Five students K, L, P, Q, S are in one row. S is to the right of L. P is to the left of L but to the right of K. S is to the left of Q. Who is first from the left end?

Introduction / Context:We must determine the leftmost student using relative left–right constraints.

Given Data / Assumptions:

• P left of L but right of K ⇒ K < P < L.
• S right of L ⇒ L < S.
• S left of Q ⇒ S < Q.

Concept / Approach:Combine to get the chain K < P < L < S < Q, which fixes the full order.

Step-by-Step Solution:Left→right: K, P, L, S, Q.First from the left is K.

Verification / Alternative check:Every original relation matches the obtained sequence.

Why Other Options Are Wrong:L/P/S cannot be left of K under the given constraints.

Common Pitfalls:Misplacing Q relative to S.

Final Answer:K