Difficulty: Easy
Correct Answer: greater than or equal to 5 time constants
Explanation:
Introduction / Context:In first-order systems, “complete” charging is a practical notion. Engineers often use 5τ as a rule of thumb for ≈99% settling of an exponential response. This item asks how the pulse width (the available charging time) must compare with τ to achieve near-full charging during a pulse interval.
Given Data / Assumptions:
Concept / Approach:The capacitor voltage follows v_C(t) = V_final + (V_initial − V_final) * exp(−t/τ). After t = 5τ, the residual error is exp(−5) ≈ 0.0067, or about 0.7%. Thus, a pulse that lasts at least 5τ allows the capacitor to get within about 1% of its asymptotic value for that interval. Shorter pulses yield proportionally less settling.
Step-by-Step Solution:
Define settling goal: ≈99% in practical design.Use the exponential error term e^(−t/τ).Solve e^(−t/τ) ≤ 0.01 → t ≥ 4.6τ; designers round to 5τ.Therefore, PW ≥ 5τ is a standard engineering guideline.Verification / Alternative check:Simulation or measurement of step response shows 63% at 1τ, 95% at 3τ, ≈99% at 5τ, reinforcing the rule.
Why Other Options Are Wrong:
Common Pitfalls:Treating “complete” as 100% in finite time; exponentials only approach asymptote, so 5τ is a practical design target.
Final Answer:Greater than or equal to 5 time constants.
Discussion & Comments