Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context:
The “5τ rule” is a convenient guideline for first-order responses to a step input: after about five time constants, a system is essentially settled near its final value. However, applying this rule blindly to RC integrators driven by pulse trains can be misleading. The steady-state level depends on waveform shape, duty cycle, and repetition rate, not just elapsed time.
Given Data / Assumptions:
Concept / Approach:
For a single step, the capacitor voltage approaches its final value as v_C(t) = V_final − (V_final − V_initial) * exp(−t/τ). After ~5τ, the error is under 1%. For a pulse train, the output is the convolution of the input with the RC exponential; the final steady-state depends on the periodic input’s average and duty cycle. Multiple pulses within 5τ continually perturb the capacitor, preventing it from reaching the same level as a single uninterrupted step would. Therefore, “steady-state after 5τ regardless of pulses” is incorrect.
Step-by-Step Solution:
Verification / Alternative check:
Simulate with τ = 10 ms and a 2 ms wide pulse repeating every 4 ms. Even after many multiples of 5τ, the waveform remains a periodic ripple around a duty-cycle-dependent mean, not a step-like flat level. This contradicts the claim.
Why Other Options Are Wrong:
Common Pitfalls:
Using “5τ” as a magic number for every situation; forgetting that different inputs produce different steady-state behaviors even in the same RC network.
Final Answer:
Incorrect.
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