Question 1

Which of the following statements about the charges and masses of subatomic particles is not true?

Accepted Answer

Introduction / Context: Basic knowledge of subatomic particles is essential for understanding atomic structure, chemical bonding, and many areas of physics. Protons, neutrons, and electrons differ in charge and mass, and exam questions often test your ability to recall these differences correctly. This question asks which of the given statements about subatomic particles is not true, meaning it contradicts the accepted model of the atom. Given Data / Assumptions: We consider three main subatomic particles: protons, neutrons, and electrons. Protons carry a positive charge, electrons carry a negative charge, and neutrons are neutral. Protons and neutrons have comparable masses, while electrons are much lighter. Concept / Approach: To solve this, recall the standard properties of subatomic particles. Protons have a charge of plus one in elementary charge units, electrons have minus one, and neutrons have zero charge. Protons and neutrons both reside in the nucleus and have similar masses, roughly 1 atomic mass unit, whereas electrons are about 1/1836 of this mass. The statement that is not true will contradict one of these well established facts, particularly regarding charge or mass relationships between particles. Step-by-Step Solution: Step 1: Examine option A: protons and neutrons have the same charge. Protons are positively charged and neutrons are neutral, so this statement is false. Step 2: Examine option B: protons and electrons have opposite charges. Protons are positive and electrons are negative, so this statement is true. Step 3: Examine option C: protons and neutrons have almost the same mass. Both have masses close to 1 atomic mass unit, so this statement is true. Step 4: Option D, all of the above, would imply that all listed statements are true, which is not correct because option A is false. Step 5: Conclude that the statement that is not true is option A. Verification / Alternative check: You can verify by recalling the symbols and charges: proton is written as p plus, neutron as n with zero charge, and electron as e minus. Textbooks and reference tables consistently show that neutrons do not carry electric charge. This directly contradicts the idea that protons and neutrons have the same charge. At the same time, standard references confirm that protons and neutrons have nearly equal masses, and that protons and electrons carry equal but opposite charges, confirming that options B and C are correct statements. Why Other Options Are Wrong: Option B is accurate because the positive charge of a proton balances the negative charge of an electron in neutral atoms. Option C is accurate because proton and neutron masses are both close to 1 atomic mass unit and are very similar. Option D is wrong because it groups together one false statement with true ones and labels all of them as true. The only statement that is actually not true is option A, which incorrectly describes the charges of protons and neutrons. Common Pitfalls: A common mistake is to confuse neutrality with having the same charge as another particle. Some students wrongly think that if a neutron has no charge, it can be grouped with positively charged protons as similar. Another pitfall is to assume that all nuclei particles must have the same properties in terms of charge, which is incorrect. Keeping a clear mental table of the charges and relative masses of protons, neutrons, and electrons helps avoid these errors in exam questions. Final Answer: The statement that is not true is protons and neutrons have the same charge.

Question 2

Which of the following statements correctly describes an important physical property of liquid water?

Accepted Answer

Introduction / Context: Water is a unique substance with several unusual physical properties that are very important for life and the environment. Its density behavior, specific heat capacity, and heat of vaporization influence climate, weather, and biological systems. This question asks you to identify which statement correctly describes a key physical property of liquid water, focusing especially on its capacity to absorb heat and its behavior during phase changes. Given Data / Assumptions: The options refer to density, specific heat capacity, and heat of vaporization of water. We consider water under normal conditions, near room temperature and atmospheric pressure. We compare water to many other common liquids and substances. Concept / Approach: Water is known to have a relatively high density compared to many liquids, except for the special case of ice being less dense than liquid water. It also has a high specific heat capacity, meaning it can absorb a large amount of heat energy for a small rise in temperature. Additionally, water has a high heat of vaporization, so it requires a large amount of energy to convert it from liquid to gas. The correct statement must reflect these high values, not low ones, for specific heat and heat of vaporization. Step-by-Step Solution: Step 1: Examine option A, which claims that water has low density compared to most liquids. This is not correct because liquid water is fairly dense and even denser than ice. Step 2: Examine option B, which claims that water has low specific heat capacity. This conflicts with the known fact that water has a high specific heat capacity. Step 3: Examine option C, which claims that water has low heat of vaporization. This is also incorrect because water requires a lot of energy to vaporize. Step 4: Examine option D, which states that water has high specific heat capacity and high heat of vaporization, matching the known physical properties. Step 5: Select option D as the correct statement about the physical properties of water. Verification / Alternative check: Consider practical observations. Large bodies of water like seas and lakes heat up and cool down slowly, which is a direct consequence of high specific heat capacity. Sweating is effective at cooling the body because water on the skin absorbs a large amount of energy as it evaporates, reflecting a high heat of vaporization. Both phenomena confirm that water does not have low specific heat and low heat of vaporization. Instead, it has high values for both, supporting option D. Why Other Options Are Wrong: Option A is incorrect because water does not generally have low density; in fact, the density of liquid water near 4 degrees Celsius is relatively high, and ice floats because it is less dense than liquid water. Option B is wrong since water has one of the highest specific heat capacities among common substances, not a low one. Option C is wrong because water requires substantial energy to change from liquid to gas, indicating a high, not low, heat of vaporization. These incorrect options reverse or misstate well known properties of water. Common Pitfalls: Students sometimes confuse the terms high and low when describing physical properties and may not recall the correct direction of these comparisons. Another pitfall is mixing up the special density behavior of ice with general statements about the density of liquid water. To avoid these mistakes, remember that water is special because it can absorb or release large amounts of energy with relatively small temperature changes and because evaporation absorbs a lot of heat. These facts are captured by high specific heat capacity and high heat of vaporization. Final Answer: The correct statement about liquid water is that it has high specific heat capacity and high heat of vaporization.

Question 3

In chemical bonding, covalent bonds are formed between atoms when electrons are mainly involved in which of the following processes?

Accepted Answer

Introduction / Context: Chemical bonds hold atoms together in molecules and compounds, and understanding different types of bonding is fundamental to chemistry. Covalent bonds are one of the main types, especially important in organic molecules and many nonmetal compounds. This question tests whether you know that covalent bonds involve the sharing, not the transfer, of electrons between atoms. Given Data / Assumptions: The focus is on covalent bonds, not ionic or metallic bonds. The options mention transfer, sharing, and other processes involving electrons. We consider simple diatomic molecules like H2 or Cl2 as basic examples of covalent bonding. Concept / Approach: In a covalent bond, two atoms share one or more pairs of valence electrons so that each atom can achieve a more stable electron configuration, often similar to noble gases. This is different from ionic bonding, where electrons are transferred completely from one atom to another, producing ions that attract electrostatically. Therefore, the correct description for covalent bonding must emphasize sharing of electrons between atoms, not transfer or separation into non interacting parts. Step-by-Step Solution: Step 1: Recall that covalent bonds typically form between nonmetal atoms with similar electronegativity values. Step 2: Understand that in these cases, neither atom completely donates or accepts electrons; instead, they share electron pairs. Step 3: Examine option A, which describes transfer of electrons; this fits ionic bonding, not covalent bonding. Step 4: Examine option B, which describes sharing of electrons between atoms; this matches the definition of covalent bonding. Step 5: Examine option C, which mentions dividing electrons into parts that do not interact, a description that does not apply to any standard bond type. Step 6: Conclude that option B is the only one that correctly describes covalent bond formation. Verification / Alternative check: Take the example of a hydrogen molecule, H2. Each hydrogen atom has one electron, and in the H2 molecule, they share a pair of electrons, allowing each to feel as if it has a duplet like helium. If electrons were transferred, one atom would lose an electron and become H plus while the other would gain and become H minus, resulting in ionic bonding, which is not what we see in H2 gas. Similar analysis of chlorine molecules and water molecules confirms that sharing of electrons is the key characteristic of covalent bonding. Why Other Options Are Wrong: Option A describes transfer of electrons, which is typical of ionic bonds, not covalent bonds. Option C mentions dividing electrons into separate parts that do not interact, which does not correspond to real chemical bonding, where electrons are shared or transferred in a way that binds atoms. Option D, all of the above, cannot be correct because options A and C are incorrect descriptions for covalent bond formation. Only option B accurately expresses the fundamental idea of electron sharing. Common Pitfalls: Students sometimes confuse ionic and covalent bonds because both involve valence electrons and can result in stable configurations. Another pitfall is to oversimplify covalent bonding as just one type, forgetting that there are single, double, and triple covalent bonds, all based on shared electron pairs. Remember that the key difference is that covalent bonding involves sharing electrons between atoms, whereas ionic bonding involves complete electron transfer followed by electrostatic attraction between ions. Final Answer: Covalent bonds are formed when there is sharing of electrons between atoms.

Question 4

In terms of molecular shape and bond polarity, is sulfur dioxide, SO2, a polar or a nonpolar molecule?

Accepted Answer

Introduction / Context: Molecular polarity depends on both the polarity of individual bonds and the overall geometry of the molecule. Sulfur dioxide, SO2, is a common atmospheric gas and a good example of how shape and bond polarity combine to produce a polar molecule. This question asks whether SO2 is polar or nonpolar and requires you to think about electronegativity differences and molecular shape together. Given Data / Assumptions: Molecule: sulfur dioxide, formula SO2. Central atom: sulfur, surrounding atoms: two oxygen atoms. We consider the usual Lewis structure and VSEPR based geometry. Oxygen is more electronegative than sulfur. Concept / Approach: A bond is polar when there is a difference in electronegativity between the bonded atoms, causing partial charges. In SO2, sulfur and oxygen differ in electronegativity, so each S O bond is polar. However, to decide if the whole molecule is polar, we must consider the shape. SO2 is not linear; it has a bent or V shaped geometry due to lone pairs on the sulfur atom. In a bent molecule with polar bonds, the bond dipoles do not cancel and produce a net dipole moment, making the molecule polar. Step-by-Step Solution: Step 1: Determine whether S O bonds are polar. Oxygen is more electronegative than sulfur, so each S O bond is polar with electron density shifted toward oxygen. Step 2: Draw the Lewis structure of SO2 and count electron domains around sulfur, including lone pairs. Step 3: Apply VSEPR theory; with lone pairs on sulfur and two bonding pairs, the molecular geometry is bent, not linear. Step 4: Represent bond dipoles as arrows from sulfur toward oxygen for each S O bond. Step 5: In a bent arrangement, these dipoles do not cancel; their vector sum is nonzero, leading to a net molecular dipole. Step 6: Conclude that SO2 has polar bonds and an overall polar molecule. Verification / Alternative check: You can compare SO2 with CO2. Carbon dioxide is linear with two polar C O bonds that point in exactly opposite directions, causing their dipoles to cancel and giving a nonpolar molecule. In contrast, SO2 has a non linear, bent shape due to lone pairs on sulfur, so the dipoles do not oppose each other directly. Experimental data and reference tables list a nonzero dipole moment for SO2, confirming its polar nature, which matches the prediction from VSEPR theory. Why Other Options Are Wrong: Option A claims SO2 has nonpolar bonds and is linear, which is incorrect because S O bonds are polar and the geometry is bent. Option B claims the bonds are polar but the molecule is nonpolar, which would describe a symmetrical arrangement such as CO2, not SO2. Option D claims the bonds are nonpolar but the molecule is polar, which is not consistent, because nonpolar bonds alone cannot create a polar molecule in this context. Only option C correctly describes both the bond polarity and the bent shape leading to a polar molecule. Common Pitfalls: Students sometimes memorize that "dioxide" molecules like CO2 are linear and then wrongly assume the same shape for SO2. Another pitfall is to consider only electronegativity differences and forget to check molecular geometry, leading to confusion between polar bonds and polar molecules. Always remember that geometry and symmetry determine whether bond dipoles cancel. For molecules like SO2 with bent shapes and polar bonds, the result is a net molecular dipole and a polar molecule. Final Answer: Sulfur dioxide, SO2, has polar S O bonds and, because of its bent shape, is an overall polar molecule.

Question 5

Bleaching powder is added to drinking water mainly for which purpose in water treatment?

Accepted Answer

Introduction / Context: Safe drinking water is essential for public health, and various chemicals are used in water treatment to remove contaminants and kill harmful organisms. Bleaching powder, which contains calcium hypochlorite, is one such chemical often used in controlled amounts. This question asks you to identify the main purpose for adding bleaching powder to drinking water, focusing on its role in disinfection. Given Data / Assumptions: Chemical considered: bleaching powder, usually calcium hypochlorite. Application: addition to drinking water. Options include disinfectant, antibiotic, coagulant, and antiseptic roles. Concept / Approach: Bleaching powder releases chlorine when added to water. Chlorine is a strong oxidizing agent that can kill bacteria, viruses, and other microorganisms present in water. In water treatment, chemicals that kill or inactivate disease causing microbes are called disinfectants. Antibiotics and antiseptics are related to medicine and topical applications, not directly to water treatment, and coagulants are used for particle removal, not primarily for killing germs. Therefore, the correct purpose is disinfection. Step-by-Step Solution: Step 1: Recall that bleaching powder is used to chlorinate water by releasing chlorine or hypochlorite ions. Step 2: Understand that chlorine reacts with and destroys many harmful microorganisms, making water safer to drink. Step 3: Recognize that a chemical that kills microbes in water is acting as a disinfectant. Step 4: Compare this with the meanings of antibiotic, coagulant, and antiseptic and see that these terms do not primarily describe water disinfection. Step 5: Select disinfectant as the main purpose of adding bleaching powder to drinking water. Verification / Alternative check: Water supply agencies commonly monitor residual chlorine levels after bleaching powder or other chlorination methods to ensure that disinfection has been effective. This practice would not make sense if bleaching powder were mainly used as an antibiotic or coagulant. Textbooks and public health guidelines consistently describe bleaching powder as a disinfecting agent for water. These references confirm that its main role is to kill or inactivate microorganisms, not to treat human infections directly or to serve as a coagulant. Why Other Options Are Wrong: Option B, antibiotic, refers to drugs used inside the body to treat bacterial infections, which is different from disinfecting water. Option C, coagulant, describes substances like alum that cause suspended particles to clump together and settle, a different step in water treatment. Option D, antiseptic, refers to agents applied to skin or living tissue to prevent infection, not primarily to treat large volumes of drinking water. None of these options matches the main role of bleaching powder in water treatment. Common Pitfalls: Students sometimes confuse terms like disinfectant, antiseptic, and antibiotic because all are related to controlling germs. Another pitfall is to associate bleaching powder only with whitening clothes and forget its role in water chlorination. To avoid these errors, remember that disinfectants are used on non living surfaces or in water, antiseptics are used on living tissues, and antibiotics are medicines taken into the body. Bleaching powder in water is clearly used as a disinfectant. Final Answer: Bleaching powder is added to drinking water mainly as a disinfectant, to kill disease causing microorganisms.

Question 6

In the formation of an ionic bond between a metal and a nonmetal, what happens to the valence electrons?

Accepted Answer

Introduction / Context: Ionic bonding is a fundamental concept in chemistry that explains how many salts and simple inorganic compounds form. It involves interactions between metals and nonmetals and the behavior of their valence electrons. This question focuses on what happens to valence electrons during the formation of an ionic bond and helps distinguish ionic bonding from covalent bonding, where electrons are shared rather than transferred. Given Data / Assumptions: We consider a typical ionic bond between a metal atom and a nonmetal atom. The question asks about the fate of valence electrons, not core electrons. Options mention collisions, sharing, and transfer of electrons. Concept / Approach: In ionic bonding, metal atoms tend to lose one or more valence electrons to achieve a stable noble gas configuration, forming positively charged cations. Nonmetal atoms gain valence electrons to complete their valence shell and form negatively charged anions. The electrostatic attraction between these oppositely charged ions constitutes the ionic bond. Therefore, the key idea is the transfer, not sharing or simple collision, of valence electrons from the metal to the nonmetal. Step-by-Step Solution: Step 1: Recall that metals generally have low ionization energies and can lose valence electrons easily. Step 2: Recall that nonmetals have high electronegativities and tend to gain electrons to fill their valence shells. Step 3: When an ionic compound forms, such as NaCl, the sodium atom transfers one valence electron to the chlorine atom. Step 4: This transfer produces Na plus and Cl minus ions, which attract each other through electrostatic forces. Step 5: Compare this description with the options and select the one that mentions electrons being transferred and ions being formed. Verification / Alternative check: You can verify this by examining electron configurations. Sodium in the ground state has one valence electron in its outer shell, and chlorine needs one electron to complete its valence shell. After sodium transfers its electron to chlorine, sodium achieves a stable configuration similar to neon, and chlorine achieves a configuration similar to argon. The result is a stable ionic pair. This pattern is repeated in many ionic compounds, confirming that transfer of valence electrons and formation of ions is the defining feature of ionic bonding. Why Other Options Are Wrong: Option A suggests that electrons only collide and produce heat without actually transferring, which does not describe bond formation accurately. Option B talks about equal sharing of valence electrons, which is characteristic of covalent bonds, not ionic bonds. Option C combines collision and sharing, which again does not match the definition of ionic bonding. Only option D correctly states that valence electrons are transferred from one atom to another, leading to oppositely charged ions that attract each other. Common Pitfalls: Students sometimes confuse ionic and covalent bonds because both involve valence electrons and can produce stable structures. Another pitfall is to think of electrons as colliding rather than being transferred in a controlled way driven by differences in ionization energy and electron affinity. To avoid these mistakes, remember that ionic bonding always involves transfer of electrons and formation of ions, while covalent bonding involves sharing of electron pairs between atoms. Final Answer: In an ionic bond, valence electrons are transferred from one atom to another, forming oppositely charged ions that attract each other.

Question 7

An ionic bond between two atoms is formed when which of the following processes occurs?

Accepted Answer

Introduction / Context: Ionic bonds are one of the basic types of chemical bonds that hold atoms together in compounds such as salts. Understanding how these bonds form is crucial for predicting properties like melting point, solubility, and electrical conductivity. This question asks you to choose the best description of the process that leads to the formation of an ionic bond between two atoms. Given Data / Assumptions: We are dealing with two atoms, typically one metal and one nonmetal. The options describe sharing, transfer of electrons, combined processes, and losing of protons. We assume normal conditions and typical ionic compounds like NaCl or MgO as examples. Concept / Approach: An ionic bond forms when electrons are transferred from one atom, usually a metal, to another atom, usually a nonmetal. The metal atom loses electrons and becomes a positively charged cation, while the nonmetal atom gains electrons and becomes a negatively charged anion. The electrostatic attraction between these oppositely charged ions constitutes the ionic bond. Therefore, the correct description must emphasize electron transfer and the formation of ions that attract each other, not sharing of electrons or changes in protons. Step-by-Step Solution: Step 1: Recall that metals have a tendency to lose valence electrons, forming positive ions. Step 2: Recall that nonmetals tend to gain electrons to complete their valence shells, forming negative ions. Step 3: Consider a typical example, such as sodium and chlorine forming NaCl. Sodium transfers one valence electron to chlorine. Step 4: After transfer, Na becomes Na plus and Cl becomes Cl minus, and a strong electrostatic attraction arises between them. Step 5: Identify the option that explicitly describes this process of electron transfer and ion formation leading to ionic bonding. Verification / Alternative check: Electron configuration provides an alternative check. For sodium, losing one electron gives a stable noble gas configuration, and for chlorine, gaining one electron also results in a stable configuration. The formation of Na plus and Cl minus ions thus lowers the energy of the system and creates a stable ionic lattice. In contrast, sharing electrons as in covalent bonding leads to different structures and properties. This reasoning confirms that electron transfer and ionic attraction are central to ionic bond formation. Why Other Options Are Wrong: Option A, sharing of electrons, describes covalent bonding rather than ionic bonding. Option C, both sharing and transfer at the same time, mixes concepts and does not correspond to a standard bond type in simple compounds. Option D, losing of protons from the nucleus, would change the element itself and is not how chemical bonds form, since proton number defines the element. Only option B correctly captures the essence of ionic bond formation: transfer of electrons from a metal atom to a nonmetal atom and the resulting electrostatic attraction between ions. Common Pitfalls: Students may confuse the terms because ionic and covalent bonds both lead to stable compounds and involve valence electrons. Another pitfall is overlooking the role of charge attraction and focusing only on electron movement without connecting it to the formation of ions. To avoid these errors, remember that ionic bonds are always associated with electron transfer and ion formation, while covalent bonds are associated with electron sharing between atoms. Keeping these definitions clear makes questions about bond types much easier to answer. Final Answer: An ionic bond is formed when there is transfer of electrons from a metal atom to a nonmetal atom, producing oppositely charged ions that attract each other.

Question 8

In basic chemistry, which of the following reactions are correctly classified as exothermic processes, that is, reactions that release heat energy to the surroundings?

Accepted Answer

Introduction / Context: Exothermic reactions are chemical changes in which energy is released to the surroundings, usually in the form of heat or sometimes light. In introductory chemistry, students often see examples such as combustion, formation of ionic compounds from metals and nonmetals, and hydration of certain salts. This question asks you to judge whether three specific reactions are exothermic and to recognise that more than one of them can release heat. Understanding which typical textbook reactions are exothermic helps in predicting temperature changes during experiments and in everyday processes such as burning fuels or setting plaster. Given Data / Assumptions: Reaction 1: C + O2 → CO2 Reaction 2: 2Mg + O2 → 2MgO Reaction 3: CuSO4 + 5H2O → CuSO4·5H2O All reactions are considered under normal laboratory conditions. Exothermic means overall release of heat to the surroundings. Concept / Approach: The concept is that exothermic reactions have a negative enthalpy change because products have lower chemical energy than reactants. Combustion of elements like carbon and magnesium are classic exothermic processes. Hydration of anhydrous copper sulfate to the blue pentahydrate is also exothermic, which is why the solid heats up when water is added. The approach is to recall standard examples of exothermic reactions from basic chemistry and match them to the listed reactions, rather than trying to calculate enthalpy values numerically. Step-by-Step Solution: Step 1: Consider reaction 1, C + O2 → CO2. Combustion of carbon in oxygen to form carbon dioxide is a classic exothermic reaction; it releases heat and sometimes visible light as a flame. Step 2: Consider reaction 2, 2Mg + O2 → 2MgO. Burning magnesium ribbon in air produces a bright white flame and releases a lot of heat, again making this a clear exothermic reaction. Step 3: Consider reaction 3, CuSO4 + 5H2O → CuSO4·5H2O. When water is added to white anhydrous copper sulfate, it becomes blue hydrated copper sulfate and the process releases heat, so this hydration is also exothermic. Step 4: Since all three reactions individually are exothermic, the correct classification is that reactions 1, 2 and 3 are all exothermic. Verification / Alternative check: Another way to check is from experimental observations. When carbon or magnesium burn, the surroundings definitely become hotter, which is a direct sign of heat release. With anhydrous copper sulfate, a noticeable temperature rise is felt if you carefully touch the container after adding water. Many data tables in chemistry textbooks and handbooks also list negative enthalpy changes for combustion reactions and hydration of copper sulfate, confirming their exothermic nature. These independent references support the conclusion that each of the three reactions releases heat overall. Why Other Options Are Wrong: Option A is wrong because it ignores the obviously exothermic combustion of magnesium and the exothermic hydration of copper sulfate. Option B fails to recognise that reaction 3 is also exothermic. Option C incorrectly leaves out reaction 1, which is one of the most famous exothermic processes. Option D wrongly suggests that only two of the three are exothermic. Only option E correctly states that all three listed reactions are exothermic. Common Pitfalls: A common mistake is to assume that only burning reactions are exothermic and to forget that hydration or neutralisation processes can also release heat. Some learners also think that any reaction involving water must be endothermic, which is not always true. It is important to rely on known examples and experimental evidence rather than guessing from appearance alone. Another pitfall is confusing exothermic with fast or dramatic reactions, but some exothermic changes can be slow or gentle while still releasing heat overall. Final Answer: The correct choice is All three reactions 1, 2 and 3 are exothermic because each one releases heat to the surroundings when it occurs under normal conditions.

Question 9

In chemical bonding and molecular polarity, is silicon tetrachloride (SiCl4) a polar or a nonpolar molecule, and what feature of its structure explains this behaviour?

Accepted Answer

Introduction / Context: Understanding whether a molecule is polar or nonpolar is a key part of chemical bonding and molecular structure. Polarity affects boiling point, solubility, and many physical properties. Silicon tetrachloride, SiCl4, is a common example used in textbooks to show how a molecule can contain polar bonds but still be nonpolar overall. This question asks you to identify whether SiCl4 is polar or nonpolar and to connect that to its geometry and bond dipoles. Given Data / Assumptions: Molecule: silicon tetrachloride, formula SiCl4. Central atom: silicon, surrounded by four chlorine atoms. Each Si–Cl bond is a covalent bond with some polarity due to electronegativity difference. The molecular shape is known from valence shell electron pair repulsion theory. Concept / Approach: The approach is to combine two ideas. First, each Si–Cl bond is polar because chlorine is more electronegative than silicon, so electrons are drawn toward the chlorine atom. Second, the overall molecular geometry determines whether these individual bond dipoles cancel or reinforce each other. According to valence shell electron pair repulsion ideas, a molecule with four bonding pairs and no lone pairs on the central atom adopts a tetrahedral geometry. In a perfect tetrahedron with identical outer atoms, the bond dipoles are symmetrically arranged and cancel out, giving a nonpolar molecule even though each bond is polar. Step-by-Step Solution: Step 1: Determine the electron pair arrangement around silicon. Silicon in SiCl4 forms four single covalent bonds and has no lone pairs on the central atom. Step 2: Use valence shell electron pair repulsion rules: four bonding pairs and no lone pairs lead to a tetrahedral molecular geometry. Step 3: Recognise that each Si–Cl bond is polar because chlorine attracts bonding electrons more strongly than silicon, giving a partial negative charge near each chlorine. Step 4: In a regular tetrahedral arrangement with four identical polar bonds, the bond dipole vectors are oriented symmetrically and cancel each other, resulting in no net dipole moment for the whole molecule. Step 5: Therefore, SiCl4 is classified as a nonpolar molecule, even though the individual bonds are polar. Verification / Alternative check: Another way to verify this conclusion is to recall similar molecules such as carbon tetrachloride, CCl4, which is also nonpolar for the same geometric reason. Experimental measurements of dipole moment for SiCl4 show a value close to zero, supporting the nonpolar classification. In addition, the solubility behaviour is typical of nonpolar molecules; SiCl4 is more soluble in nonpolar organic solvents than in water, which is consistent with an overall nonpolar character. Why Other Options Are Wrong: Option A is wrong because although Si–Cl bonds are polar, the shape is not asymmetric; it is symmetric tetrahedral, so the dipoles cancel. Option C is incorrect since SiCl4 is not an ionic salt; it is a covalent molecular compound. Option D claims the molecule is linear, which contradicts the known tetrahedral shape. Option E is wrong because it states that the bonds are nonpolar; the bonds themselves are polar, but the net molecule is nonpolar due to symmetry. Only option B correctly explains that SiCl4 is nonpolar because of cancellation of bond dipoles in a tetrahedral geometry. Common Pitfalls: A frequent mistake is to assume that if all bonds in a molecule are polar, then the molecule must automatically be polar. Another pitfall is to ignore the molecular shape and focus only on electronegativity differences. Some learners also misremember the geometry and think SiCl4 is planar or linear rather than tetrahedral. Always determine the shape first, then combine bond polarity with symmetry to decide overall polarity. For symmetrical molecules with identical outer atoms, bond dipoles often cancel. Final Answer: The correct description is that SiCl4 is a nonpolar molecule because the polar Si–Cl bonds cancel in a tetrahedral shape and the net dipole moment is essentially zero.

Question 10

In basic thermochemistry, which of the following common processes are correctly classified as endothermic, meaning that they absorb heat energy from the surroundings?

Accepted Answer

Introduction / Context: In thermochemistry, processes are called endothermic when they absorb heat from the surroundings. This absorption often causes a temperature decrease in the nearby environment unless heat is supplied from outside. Many everyday changes, including phase changes and biological processes, can be endothermic. This question asks you to recognise which listed processes are endothermic and to distinguish them from exothermic examples like combustion. Knowing these differences helps in understanding energy flow in physical changes, solution formation and life processes. Given Data / Assumptions: Process A: Melting of ice at its melting point. Process B: Dissolving potassium chloride (KCl) in water. Process C: Photosynthesis in green plants using light energy. Process D: Combustion of methane gas in air. Endothermic means net absorption of heat energy by the system. Concept / Approach: The key concept is that endothermic processes have a positive enthalpy change, because energy must be supplied to break bonds or increase molecular separation. Melting requires energy to overcome forces in a solid lattice. Dissolving certain salts like KCl also requires more energy to pull ions apart than is released when ions interact with water molecules, so the solution cools. Photosynthesis is a strongly endothermic process that uses light energy to convert carbon dioxide and water into glucose and oxygen. Combustion, however, is a classic exothermic process that releases heat and light. Step-by-Step Solution: Step 1: For melting of ice, heat is absorbed from the environment to convert solid water into liquid water at the same temperature, so this is endothermic. Step 2: When potassium chloride dissolves in water, the solution typically becomes colder because the energy required to separate ions in the crystal is greater than the energy released during hydration, so this is also endothermic. Step 3: Photosynthesis in plants uses light energy to convert low energy molecules (CO2 and H2O) into higher energy glucose; this is clearly an energy absorbing, endothermic process. Step 4: Combustion of methane is known to release heat and light, so it is exothermic and not part of the endothermic group. Step 5: Therefore processes A, B and C are all endothermic, which matches option E that groups them together. Verification / Alternative check: You can verify the classification by thinking about observed temperature changes. Ice melts when heat is supplied, and if you hold ice in your hand it feels cold because it is taking heat from your skin. When solid KCl dissolves in water, the beaker feels cooler, indicating heat absorption. Photosynthesis obviously needs continual input of solar energy for the reaction to proceed. In contrast, a burning methane flame can be used to heat water because it releases heat. These observations reinforce the conclusion that the first three processes are endothermic. Why Other Options Are Wrong: Option A includes only one endothermic process and ignores the other two. Option B focuses on just one process and is incomplete. Option C mentions only photosynthesis, again missing the other endothermic examples. Option D confuses things by bringing in combustion, which is exothermic. Only option E clearly states that all of the processes in options A, B and C are endothermic, which matches the correct thermochemical classification. Common Pitfalls: Students sometimes think that only chemical reactions can be endothermic or exothermic and forget that phase changes like melting and boiling also involve heat flow. Another common error is to assume that all dissolving processes are exothermic because some salts warm the solution, but the direction of heat flow depends on the balance of lattice and hydration energies. In biological contexts, learners may overlook that building complex molecules like glucose from simple ones usually requires an input of energy. Always relate the concept back to whether the surroundings gain heat or lose heat overall. Final Answer: The correct choice is All of the processes in options A, B and C are endothermic, because melting of ice, dissolving potassium chloride and photosynthesis all absorb heat energy from their surroundings.

Question 11

In human physiology, which of the following is a major function of the chloride ion (Cl⁻) in body fluids and digestive secretions?

Accepted Answer

Introduction / Context: Electrolytes such as sodium, potassium and chloride are essential ions in human physiology. Chloride ions, written as Cl⁻, are particularly important in maintaining fluid balance, electrical neutrality and digestive function. This question focuses on a key role of chloride in the stomach. Recognising specific functions of major ions is useful for students of biology, nursing, and medicine, because disturbances in electrolyte levels can lead to serious clinical problems. Given Data / Assumptions: The question mentions the chloride ion as an electrolyte. We are asked to identify a major function rather than a minor or rare one. Possible roles include gastric acidity, intracellular dominance, and no role in fluid balance. Normal human physiology is assumed, without disease states. Concept / Approach: Chloride is the major extracellular anion in the body. Together with sodium, it helps maintain osmotic pressure and electrical neutrality in extracellular fluid. In the stomach, chloride combines with hydrogen ions secreted by parietal cells to form hydrochloric acid, HCl. Gastric acid is crucial for protein digestion and for killing ingested microbes. The approach is to recall this well known role and then eliminate options that incorrectly label chloride as a principal intracellular ion or as having no role in fluid balance. Step-by-Step Solution: Step 1: Recall that parietal cells in the stomach secrete hydrogen ions and chloride ions into the gastric lumen, which combine to form hydrochloric acid. Step 2: Hydrochloric acid maintains a very low pH in the stomach, which helps denature dietary proteins and activates digestive enzymes like pepsin. Step 3: Therefore chloride clearly plays a major role in maintaining gastric acidity, matching option A. Step 4: Chloride is not the principal intracellular cation; that role belongs mainly to potassium. Nor is it the principal intracellular anion, which is largely contributed by phosphates and proteins. Step 5: Chloride, together with sodium, also participates in fluid and acid–base balance, so any claim that it has no role in these processes is incorrect. Verification / Alternative check: Textbooks of physiology and biochemistry state that plasma chloride concentration is high compared with intracellular chloride, confirming its main location in extracellular fluid. Clinical laboratory reports often list chloride alongside sodium as key electrolytes. Gastric juice analysis clearly shows high concentrations of hydrochloric acid, which by definition contains chloride ions. Conditions that reduce chloride or hydrogen ion secretion can lead to reduced acidity and impaired digestion, further confirming the functional importance of chloride in gastric acid formation. Why Other Options Are Wrong: Option B is wrong because chloride is not a cation at all; it is an anion, and the major intracellular cation is potassium, not chloride. Option C is incorrect because chloride is more abundant outside cells than inside, and intracellular anions are mainly phosphates and proteins. Option D is wrong because chloride clearly contributes to fluid balance and acid–base regulation. Option E is incorrect because chloride is widely present in extracellular fluid and gastric secretions, not just in bone. Only option A correctly states that chloride helps maintain gastric acidity by forming part of hydrochloric acid in the stomach. Common Pitfalls: Learners sometimes confuse the intracellular and extracellular distribution of sodium, potassium and chloride. Another confusion is between cations and anions, leading to misclassification of ions. It is also easy to focus only on sodium and forget that chloride is equally important in maintaining osmotic balance. Always remember that chloride works with hydrogen ions in the stomach and with sodium in extracellular fluid, so it has major roles in both digestion and fluid homeostasis. Final Answer: The correct answer is Helps maintain gastric acidity by forming part of hydrochloric acid in the stomach, which is a major physiological function of chloride ions in humans.

Question 12

In chemistry, the weighted average atomic mass of an element as listed on the periodic table is usually expressed in which standard unit?

Accepted Answer

Introduction / Context: The concept of weighted average atomic mass is central to understanding the periodic table and chemical calculations. Each element has more than one isotope, and the atomic mass shown on the periodic table is a weighted average that takes into account the relative abundance of each isotope. This value is not just a simple count of protons and neutrons, but an experimentally determined average. The question asks which unit is used for this quantity, which is often called the atomic weight or relative atomic mass in basic chemistry courses. Given Data / Assumptions: The term used is weighted average atomic mass of an element. This is the value typically printed under the element symbol on the periodic table. Standard conventions in chemistry are assumed. Concept / Approach: The weighted average atomic mass is defined relative to a standard, which is one twelfth of the mass of a carbon 12 atom. The unit used is the atomic mass unit, symbol u or amu. While the numerical value of atomic mass in atomic mass units is equal to the numerical value of molar mass in grams per mole, the physical quantities and their units are conceptually different. Atomic mass is the mass of a single atom or the average mass per atom, while molar mass refers to the mass of one mole of atoms. The approach is to recall that periodic table values are quoted in atomic mass units as a microscopic mass unit. Step-by-Step Solution: Step 1: Recognise that the quantity described is the average mass of one atom of an element, based on natural isotopic abundances. Step 2: Recall that chemists use a special small mass unit, the atomic mass unit, to express masses at the atomic scale. Step 3: The definition of one atomic mass unit is one twelfth of the mass of a carbon 12 atom, making it convenient for comparing atomic masses. Step 4: Therefore, the weighted average atomic mass of an element is expressed in atomic mass units, amu or simply u. Step 5: Molar mass, on the other hand, uses gram per mole and is related but not the same conceptually. Verification / Alternative check: Looking at any modern periodic table, you will see atomic masses listed as numbers like 12.01 for carbon or 35.45 for chlorine. These numbers are understood to be in atomic mass units. Textbooks often write the unit explicitly when introducing the concept. At the same time, they explain that the molar mass in grams per mole has the same numerical value, but this is because one mole contains Avogadro number of atoms. This cross check between atomic mass and molar mass supports the distinction between the amu unit for atomic scale and g/mol for molar quantities. Why Other Options Are Wrong: Option B, gram, is too large a unit for the mass of a single atom and is instead used for macroscopic samples. Option C, gram per mole, is the unit of molar mass, not the microscopic atomic mass itself. Option D, per mole, is dimensionally incorrect for a mass quantity. Option E, kilogram per cubic metre, is a density unit, not a mass unit. Only option A correctly identifies atomic mass unit, amu or u, as the standard unit for the weighted average atomic mass printed on the periodic table. Common Pitfalls: A frequent confusion is treating atomic mass and molar mass as identical quantities because their numerical values match. Students sometimes write g/mol when asked for the unit of atomic mass. It is important to distinguish between the mass of a single atom, which uses amu, and the mass of a mole of atoms, which uses g/mol. Keeping track of microscopic versus macroscopic quantities helps avoid unit errors in stoichiometry and other calculations. Final Answer: The correct unit is Atomic mass unit (amu or u), which is used to express the weighted average atomic mass of an element on the periodic table.

Question 13

In terms of chemical bonding, the bonding in barium oxide (BaO) is best described as which dominant type of bond?

Accepted Answer

Introduction / Context: Classifying the type of bonding in compounds is an essential skill in basic chemistry. Barium oxide, BaO, is a simple binary compound of a metal and a nonmetal. Students are often asked whether such compounds are ionic or covalent and how to justify the choice. This question focuses on the dominant bonding in BaO and tests your understanding of periodic trends and the behaviour of metal and nonmetal combinations. Given Data / Assumptions: Compound: barium oxide, formula BaO. Barium is an alkaline earth metal in group 2 of the periodic table. Oxygen is a nonmetal in group 16. Barium commonly forms Ba²⁺ ions and oxygen commonly forms O²⁻ oxide ions. We are asked for the best description of the bonding type. Concept / Approach: The main concept is that compounds formed between a highly electropositive metal and a highly electronegative nonmetal tend to be ionic, especially when the metal is from group 1 or group 2. Barium has a low ionisation energy and readily loses two electrons to form a Ba²⁺ cation. Oxygen has a high electronegativity compared with metals and can gain two electrons to form an O²⁻ anion. The strong electrostatic attraction between these oppositely charged ions forms an ionic lattice. While no bond is one hundred percent ionic or covalent, the dominant character in BaO is clearly ionic. Step-by-Step Solution: Step 1: Identify barium as a group 2 metal that commonly forms Ba²⁺ ions by losing two valence electrons. Step 2: Identify oxygen as a nonmetal that commonly gains two electrons to form O²⁻ oxide ions. Step 3: Recognise that electrostatic attraction between Ba²⁺ and O²⁻ ions forms a crystal lattice characteristic of ionic solids. Step 4: Compare this picture to typical covalent bonding, where electrons are shared rather than completely transferred, which is more common between nonmetals. Step 5: Conclude that the bonding in BaO is best described as predominantly ionic bonding between Ba²⁺ and O²⁻ ions. Verification / Alternative check: Additional evidence for ionic bonding in BaO includes its physical properties. Barium oxide has a high melting point and boiling point, typical of ionic solids with strong ionic attractions. It also conducts electricity when molten, because ions are free to move in the liquid state. In water, BaO reacts to form barium hydroxide, again behaving like an ionic oxide of an alkaline earth metal. These observable properties align well with an ionic bonding model and not with purely covalent or metallic bonding. Why Other Options Are Wrong: Option B is wrong because nonpolar covalent bonds form mainly between identical nonmetal atoms, not between a metal like barium and a nonmetal like oxygen. Option C suggests polar covalent bonds, but the electronegativity difference and metal nonmetal combination favour ionic character rather than shared electron pairs. Option D describes metallic bonding, which is found in pure metals or alloys, not in metal oxides of this type. Option E mentions hydrogen bonding, which requires hydrogen atoms bonded to highly electronegative atoms such as O, N or F; BaO has no hydrogen and therefore cannot form hydrogen bonds. Only option A correctly describes the bonding in BaO as predominantly ionic between Ba²⁺ and O²⁻ ions. Common Pitfalls: A common mistake is to assume that every bond has to be classified as purely ionic or purely covalent, when in reality bonding is often a spectrum. However, for exam questions, simple rules based on metal and nonmetal combinations usually apply. Another pitfall is confusing metal oxides like BaO with covalent oxides such as CO2 or SO2. Remember that oxides of highly electropositive metals in groups 1 and 2 are almost always ionic in character. Final Answer: The correct description is Predominantly ionic bonding between Ba²⁺ and O²⁻ ions, which best explains the structure and properties of barium oxide.

Question 14

In cement chemistry, which compound present in ordinary Portland cement predominantly contributes to the ultimate long term strength of hardened cement paste?

Accepted Answer

Introduction / Context: Ordinary Portland cement contains several important clinker minerals, and each one contributes differently to strength development over time. Civil engineering and construction exam questions often ask which specific compound is responsible for early strength and which one controls ultimate long term strength. This question focuses on identifying the compound that mainly contributes to the ultimate strength of hardened cement paste after long curing periods. Given Data / Assumptions: We are dealing with ordinary Portland cement composition. Major clinker phases include tricalcium silicate (C3S), dicalcium silicate (C2S), tricalcium aluminate (C3A) and tetracalcium aluminoferrite (C4AF). Gypsum is present as a set regulator. Ultimate strength refers to long term strength, typically after many weeks or months of curing. Concept / Approach: Tricalcium silicate, C3S, hydrates relatively quickly and is mainly responsible for early strength development in the first few days. Dicalcium silicate, C2S, hydrates more slowly but continues to contribute strength over a longer period, playing a major role in the ultimate strength. The aluminates and ferrites contribute to early reactions, setting behaviour and colour but are not the primary sources of long term compressive strength. The approach is to recall the distinct roles of C3S and C2S in the hydration of cement. Step-by-Step Solution: Step 1: Recall that tricalcium silicate (C3S) hydrates rapidly and is the main contributor to strength in the first seven days. Step 2: Remember that dicalcium silicate (C2S) hydrates slowly and continues to form calcium silicate hydrate gel over extended curing periods. Step 3: Understand that long term or ultimate strength, often measured after 28 days and beyond, depends significantly on the continued hydration of C2S. Step 4: Recognise that C3A and C4AF have more influence on setting time, heat evolution and other properties rather than on ultimate compressive strength. Step 5: Therefore, the compound that mainly provides ultimate strength to cement is dicalcium silicate (C2S). Verification / Alternative check: Standard texts on concrete technology provide strength development curves showing rapid early strength gain attributable to C3S, followed by gradual long term strength growth due in large part to C2S. Microstructural studies of hardened cement paste confirm ongoing hydration of C2S at later ages. In practical terms, concretes with higher C2S content tend to gain strength more slowly but may reach higher ultimate strengths and lower heat of hydration, which is desirable for massive structures. Why Other Options Are Wrong: Option B, C3S, is mainly responsible for early strength, not ultimate strength, although it does contribute. Option C, C4AF, influences colour and some early properties but is not the main strength giving phase. Option D, C3A, reacts rapidly with water and gypsum to control setting and can generate considerable heat, but it is not the principal source of long term strength. Option E, gypsum, is added to regulate setting and prevent flash set; it does not control ultimate compressive strength. Only option A correctly identifies dicalcium silicate (C2S) as the main contributor to ultimate strength. Common Pitfalls: A common error is to select C3S for any strength related question because students remember that it gives high early strength. It is important to separate early strength from long term strength. Another pitfall is ignoring the slower but continuous hydration of C2S over weeks and months. Remembering that C3S is for early strength and C2S is for ultimate strength is a useful mnemonic in civil engineering examinations. Final Answer: The component that predominantly provides long term compressive strength is Dicalcium silicate (C2S), making it the correct answer for ultimate strength of cement.

Question 15

In photosynthesis, the reactions that directly require carbon dioxide (CO2) occur in which specific stage or part of the overall process?

Accepted Answer

Introduction / Context: Photosynthesis in plants is divided into light dependent reactions and light independent reactions, also called the Calvin cycle. Carbon dioxide fixation is a key step in building carbohydrates from inorganic carbon. This question tests your understanding of where in the photosynthetic process CO2 is actually used and incorporated into organic molecules. Knowing this helps in understanding how energy captured from light is later used to drive sugar formation. Given Data / Assumptions: Photosynthesis takes place in chloroplasts. There are two major stages: light reactions and the Calvin cycle. The question asks which reactions require CO2. Normal green plant photosynthesis is assumed. Concept / Approach: The light dependent reactions occur in the thylakoid membranes and involve absorption of light, splitting of water, release of oxygen and production of ATP and NADPH. These reactions do not directly require CO2. The Calvin cycle occurs in the stroma of the chloroplast and uses ATP and NADPH to fix CO2 into organic molecules through a series of enzyme controlled steps, beginning with carboxylation of ribulose bisphosphate. The approach is to recall which part of photosynthesis is called carbon fixation and match that to the Calvin cycle. Step-by-Step Solution: Step 1: Identify that light reactions use light energy to split water and generate ATP and NADPH, releasing oxygen as a by product. Step 2: Note that CO2 is not used in the light reactions; these steps focus on energy capture and electron transfer. Step 3: Recognise that the Calvin cycle in the stroma uses ATP and NADPH produced by the light reactions. Step 4: In the first step of the Calvin cycle, the enzyme RuBisCO catalyses the fixation of CO2 to ribulose bisphosphate, forming unstable intermediates that lead to 3 carbon sugars. Step 5: Therefore, the reactions that directly require CO2 occur in the Calvin cycle, not in the light dependent reactions. Verification / Alternative check: Diagrams of the chloroplast and photosynthetic pathways in biology textbooks consistently show CO2 entering at the Calvin cycle stage. Experimental evidence includes radioactive labelling studies in which carbon 14 labelled CO2 first appears in intermediate compounds of the Calvin cycle. The light reactions, in contrast, involve water, light, ATP and NADPH but not CO2 directly, confirming that CO2 dependent reactions are part of the Calvin cycle. Why Other Options Are Wrong: Option B is wrong because the light dependent reactions deal with light absorption and water splitting, not CO2 fixation. Option C incorrectly suggests that both stages use CO2, which they do not. Option D places CO2 requiring reactions in mitochondria, but mitochondria are primarily sites of respiration, not photosynthetic carbon fixation. Option E is clearly incorrect because biochemical reactions like photosynthesis occur inside organelles and cells, not outside the cell membrane. Only option A correctly points to the Calvin cycle in the stroma of the chloroplast as the site where reactions require CO2. Common Pitfalls: Students sometimes mix up the roles of light reactions and the Calvin cycle, thinking that CO2 must enter during the light stage because sunlight is involved. Another pitfall is confusing photosynthesis with respiration, which uses oxygen and produces CO2. Remember that in photosynthesis, CO2 is consumed during the Calvin cycle, while in respiration CO2 is produced in mitochondria. Keeping the stages and their inputs and outputs clearly separated helps avoid these misunderstandings. Final Answer: The correct stage is The Calvin cycle (dark reactions) in the stroma of the chloroplast, where CO2 is directly fixed into organic molecules.

Question 16

In inorganic nomenclature, what is the correct name for the compound with the formula Cu2CO3, based on the oxidation state of copper in this carbonate?

Accepted Answer

Introduction / Context: Correctly naming ionic compounds requires understanding the charge balance between cations and anions as well as the oxidation states of transition metals. Copper can exhibit more than one oxidation state, so Roman numerals are used in names to show the charge on the metal ion. This question asks you to identify the correct name for Cu2CO3 and therefore determine the oxidation state of copper in this carbonate compound. Given Data / Assumptions: Formula given: Cu2CO3. The carbonate ion has the formula CO3²⁻. Copper can form Cu⁺ (copper(I)) and Cu²⁺ (copper(II)) ions. The compound is assumed neutral overall. Concept / Approach: The approach is to apply charge balance. In an ionic compound, the total positive charge from the metal cations must balance the total negative charge from the anions. The carbonate ion carries a charge of 2⁻. The formula Cu2CO3 shows two copper atoms for each carbonate ion, so the combined positive charge from the two copper ions must be 2⁺ to balance the 2⁻ of carbonate. Dividing that positive charge by two gives the individual oxidation state of copper. Once the oxidation state is known, the correct stock name can be assigned using Roman numerals. Step-by-Step Solution: Step 1: Note that the carbonate ion CO3 has a charge of 2⁻. Step 2: The formula Cu2CO3 contains one CO3²⁻ ion and two Cu ions. Step 3: For overall charge neutrality, the sum of charges must equal zero, so total positive charge from copper ions must be 2⁺ to balance the 2⁻ from carbonate. Step 4: If the total positive charge from two copper ions is 2⁺, then each copper ion must have a charge of +1. Step 5: A copper ion with a +1 charge is copper(I), so the correct name is copper(I) carbonate. Verification / Alternative check: You can check by writing the compound as Cu⁺ and CO3²⁻ and then criss crossing the charges to get the formula. A 1⁺ cation and a 2⁻ anion will combine in a 2:1 ratio to give Cu2CO3. This matches the given formula and confirms the +1 oxidation state for copper. In contrast, copper(II) carbonate would be written as CuCO3 because Cu²⁺ and CO3²⁻ combine in a 1:1 ratio. This difference in formula between Cu2CO3 and CuCO3 is a useful way to distinguish the two oxidation states in carbonate compounds. Why Other Options Are Wrong: Option B, copper(II) carbonate, would correspond to CuCO3, not Cu2CO3. Option C, copper(III) carbonate, is not a common stable compound and would also not match the 2:1 ratio in the formula. Option D, basic copper carbonate, usually refers to compounds like Cu2CO3(OH)2, which include hydroxide as well as carbonate. Option E, copper hydrogen carbonate, would involve the hydrogen carbonate ion HCO3⁻ and would have a different formula. Only option A, copper(I) carbonate, correctly reflects the +1 oxidation state indicated by the Cu2CO3 formula. Common Pitfalls: Learners often assume that copper is always in the +2 state, leading them to choose copper(II) carbonate by habit. Another pitfall is forgetting to use charge balance and instead trying to guess based on typical names. Remember that the subscript numbers in formulas are linked to the charges on the ions. For transition metals that have variable oxidation states, always determine the charge from the formula before naming the compound. Final Answer: The correct IUPAC style name is Copper(I) carbonate, which corresponds to the formula Cu2CO3 with copper in the +1 oxidation state.

Question 17

In molecular polarity, the dipole moment of a water (H2O) molecule has its negative end located in which direction within the molecule?

Accepted Answer

Introduction / Context: Water is one of the most important examples used to illustrate molecular polarity. The bent shape and the electronegativity difference between oxygen and hydrogen give water a permanent dipole moment. This polarity affects many properties of water, including its high boiling point, surface tension and ability to dissolve ionic and polar substances. The question asks you to identify where the negative end of the dipole moment is located in a water molecule. Given Data / Assumptions: Molecule: H2O, with one oxygen atom and two hydrogen atoms. The H–O–H bond angle is about 104.5 degrees, giving a bent geometry. Oxygen is more electronegative than hydrogen. Dipole moment has a direction from positive to negative charge centre. Concept / Approach: The concept is that electronegativity differences in a covalent bond create partial charges. In H2O, each O–H bond is polar, with electrons more attracted toward the oxygen atom. The molecular geometry is bent, not linear, so the individual bond dipoles do not cancel. As a result, the overall dipole moment vector points toward the region of higher electron density, near the oxygen atom. The negative end of the dipole is associated with the atom that carries a partial negative charge due to attracting bonding electrons more strongly. Step-by-Step Solution: Step 1: Recognise that oxygen has a higher electronegativity than hydrogen, so in each O–H bond, electrons are drawn closer to the oxygen. Step 2: As a result, oxygen carries a partial negative charge, while each hydrogen carries a partial positive charge. Step 3: The H2O molecule is bent, not linear, so the dipoles of the two O–H bonds add rather than cancel. Step 4: The combined dipole moment points toward the more negative region near the oxygen atom. Step 5: Therefore, the negative end of the dipole moment is directed toward the oxygen atom, with the positive region near the hydrogens. Verification / Alternative check: This conclusion can be verified by looking at electrostatic potential maps of water, which show a region of more negative potential around the oxygen atom. Experimental measurements of dipole moments confirm that water has a relatively high dipole moment among small molecules. Textbook diagrams usually draw the dipole arrow pointing toward the oxygen with a plus sign near the hydrogen side, consistent with this explanation. Water behaviour as a polar solvent, able to dissolve salts by interacting with cations and anions, further supports the idea that oxygen is the negative end. Why Other Options Are Wrong: Option B is wrong because the negative charge is not localised on just one hydrogen; hydrogens are partially positive, not negative. Option C incorrectly places the negative region between hydrogens, whereas that region is comparatively positive. Option D claims that there is no dipole, which would only be true if the molecule were linear or symmetrical with cancelling bond dipoles, which is not the case for water. Option E suggests the negative end is away from oxygen, which contradicts electronegativity considerations. Only option A correctly states that the negative end of the water dipole is toward the oxygen atom. Common Pitfalls: One common mistake is to assume that because water has two hydrogens, the negative region must be between them, but geometry and electronegativity must both be considered. Another pitfall is confusing the direction of dipole arrows; some conventions draw arrows from positive to negative, while others do the reverse. To avoid confusion, focus on which atom is more electronegative and therefore carries the partial negative charge. For water, remember that oxygen is the more electronegative atom and thus is associated with the negative end of the dipole. Final Answer: The negative end of the dipole moment in water is Toward the oxygen atom, which carries a partial negative charge due to its higher electronegativity.

Question 18

Which radioactive noble gas naturally seeping from rocks is an important source of natural groundwater and indoor air pollution?

Accepted Answer

Introduction / Context: Groundwater and indoor air can be contaminated by naturally occurring substances as well as human made pollutants. Some gases originate from radioactive decay of elements in rocks and can seep into soil, water and buildings. This question asks you to identify which noble gas is a recognised source of natural groundwater and indoor air pollution. Understanding such pollutants is important for environmental chemistry and public health. Given Data / Assumptions: The gases listed are noble gases: helium, krypton, radon, argon and neon. We are concerned with natural groundwater pollution and indoor air quality. One of these gases is radioactive and produced from decay of uranium and thorium in rocks. Basic environmental science knowledge is assumed. Concept / Approach: Radon is a radioactive noble gas that arises from decay of radium, itself a decay product of uranium and thorium in the Earth crust. Radon can diffuse through soil and enter groundwater or accumulate in basements and enclosed spaces. Because it is radioactive, long term exposure to elevated radon levels increases the risk of lung cancer. Other noble gases like helium, neon, argon and krypton are largely inert and non radioactive in their common isotopes and do not significantly pollute groundwater in a harmful way at normal concentrations. The approach is to recall that radon is the problematic radioactive gas among the noble gases. Step-by-Step Solution: Step 1: List the candidate noble gases from the options: helium, krypton, radon, argon and neon. Step 2: Recall that radon is a radioactive noble gas produced by natural radioactive decay chains in rocks and soil. Step 3: Understand that radon gas can dissolve in groundwater and can also seep into houses, especially in areas with uranium rich rocks. Step 4: Recognise that helium, neon, argon and krypton are not significant radioactive pollutants in normal environmental conditions. Step 5: Conclude that the gas responsible for natural groundwater pollution among the given options is radon. Verification / Alternative check: Environmental agencies and health organisations identify radon as a major naturally occurring indoor air pollutant. Maps of radon risk often show regions where geological formations lead to higher radon emission. Studies of groundwater quality in certain areas also report elevated radon levels, especially in wells drilled into granite or other uranium containing rocks. No similar warnings are routinely issued for helium or other noble gases in groundwater, supporting the conclusion that radon is the relevant pollutant here. Why Other Options Are Wrong: Option A, helium, is inert and non radioactive in its common isotopes and is not considered a serious groundwater pollutant. Option B, krypton, also has stable isotopes and is not a major natural groundwater contaminant. Option D, argon, is present in the atmosphere and can dissolve slightly in water, but it is not harmful at normal concentrations and is not a radioactive pollutant. Option E, neon, is similarly inert and not associated with groundwater pollution. Only option C, radon, matches the description of a radioactive gas that pollutes groundwater and indoor air. Common Pitfalls: Students may be tempted to choose argon or helium because they are more familiar names or more abundant in the atmosphere. Another pitfall is to forget that the main reason radon is dangerous is its radioactivity, not its chemical reactivity. Remember that radon is unique among the noble gases in being significantly radioactive in the environment and is specifically monitored in homes and water supplies in some regions. Final Answer: The correct gas is Radon, a radioactive noble gas that can pollute groundwater and indoor air when it seeps from rocks and soil.

Question 19

In cell biology, ATP generally energises a cellular process by which primary mechanism involving its phosphate groups?

Accepted Answer

Introduction / Context: Adenosine triphosphate, ATP, is often described as the energy currency of the cell. It couples exergonic and endergonic reactions, allowing cells to perform work such as muscle contraction, active transport and biosynthesis. This question asks which specific mechanism is most commonly used by ATP to energise cellular processes. Understanding this mechanism is fundamental in biochemistry and cell biology. Given Data / Assumptions: ATP has three phosphate groups, named alpha, beta and gamma. Hydrolysis of ATP to ADP and inorganic phosphate releases free energy. Several answer choices mention transfer of phosphate, oxidation, heat release and sugar transfer. We are looking for the general and primary way ATP energises reactions. Concept / Approach: The key concept is that ATP often participates directly in reactions by transferring its terminal phosphate group to a substrate. This process is called phosphorylation. The phosphorylated intermediate is usually more reactive or has altered conformation, which allows the overall reaction to proceed. While heat is released during ATP hydrolysis, cells use the free energy primarily through chemical coupling, not as random heat. ATP also plays roles in nucleic acid synthesis, but the classic energy coupling mechanism is phosphate transfer. Step-by-Step Solution: Step 1: Recall that ATP hydrolysis involves breaking the bond between the terminal phosphate group and the rest of the molecule. Step 2: In many enzymatic reactions, the terminal phosphate group is transferred to a substrate, forming a phosphorylated intermediate. Step 3: This phosphorylation changes the energy state or shape of the substrate, making it more likely to undergo the next step in the pathway. Step 4: The enzyme catalyses both the phosphate transfer and the subsequent reaction, effectively coupling ATP hydrolysis to useful work. Step 5: Therefore, ATP generally energises cellular processes by direct chemical transfer of a phosphate group to another molecule. Verification / Alternative check: Examples abound in metabolism. In glycolysis, ATP phosphorylates glucose to form glucose 6 phosphate and later fructose 6 phosphate to fructose 1,6 bisphosphate. In active transport, such as the sodium potassium pump, ATP phosphorylates the transport protein, causing conformational changes that move ions across membranes. These examples show that phosphorylation, not simple heat release, is the common mechanism. Textbooks consistently describe ATP as driving endergonic reactions by formation of phosphorylated intermediates. Why Other Options Are Wrong: Option B, becoming oxidised, is not the primary way ATP energises processes; electron carriers like NADH and FADH2 are more directly involved in redox transfers. Option C emphasises heat release, but cells cannot efficiently harness random heat at physiological temperatures to do specific chemical work. Option D mentions transfer of the ribose sugar, which is not the typical energy coupling mechanism. Option E incorrectly suggests that ATP acts mainly as a structural membrane component, whereas phospholipids perform that role. Only option A correctly captures the general mechanism: ATP donates a phosphate group to substrates or proteins. Common Pitfalls: Students sometimes focus too much on the idea that ATP hydrolysis releases energy as heat and overlook the importance of phosphorylated intermediates. Another mistake is to confuse ATP with electron carriers, assuming that oxidation of ATP itself is the key step. Remember that ATP is used most often as a phosphate donor, while compounds like NADH are used for electron transfer. Keeping these roles distinct helps clarify metabolic pathways. Final Answer: ATP typically energises cellular processes by Direct chemical transfer of a phosphate group from ATP to another molecule, forming a higher energy phosphorylated intermediate that can undergo further reaction.

Question 20

Gammaxene (lindane), D.D.T. and bleaching powder are all important industrial and agricultural compounds of which halogen element?

Accepted Answer

Introduction / Context: Many industrial and agricultural chemicals are compounds of halogens, a group of reactive nonmetals that includes fluorine, chlorine, bromine, iodine and astatine. The question mentions three well known substances: gammaxene, also called lindane, D.D.T., and bleaching powder. It asks which element they have in common. Recognising the halogen associated with these compounds helps in understanding their properties, uses and environmental impacts. Given Data / Assumptions: Gammaxene or lindane is a chlorinated hydrocarbon insecticide based on hexachlorocyclohexane. D.D.T. is dichlorodiphenyltrichloroethane, a heavily chlorinated pesticide. Bleaching powder is calcium oxychloride, containing hypochlorite and chloride. The question asks which element is common to all of them. Concept / Approach: The common feature among these substances is the presence of chlorine atoms. Lindane has several chlorine atoms attached to a cyclohexane ring. D.D.T. has multiple chlorine atoms attached to aromatic rings and an aliphatic chain. Bleaching powder contains hypochlorite and chloride ions, both of which involve chlorine in different oxidation states. Chlorine compounds are widely used as disinfectants, bleaching agents and pesticides, but they can also have environmental and health concerns. The approach is to recall the names and compositions of these chemicals and identify chlorine as the shared element. Step-by-Step Solution: Step 1: Recognise that gammaxene or lindane is the gamma isomer of hexachlorocyclohexane, which clearly contains six chlorine atoms. Step 2: Recall that D.D.T. stands for dichlorodiphenyltrichloroethane, whose name itself indicates multiple chlorine atoms. Step 3: Bleaching powder is essentially calcium oxychloride, containing Ca(OCl)Cl, where OCl⁻ and Cl⁻ are chlorine based ions. Step 4: Nitrogen and phosphorus are not the main elements that define these compounds, although other groups may be present. Step 5: Therefore the common element forming these compounds is chlorine. Verification / Alternative check: Chemical formulas provide a direct check. Lindane can be written as C6H6Cl6, which contains six chlorine atoms. D.D.T. has the formula C14H9Cl5, again showing five chlorine atoms. Bleaching powder is often represented as Ca(OCl)Cl or a mixture containing CaCl2 and Ca(OCl)2. All of these representations contain chlorine. Reference to chemistry texts or safety data sheets confirms that chlorine chemistry is central to their function as insecticides and bleaching agents. Why Other Options Are Wrong: Option A, nitrogen, is common in many organic compounds but is not the defining element in these particular substances. Option B, phosphorus, appears in some pesticides and matches names like organophosphates, not D.D.T. or lindane. Option D, sulphur, is present in some fungicides and drugs but not as the key element in the compounds listed here. Option E, fluorine, is used in other fluorinated pesticides and refrigerants but does not characterise gammaxene, D.D.T. or bleaching powder. Only option C, chlorine, is consistently present in all three chemicals. Common Pitfalls: Students may be distracted by the fact that nitrogen and phosphorus are essential elements in agriculture and might think they must be involved in pesticides. However, the names and formulas of gammaxene and D.D.T. clearly point to chlorine. Another pitfall is to focus on the bleaching action of bleaching powder and forget that it is due to chlorine containing species like hypochlorite. Always pay attention to prefixes such as chloro and to chemical formulas when identifying common elements. Final Answer: The correct common element is Chlorine, which is present in gammaxene, D.D.T. and bleaching powder as part of their chemical structure.

Chemistry Questions