555 Timer (Monostable) — Compute Output Pulse Width A 555 monostable circuit uses R1 = 4.7 kΩ and C1 = 47 µF. Using t = 1.1 * R1 * C1, determine the output pulse width and choose the closest option.

Introduction / Context:
The 555 timer in monostable mode generates a single pulse each time it is triggered. Pulse width depends on the external timing resistor and capacitor. Accurate calculation is essential for timing, control, and pulse-shaping tasks.

Given Data / Assumptions:

• R1 = 4.7 kΩ = 4700 Ω.
• C1 = 47 µF = 47 × 10^-6 F.
• Formula: t = 1.1 * R1 * C1.

Concept / Approach:
Apply the standard monostable timing relation directly and express the result in milliseconds for readability.

Step-by-Step Solution:
Compute t = 1.1 * 4700 * 47×10^-6.First multiply R1 * C1 = 4700 * 47×10^-6 ≈ 0.2209.Multiply by 1.1: 0.2209 * 1.1 ≈ 0.243 s.Convert to milliseconds: 0.243 s ≈ 243 ms.

Verification / Alternative check:
Dimensional check: Ω * F yields seconds; numerical value aligns with typical 555 timing ranges for kΩ and tens of µF.

Why Other Options Are Wrong:

• 24 s: Off by three orders of magnitude.
• 24 ms: Off by approximately a factor of 10.
• 243 µs: Off by a factor of 1000.

Common Pitfalls:
Misplacing metric prefixes (µF vs nF) or forgetting the 1.1 factor.

Final Answer:
243 ms