Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context:
Fault-finding in simple RC networks often relies on qualitative symptoms. In an RC integrator (input → R_series → node → C_to_ground, with output measured at the node across C), a “zero volts” reading at the output suggests a specific type of failure. This question checks whether “capacitor open” is the likely cause or if another fault better explains the symptom.
Given Data / Assumptions:
Concept / Approach:
In the integrator, the capacitor must charge and discharge to develop output voltage. If the capacitor is shorted, the output node is effectively clamped to ground potential, resulting in ~0 V regardless of input (apart from possible small source resistance drops). If the capacitor is open, the node becomes floating; depending on stray/leak paths, the output may drift, show spikes via parasitics, or even mirror portions of the input through stray capacitances—but it is not automatically a rock-solid 0 V. Thus, “0 V ⇒ capacitor open” is not the best conclusion; “0 V ⇒ capacitor short” is more consistent with the observed symptom.
Step-by-Step Solution:
Verification / Alternative check:
Practical troubleshooting guides list “shorted shunt capacitor” as a cause of no output in RC coupling/integrator stages. Replacing the capacitor or lifting one lead to test continuity confirms the diagnosis empirically.
Why Other Options Are Wrong:
Common Pitfalls:
Equating “no signal” with any component being open; overlooking that an open component often yields a floating node (undefined), not a hard zero.
Final Answer:
Incorrect.
Discussion & Comments