Age order from statements: Amit and Sumit are twins (same age). Richa is younger than Sumit. Richa is younger than Jyotsana but older than Saurabh. Sumit is younger than Jyotsana. Who is the eldest among them?

Difficulty: Easy

Correct Answer: Jyotsana

Explanation:


Introduction / Context:
This is an age-ordering problem with clear pairwise comparisons, including a twin pair (equal ages). We must identify the oldest person given the constraints.



Given Data / Assumptions:

  • Amit and Sumit are twins ⇒ Amit = Sumit.
  • Richa < Sumit.
  • Richa < Jyotsana and Richa > Saurabh.
  • Sumit < Jyotsana.


Concept / Approach:
Combine all inequalities into a single order. From Sumit < Jyotsana and Amit = Sumit, both twins are below Jyotsana. With Richa less than Sumit, and Saurabh less than Richa, the unique topmost candidate is Jyotsana.



Step-by-Step Solution:

1) Twins: Amit = Sumit.2) Sumit < Jyotsana ⇒ Jyotsana above both Sumit and Amit.3) Richa < Sumit and Richa < Jyotsana; also Saurabh < Richa.4) Consolidated order (youngest→oldest): Saurabh < Richa < (Amit = Sumit) < Jyotsana.


Verification / Alternative check:
Every relation is satisfied by the chain above; no one is above Jyotsana, so she is the eldest.


Why Other Options Are Wrong:

  • Amit: Same age as Sumit, and Sumit is younger than Jyotsana.
  • Richa, Saurabh: Each is explicitly younger than at least two others.
  • None of these: A correct explicit option exists (Jyotsana).


Common Pitfalls:
Overlooking that “twins” implies equality, not relative order between the two but still below Jyotsana per the given.


Final Answer:
Jyotsana

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