A and B can complete a work alone in 15 days and 25 days, respectively. They start together, but B leaves after some time and A finishes the remaining work in the last 7 days. After how many days from the start did B leave?

Difficulty: Medium

Correct Answer: 5

Explanation:

Introduction / Context:When one worker leaves before completion, split the work into two phases: joint phase and solo phase. Use rates to form an equation for the total work.

Given Data / Assumptions:

  • A = 1/15 per day; B = 1/25 per day.
  • A alone finishes the last 7 days.
  • Let x = days they worked together.

Concept / Approach:Work done = x*(A+B) + 7*A = 1. Solve for x.

Step-by-Step Solution:

A+B = 1/15 + 1/25 = 8/75Equation: x*(8/75) + 7*(1/15) = 17/15 = 35/75; 1 - 35/75 = 40/75 = 8/15x = (8/15) / (8/75) = 75/15 = 5

Verification / Alternative check:Check totals: 5*(8/75) = 8/15; plus 7/15 = 1 → consistent.

Why Other Options Are Wrong:They do not satisfy the total-work equation when rates are used correctly.

Common Pitfalls:Equating times instead of work; arithmetic slips when converting to common denominators.

Final Answer:5

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