Find the youngest using age differences: Sashi is 2 years older than Sunita. Sunita is 3 years older than Bindu. Shekhar is 1 year older than Bindu. Who is the youngest in the group?
Verbal Reasoning
Ranking Test
Difficulty: Easy
Choose an option
-
ASashi
-
BShekhar
-
CBindu
-
DSunita
-
ENone of these
Answer
Correct Answer: Bindu
Explanation
Introduction / Context:Age-difference questions are easily handled by setting a baseline variable and expressing others relative to it. The youngest will be the one with the smallest algebraic value.
Given Data / Assumptions:
- Sashi = Sunita + 2.
- Sunita = Bindu + 3.
- Shekhar = Bindu + 1.
- All ages are integers in the same time frame.
Concept / Approach:Let Bindu = b. Then compute each other person in terms of b and compare magnitudes.
Step-by-Step Solution:
Let Bindu = b.Sunita = b + 3.Sashi = (b + 3) + 2 = b + 5.Shekhar = b + 1.Ordering by age: Sashi (b+5) > Sunita (b+3) > Shekhar (b+1) > Bindu (b).Verification / Alternative check:Sample values: if Bindu = 10, then Shekhar = 11, Sunita = 13, Sashi = 15. Clearly Bindu is youngest. Any other b preserves this order.
Why Other Options Are Wrong:
- Sashi/Sunita/Shekhar: Each is defined as Bindu plus a positive number, hence older than Bindu.
- None of these: Not applicable because Bindu is explicitly the youngest among the listed names.
Common Pitfalls:Mixing up “older than” direction or forgetting to propagate differences correctly (e.g., computing Sashi as Sunita − 2).
Final Answer:Bindu