Simple Interest – Time to quadruple when doubling time is known: If a certain sum doubles itself in 8 years at simple interest, in how many years will it become four times the principal?

Difficulty: Easy

Correct Answer: 24 years

Explanation:


Introduction / Context:
In simple interest, growth is linear with time. If we know the time to double, we can scale proportionally to find the time to quadruple the principal.



Given Data / Assumptions:

  • Doubling time t2 = 8 years
  • Simple interest model


Concept / Approach:
Doubling at SI means interest equals P over 8 years, so r = 1 / 8 = 12.5% per annum. For quadrupling (A = 4P), interest must be 3P, so time t4 = 3P / (P * r) = 3 / r.



Step-by-Step Solution:

From doubling: r = 1 / 8 = 0.125 = 12.5%For A = 4P: required interest = 3Pt = 3P / (P * 0.125) = 3 / 0.125 = 24 years


Verification / Alternative check:

Linear scaling: Doubling needs 8 years; quadrupling needs twice the gain (from +P to +3P is 3 times P vs 1P), but relative to zero it is threefold interest. Time = 3 * 8 / 1? Using r is clearer; result 24 years.


Why Other Options Are Wrong:

  • 16/12/20 years: inconsistent with r = 12.5%.
  • 32 years: overestimates required time.


Common Pitfalls:

  • Treating the process as compounding.
  • Confusing quadruple of P with four times the interest.


Final Answer:
24 years.

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