Five persons A, B, C, D, E sit in a row facing the viewer. D is on the left of C; B is on the right of E; A is on the right of C; and B is on the left of D. If E is at a corner (end), who sits in the center?

Introduction / Context:
We must produce a total order from multiple inequalities and then select the middle (3rd) seat, given that E occupies one of the ends.

Given Data / Assumptions:

• D left of C ⇒ D < C.
• B right of E ⇒ E < B.
• A right of C ⇒ C < A.
• B left of D ⇒ B < D.
• E is at an end.

Concept / Approach:
Merge: E < B < D < C < A. This chain already forces E to the extreme left and A to the extreme right, consistent with the end condition.

Step-by-Step Solution:
Left→right order: E, B, D, C, A.The center (3rd) seat is D.

Verification / Alternative check:
All four constraints are satisfied in this order.

Why Other Options Are Wrong:
A/B/C are at positions 5,2,4 respectively, not the center.

Common Pitfalls:
Placing E at the right end flips the chain and breaks B left of D.

Final Answer:
D