Difficulty: Medium
Correct Answer: LOW-level current is larger.
Explanation:
Introduction / Context:
Many logic families (especially TTL and some 5 V CMOS variants driving TTL-compatible loads) can sink more current at a valid LOW than they can source at a valid HIGH. Correctly orienting the LED and resistor takes advantage of this capability for brighter and more reliable operation.
Given Data / Assumptions:
Concept / Approach:
Configure the LED to VCC with its resistor, and let the gate pull the cathode LOW to turn it on. This uses the stronger sink path, ensuring the LED current meets brightness targets while keeping output within valid logic levels.
Step-by-Step Solution:
Verification / Alternative check:
Compare brightness/current achievable when sourcing versus sinking using the same output device limits.
Why Other Options Are Wrong:
Common Pitfalls:
Ignoring VOL rise with excessive sink current, not recalculating resistor value, and forgetting per-pin and per-package current limits.
Final Answer:
LOW-level current is larger.
Discussion & Comments