Six friends sit in a circle. C is to the left of D. F sits between A and E; and E sits between F and D. Who is to the left of F?

Introduction / Context:
We must use consecutive “between” relations to lock a partial circular order and then infer the immediate left neighbor of F (for inward-facing seating, left = clockwise neighbor).

Given Data / Assumptions:

• C is to the left of D ⇒ C is the clockwise neighbor of D.
• F sits between A and E ⇒ around the circle we have A–F–E or E–F–A consecutively.
• E sits between F and D ⇒ we must have F–E–D consecutively in that order.

Concept / Approach:
From “E between F and D,” fix the triple F–E–D in clockwise order. From “C left of D,” place C after D in clockwise order. Insert A so that F is between A and E, giving A–F–E–D–C–(remaining seat).

Step-by-Step Solution:
A consistent clockwise order is: A, F, E, D, C, (B).With inward-facing seating, the immediate left of F is its clockwise neighbor, which is E.

Verification / Alternative check:
Rotations of the arrangement maintain E to F’s left.

Why Other Options Are Wrong:
They place a different neighbor to F’s left, contradicting the required consecutive triples.

Common Pitfalls:
Reversing left/right for inward-facing circles.

Final Answer:
E