaction, regardless of the specific context. Final Answer: Reactions in which oxidation and reduction occur simultaneously are called Redox reactions.

Question 20

In human physiology and excretion, the chief nitrogenous waste product excreted by human beings through urine is which of the following substances?

Accepted Answer

Introduction / Context: The human body continuously breaks down proteins and amino acids, producing nitrogenous wastes that must be removed to maintain health. Different groups of animals excrete different primary nitrogenous wastes, such as ammonia, urea, or uric acid, depending on their habitat and evolutionary adaptations. Understanding which waste product is predominant in humans helps in physiology, medicine, and general science questions. This question asks you to identify the main nitrogenous waste excreted by human beings. Given Data / Assumptions: The focus is on nitrogenous waste in humans. The options are ammonia, urea, ammonium nitrate, and uric acid. We assume normal human physiology with functioning kidneys and urinary system. We are interested in the chief or primary nitrogenous waste product. Concept / Approach: Humans are classified as ureotelic organisms, meaning they primarily excrete nitrogenous wastes in the form of urea. Urea is synthesised in the liver via the urea cycle from ammonia generated during amino acid metabolism. It is then transported in the blood to the kidneys and excreted in urine. Ammonia is highly toxic and is converted into urea before excretion; uric acid is produced in smaller amounts from nucleic acid breakdown. Ammonium nitrate is a synthetic fertiliser, not a metabolic waste product. Therefore, the chief nitrogenous waste in human urine is urea. Step-by-Step Solution: Step 1: Recall the classification of animals based on nitrogenous excretion. Ammonotelic animals excrete ammonia, ureotelic excrete urea, and uricotelic excrete uric acid. Step 2: Identify the category for humans. Humans are ureotelic; they mainly excrete nitrogen in the form of urea. Step 3: Consider the metabolic pathway. Ammonia formed during protein breakdown is converted to urea in the liver via the urea cycle. Step 4: Recognise that urea is then excreted in urine by the kidneys. Step 5: Match this information with the options and select “Urea”. Verification / Alternative check: Clinical tests of kidney function routinely measure blood urea levels (blood urea nitrogen) and the amount of urea in urine, emphasising its role as the primary nitrogenous waste. While small amounts of ammonia and uric acid are also present, urea makes up the bulk of nitrogenous material removed from the body. Biology textbooks highlight that fishes are often ammonotelic, birds and many reptiles are uricotelic, and mammals, including humans, are ureotelic. This classification confirms that urea is the chief nitrogenous waste in humans. Why Other Options Are Wrong: Option A (Ammonia): Although ammonia is produced in metabolism, it is too toxic to be excreted directly in large amounts by humans and is converted to urea first. Option C (Ammonium Nitrate): This is an artificial compound used as a fertiliser and explosive; it is not a physiological waste product. Option D (Uric Acid): Humans do excrete some uric acid, especially from purine metabolism, but it is not the chief nitrogenous waste; excessive uric acid is associated with gout. Common Pitfalls: Students sometimes confuse human excretory products with those of birds or aquatic animals and may incorrectly select ammonia or uric acid. Another mistake is being misled by the chemical-sounding term “ammonium nitrate”, forgetting that it is not produced by the human body. To avoid these errors, remember the simple classification: humans and most mammals are ureotelic, meaning that urea is the primary nitrogenous waste excreted in urine. Final Answer: The chief nitrogenous waste excreted by human beings is Urea.

Chemistry Questions