Seating (row) — who is at the extremes? Panel of six in one row. X is to the left of Q but on the right of P (so P < X < Q). Y is on the right of Q but on the left of Z (Q < Y < Z). Z is to the left of R (Z < R). Which members are at the two extreme ends?

Introduction / Context:
This classic single-row ordering asks which members must occupy the two ends given a set of left/right inequalities.

Given Data / Assumptions:

• P < X < Q.
• Q < Y < Z.
• Z < R.
• All six are distinct in one linear row (left→right).

Concept / Approach:
Chain the inequalities to build a single consistent order. If A < B and B < C, then A precedes C; the “right of”/“left of” constraints translate directly into < relations.

Step-by-Step Solution:
From P < X < Q and Q < Y < Z we infer P < X < Q < Y < Z.With Z < R, we extend to P < X < Q < Y < Z < R.Thus the only feasible linearization places P at the extreme left and R at the extreme right.

Verification / Alternative check:
Any attempt to push another element to either end violates at least one inequality (e.g., moving X left of P or Y right of R contradicts the chain).

Why Other Options Are Wrong:
Pairs like QZ, XZ, QY include interior elements (Q, X, Y, Z) that cannot sit at ends without breaking inequalities.

Common Pitfalls:
Confusing “to the right of” with “immediately to the right of.” The clues are relative, not necessarily adjacent, except where stated.

Final Answer:
PR