Which statement best describes the basic operation of a dual-slope (integrating) A/D converter?

Difficulty: Easy

Correct Answer: Integrate the input for a fixed time, then integrate a reference of opposite polarity and count time until the integrator returns to zero

Explanation:


Introduction / Context:
The dual-slope ADC is widely used in digital multimeters because it offers excellent noise rejection and accuracy at low cost. This question asks you to identify its two-phase integrate/de-integrate method.


Given Data / Assumptions:

  • Phase 1: integrate the unknown input for a precise fixed time.
  • Phase 2: apply a known reference of opposite polarity; count clock pulses until the integrator returns to zero.
  • Clock is stable and defines conversion precision.


Concept / Approach:
In the first (run-up) phase, the integrator output is proportional to Vin * T1. In the second (run-down) phase, a reference of opposite sign drives the integrator back to zero. The run-down time T2 satisfies Vin * T1 = Vref * T2, hence Vin = (Vref * T2) / T1. Counting clock pulses during T2 yields a digital result proportional to Vin, with strong line-frequency noise rejection if T1 is synchronized to mains periods.


Step-by-Step Solution:
Identify two phases: integrate Vin, then de-integrate with Vref.Note proportionality: Vin relates to counted time with fixed T1 and known Vref.Choose the description that matches this two-slope process.


Verification / Alternative check:
Textbook timing diagrams show linear ramp up during T1 and linear ramp down during T2 with the count measured only in T2.


Why Other Options Are Wrong:
A, B, C, E: Describe other converter types (V/F, single-slope, direct ramp reading, or bracketing), not dual-slope.


Common Pitfalls:
Confusing single-slope timing (input compared once) with dual-slope’s two-phase method that improves noise immunity.


Final Answer:
Integrate the input for a fixed time, then integrate a reference of opposite polarity and count time until the integrator returns to zero

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