Effect of Removing an Iron Core from a Coil An iron-cored inductive coil is converted into an air-cored coil by removing the iron core (geometry unchanged). How does its inductance change?
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AIncreases
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BDecreases
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CRemains the same
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DMay increase or decrease depending on frequency
Answer
Correct Answer: Decreases
Explanation
Introduction / Context:Inductance quantifies the magnetic flux linkage produced per unit current. Core materials with high relative permeability dramatically boost flux for a given current and geometry, increasing inductance. Removing such a core leaves only air (or vacuum), whose permeability is much smaller, so the flux and inductance drop accordingly.
Given Data / Assumptions:
- Same number of turns, dimensions, and current.
- Core is changed from high-μ (iron/steel) to μ ≈ μ0 (air).
- Linear operation (no core saturation assumed).
Concept / Approach:
For a solenoid-like coil, L ∝ μ N^2 A / l, where μ is the core permeability, N is turns, A is cross-sectional area, and l is magnetic path length. Replacing μ by μ0 (air) reduces L roughly by the factor μr (relative permeability), which for iron can be hundreds to thousands in the unsaturated region.
Step-by-Step Solution:
Start with L ∝ μ.Change core: μ_high → μ0.Therefore, L decreases by approximately μr.Verification / Alternative check:
Measured inductance of transformer coils plummets when the laminated core is removed, which is why air-core inductors require many more turns for the same L.
Why Other Options Are Wrong:
- Increase or remain same contradicts L ∝ μ for fixed geometry.
- “May increase or decrease” is not applicable here; the trend is unambiguous.
Common Pitfalls:
Confusing Q-factor (which can improve without core losses) with inductance value; overlooking saturation or hysteresis effects, which are separate issues.
Final Answer:
Decreases