Ten years ago, Sachin was twice as old as Ajay was then. If Sachin will be 40 years old ten years from now, how old is Ajay today?
Verbal Reasoning
Problems on Ages
Difficulty: Easy
Choose an option
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A20 years
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B10 years
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C30 years
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D15 years
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ENone of these
Answer
Correct Answer: 20 years
Explanation
Introduction / Context:Combine past-time multiplicative information with a future-time absolute age to deduce present ages.
Given Data / Assumptions:
- Sachin in 10 years = 40 ⇒ Sachin now = 30
- 10 years ago Sachin = 20, and at that time Sachin = 2 × (Ajay then)
Concept / Approach:From the past relationship, find Ajay's past age, then add the elapsed time to get Ajay's present age.
Step-by-Step Solution:
2 × (Ajay 10 years ago) = 20 ⇒ Ajay 10 years ago = 10Ajay now = 10 + 10 = 20 yearsVerification / Alternative check:Check: Ten years ago Ajay 10, Sachin 20, twice relation holds; in 10 years Sachin 40, consistent.
Why Other Options Are Wrong:10, 15, 30 contradict either the past twice relation or Sachin’s future age.
Common Pitfalls:Forgetting to convert the future age into present age before using the past condition.
Final Answer:20 years.