Difficulty: Easy
Correct Answer: 13410
Explanation:
Introduction / Context:
Converting between binary and decimal is a core skill in digital electronics and computer architecture. This question reinforces positional weighting of bits in an 8-bit unsigned number.
Given Data / Assumptions:
Concept / Approach:
Each binary 1 adds its positional weight to the total. For 8 bits, the weights are 128, 64, 32, 16, 8, 4, 2, 1. Sum only those weights where the bit is 1.
Step-by-Step Solution:
Write weights under bits: 1 0 0 0 0 1 1 0 → 128, 0, 0, 0, 0, 4, 2, 0.Add active weights: 128 + 4 + 2 = 134.Therefore, 10000110₂ = 134₁₀.
Verification / Alternative check:
Convert 134 back to binary: 128 + 4 + 2 → bits at 2^7, 2^2, 2^1 set → 10000110₂, confirming the result.
Why Other Options Are Wrong:
144₁₀, 110₁₀, 126₁₀: each includes incorrect weighting or extra/missing powers of two.
Common Pitfalls:
Misreading bit positions (especially internal zeros) or forgetting that the leftmost bit is 2^7 in an 8-bit number.
Final Answer:
13410
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