The difference between Meena’s and Seema’s present ages is 3 years, and the ratio of their ages is 7 : 8. What is the sum of their present ages?

Difficulty: Easy

Correct Answer: 45 yr

Explanation:


Introduction / Context:
With both a ratio and a difference, solve for the ratio multiplier, then compute individual ages and the sum.


Given Data / Assumptions:

  • Meena : Seema = 7 : 8 ⇒ Meena = 7k, Seema = 8k
  • Difference = 3 ⇒ 8k − 7k = 3


Concept / Approach:
Find k from the difference in the ratio components; sum is then 15k.


Step-by-Step Solution:

k = 3Meena = 21, Seema = 24Sum = 21 + 24 = 45


Verification / Alternative check:
Ratio check: 21 : 24 reduces to 7 : 8; difference 3 holds.


Why Other Options Are Wrong:
41, 43, 48 do not equal 15k with k = 3.


Common Pitfalls:
Treating the difference as 7k − 8k = 3 (negative) or summing 7 + 8 first.


Final Answer:
45 yr.

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