The difference between Meena’s and Seema’s present ages is 3 years, and the ratio of their ages is 7 : 8. What is the sum of their present ages?

Difficulty: Easy

Correct Answer: 45 yr

Explanation:

Introduction / Context:With both a ratio and a difference, solve for the ratio multiplier, then compute individual ages and the sum.

Given Data / Assumptions:

  • Meena : Seema = 7 : 8 ⇒ Meena = 7k, Seema = 8k
  • Difference = 3 ⇒ 8k − 7k = 3

Concept / Approach:Find k from the difference in the ratio components; sum is then 15k.

Step-by-Step Solution:

k = 3Meena = 21, Seema = 24Sum = 21 + 24 = 45

Verification / Alternative check:Ratio check: 21 : 24 reduces to 7 : 8; difference 3 holds.

Why Other Options Are Wrong:41, 43, 48 do not equal 15k with k = 3.

Common Pitfalls:Treating the difference as 7k − 8k = 3 (negative) or summing 7 + 8 first.

Final Answer:45 yr.

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion