Pick the odd number: Exactly one of 729, 123, 423, and 621 is a perfect cube n^3; the others are not. Identify the perfect cube.

Difficulty: Easy

Correct Answer: 729

Explanation:

Introduction / Context:Recognizing perfect powers is a frequent classification skill. Among the four numbers, only one is exactly n^3 for an integer n.

Given Data / Assumptions:

  • Options: 729, 123, 423, 621.
  • Recall standard cubes: 8, 27, 64, 125, 216, 343, 512, 729, 1000.

Concept / Approach:Compare against known cubes or use factorization; in a perfect cube, all prime exponents are multiples of 3.

Step-by-Step Solution:

729 = 9^3 → perfect cube.123 lies between 5^3 = 125 and 4^3 = 64 → not a cube.423 lies between 7^3 = 343 and 8^3 = 512 → not a cube.621 lies between 8^3 = 512 and 9^3 = 729 → not a cube.

Verification / Alternative check:Prime factorization: 729 = 3^6 = (3^2)^3. The others do not yield exponents all multiples of 3.

Why Other Options Are Wrong:They are not exact cubes of integers.

Common Pitfalls:Assuming proximity to a cube implies equality; only exact equality counts.

Final Answer:729 is the perfect cube and hence the odd number.

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