Row of 15 children – position shift reasoning: Raju is shifted three places towards the right and then becomes 8th from the right end. What was Raju’s original position from the left end of the row (before the shift)?

Difficulty: Easy

Correct Answer: 5

Explanation:


Introduction / Context:
This is a classic ranks-and-positions puzzle. We know the total number of children and how Raju’s rank changes after moving three places to the right. We must recover his original (pre-shift) position from the left end.



Given Data / Assumptions:

  • Total children N = 15.
  • After shifting 3 places to the right, Raju becomes 8th from the right.
  • We assume a single straight row numbered 1…15 from left to right.


Concept / Approach:
Convert a right-end rank to a left-end rank using left_rank = N − right_rank + 1. Then undo the “shift right by 3” to retrieve the original left-end rank.



Step-by-Step Solution:

After shift, right-rank(Raju) = 8 ⇒ left-rank(after) = 15 − 8 + 1 = 8.A shift 3 to the right increases his left-rank by +3.So original left-rank(before) = 8 − 3 = 5.


Verification / Alternative check:
Place a simple index to confirm: if before he was at left position 5, moving three to the right lands him at position 8 from left; in a row of 15, that is indeed 8th from right (15 − 8 + 1 = 8).



Why Other Options Are Wrong:
Values like 12 or 14 contradict the derived conversion; 6 would imply an after-shift left rank of 9, not matching the given 8th from right.



Common Pitfalls:
Forgetting the +1 when converting between right-rank and left-rank; or subtracting rather than adding the shift when moving right.



Final Answer:
5

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