Which of the following fractions is greater than | 3 | and less than | 5 | ? |
4 | 6 |
1 |
2 |
2 |
3 |
4 |
5 |
9 |
10 |
4 |
5 |
3 | = 0.75, | 5 | = 0.833, | 1 | = 0.5, | 2 | = 0.66, | 4 | = 0.8, | 9 | = 0.9. |
4 | 6 | 2 | 3 | 5 | 10 |
Clearly, 0.8 lies between 0.75 and 0.833.
∴ | 4 | lies between | 3 | and | 5 | . |
5 | 4 | 6 |
Suppose they meet after y hours .
Then, 21y - 16y = 60
? y = 12
?required distance = (16 x 12 + 21 x 12) km.
= 444 km.
Let Reena?s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.
Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
suppose the ages of Sunil and Anil are 8x yr and 7x yr, respectively.
After 6 yr, = 136x + 102 = 133x + 114
136x ? 133x = 114 ? 102
3x = 12 X = 12/3 = 4
Age of Sunil = 8x = 8 × 4 = 32 yr
Present age Anil = 7x = 7 × 4 = 28 yr
Required difference = (32 ? 28) = 4 yr
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