Given : S.I. = Rs. 50.
I gives, R = 10% p.a.
II gives, T = 10 years.
Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50
I=
I=prt
Now, the principal amount P = Rs. 1,45,440
Rate of interest R = 20%/annum
Now monthly income I = PTR/100 = 1,45,440 x 20 x 1/100 x 12
= 2908800/1200
= Rs. 2424.
Hence, her monthly income = Rs. 2424.
Let rate = R% and time = R years.
Then, (1200 x R x R) / 100 = 432
=> R = 6.
Let x be the investment of Lasya in 5% and y be in 4%
x(5)(n)/100 = y(4)(n)/100
=> x/y = 4/5
x : y = 4 : 5
Where d is difference, r is rate of interest.
=> (48 x 100 x 100) / 8 x 8 = Rs.7500
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