Difficulty: Easy
Correct Answer: Cannot be determined from the information provided
Explanation:
Introduction / Context:
The initial voltage of a capacitor at the start of a subsequent pulse depends on how much it charged during the previous high interval and how much it discharged during the low interval. Both are governed by τ = R * C and the specific high/low times (duty cycle). With no numeric values or figure, the exact voltage cannot be computed.
Given Data / Assumptions:
Concept / Approach:
Over one period, the capacitor charges toward a level during “high” and discharges during “low,” each following v_C(t) = V_final + (V_initial − V_final) * exp(−t/τ). The steady-state beginning-of-pulse value is found by equating the end of one interval to the start of the next. This requires τ and the timing parameters; absent them, there is no unique voltage.
Step-by-Step Solution:
Verification / Alternative check:
Examples with τ ≪ period produce near-zero start voltages; τ ≫ period produces significant memory (v1 near prior average), proving dependence on missing data.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming the 1τ percentages apply to any arbitrary pulse timing; they apply only when interval length equals τ.
Final Answer:
Cannot be determined from the information provided.
Discussion & Comments