60 Hz TTL-level clock conditioning: Why include a Schmitt trigger stage when building a 60 Hz clock pulse generator from a noisy or slow-edged source?
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Ato provide a triangle wave
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Bto provide a sine wave
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Cto provide a rounded pulse waveform
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Dto provide a sharp pulse waveform
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Eto generate a sawtooth ramp
Answer
Correct Answer: to provide a sharp pulse waveform
Explanation
Introduction / Context:Schmitt triggers are input conditioning circuits with hysteresis. They transform slow, noisy, or sinusoidal inputs into clean digital pulses. For mains-derived 60 Hz timing or RC-derived clocks, edge shaping ensures reliable triggering of subsequent TTL logic.
Given Data / Assumptions:
- Input may have slow rise/fall or noise around switching thresholds.
- TTL devices require fast, monotonic edges to avoid multiple transitions.
- Goal: stable, crisp square pulses.
Concept / Approach:Hysteresis creates distinct Vt+ and Vt− thresholds. The Schmitt trigger ignores small excursions around the threshold and outputs rail-to-rail transitions with steep edges. This minimizes false triggers and reduces jitter introduced by input noise.
Step-by-Step Solution:Feed the slow/noisy 60 Hz signal into a Schmitt trigger input.The device outputs a clean digital pulse with fast edges.Drive TTL counters or flip-flops reliably from the conditioned waveform.
Verification / Alternative check:Oscilloscope comparison shows ragged, threshold-chattering edges without the Schmitt stage versus square, clean transitions with it.
Why Other Options Are Wrong:Triangle, sine, and sawtooth shapes are analog waveforms not provided by Schmitt triggers.“Rounded pulse” contradicts the goal of sharp edges.
Common Pitfalls:Driving TTL directly from a slow edge can cause multiple toggles and excessive power due to cross-conduction in downstream gates.
Final Answer:to provide a sharp pulse waveform