Fourteen men and twelve boys finish a work in 4 days, while eight men and sixteen boys finish the same work in 5 days. Compare the 1-day work of 1 man with that of 1 boy (expressed as a ratio of man to boy).

Difficulty: Medium

Correct Answer: 2

Explanation:


Introduction / Context:
Two different mixed teams complete the same job in different times. Set up equations in terms of man (m) and boy (b) daily work to solve for the ratio m/b.


Given Data / Assumptions:

  • (14m + 12b)*4 = W
  • (8m + 16b)*5 = W


Concept / Approach:
Equate the two expressions for W, then solve for m in terms of b.


Step-by-Step Solution:

56m + 48b = 40m + 80b16m = 32b → m = 2bThus, man : boy (1-day work) = 2 : 1


Verification / Alternative check:
Substitute m = 2b into either team equation to confirm both give the same total job W.


Why Other Options Are Wrong:
Ratios like 1 1/2 or 3 misrepresent the algebraic balance between m and b.


Common Pitfalls:
Mixing the total-time equality with rate equality; always equate total work W.


Final Answer:
2

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