Classification – Odd one out (divisibility by 16) Among the following integers, three are exact multiples of 16. Identify the number that is not divisible by 16 and mark it as the odd one out.

Difficulty: Easy

Correct Answer: 210

Explanation:


Introduction / Context:
This classification item hinges on recognizing a higher power-of-two factor: 16 = 2^4. While many candidates quickly see whether a number is even, fewer immediately confirm the presence of four factors of 2. Practicing this check is valuable for fast elimination in test settings.



Given Data / Assumptions:

  • Candidates: 272, 210, 240, 304
  • Target property: divisibility by 16
  • We work with ordinary base-10 integers.


Concept / Approach:
There are two practical methods: (1) perform integer division by 16 and check for remainder 0; or (2) factor out powers of 2 and ensure at least four such factors are present. Because 16 is a neat benchmark, mental division is typically quick with these values.



Step-by-Step Solution:
272 / 16 = 17 → integer → divisible by 16.240 / 16 = 15 → integer → divisible by 16.304 / 16 = 19 → integer → divisible by 16.210 / 16 = 13.125 → not an integer → not divisible by 16.



Verification / Alternative check:
Prime-factor view: 272 = 16 * 17, 240 = 16 * 15, 304 = 16 * 19 all contain 2^4; 210 = 2 * 3 * 5 * 7 has only one factor of 2 and therefore cannot reach 2^4.



Why Other Options Are Wrong:

  • 272: Multiple of 16 → fits pattern.
  • 240: Multiple of 16 → fits pattern.
  • 304: Multiple of 16 → fits pattern.
  • None of these: A single non-multiple exists (210).


Common Pitfalls:
Equating “even” with “divisible by 16.” Many even numbers (including 210) lack enough factors of 2. Always confirm using 16 directly or count powers of 2.



Final Answer:
210

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