Difficulty: Easy
Correct Answer: 65
Explanation:
Introduction / Context:
Multiples of a small prime such as 7 are common in classification exercises. Faster solutions come from either recalling times-table anchors or performing small divisions without long arithmetic.
Given Data / Assumptions:
Concept / Approach:
Check each candidate by quick division or factor recall. 28 = 7 * 4, 35 = 7 * 5, 42 = 7 * 6 are well-known. The remaining value should fail the 7-multiple test to become the odd one out.
Step-by-Step Solution:
28 → 7 * 4 → multiple of 7.35 → 7 * 5 → multiple of 7.42 → 7 * 6 → multiple of 7.65 ÷ 7 = 9 remainder 2 → not a multiple of 7.
Verification / Alternative check:
Prime-factor view: 65 = 5 * 13 contains no factor 7, confirming it is the outlier.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming “ends with 5” automatically signals special status. Ending with 5 relates to divisibility by 5, not by 7; always test the actual target factor.
Final Answer:
65
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