Four players M, N, O, P are seated at a card table. M is on the right of N. P is on the left of O. Which pair are partners (i.e., seated opposite each other)?

Introduction / Context:With four people around a square/round table, “partners” are the two who sit opposite. Right/left are taken with everyone facing inward.

Given Data / Assumptions:

• M is on the right of N ⇒ in inward-facing terms, M is the counterclockwise neighbor of N.
• P is on the left of O ⇒ P is the clockwise neighbor of O.

Concept / Approach:Place N, then put M immediately to N’s right. Separately ensure P is immediately to O’s left. Fit the four around the table and identify opposite seats.

Step-by-Step Solution:A consistent clockwise order is: N, O, P, M.Check: M is right of N (counterclockwise neighbor) — yes (M is before N when listing clockwise).P is left of O (clockwise neighbor) — yes (P follows O clockwise).Opposite pairs are (N, P) and (O, M).

Verification / Alternative check:Trying other rotations yields the same opposite pairing structure.

Why Other Options Are Wrong:They are adjacent pairs, not opposites, or they conflict with right/left constraints.

Common Pitfalls:Using classroom right/left instead of inward-facing circular right/left.

Final Answer:N and P