Ten men and eight women together complete a work in 5 days. One woman’s 1-day work equals half of one man’s 1-day work. In how many days will four men and six women complete the same work?

Introduction / Context:
Use the given equivalence (1 woman = 1/2 man) to convert all workers to man-equivalents, then compute time for the smaller team.

Given Data / Assumptions:

• 10 men + 8 women → 5 days.
• 1 woman = 1/2 man.

Concept / Approach:
Compute the total work in man-days, then divide by the rate of 4 men + 6 women in man-equivalents.

Step-by-Step Solution:

Verification / Alternative check:
Half-efficiency rule applied consistently across both teams yields an exact integer.

Why Other Options Are Wrong:
They miscompute either the man-equivalent conversion or the final division.

Common Pitfalls:
Using 2 women = 1 man inconsistently; ensure consistent conversion on both teams.

Final Answer:
10 days