Find the youngest using age differences: Sashi is 2 years older than Sunita. Sunita is 3 years older than Bindu. Shekhar is 1 year older than Bindu. Who is the youngest in the group?

Introduction / Context:Age-difference questions are easily handled by setting a baseline variable and expressing others relative to it. The youngest will be the one with the smallest algebraic value.

Given Data / Assumptions:

• Sashi = Sunita + 2.
• Sunita = Bindu + 3.
• Shekhar = Bindu + 1.
• All ages are integers in the same time frame.

Concept / Approach:Let Bindu = b. Then compute each other person in terms of b and compare magnitudes.

Step-by-Step Solution:

Verification / Alternative check:Sample values: if Bindu = 10, then Shekhar = 11, Sunita = 13, Sashi = 15. Clearly Bindu is youngest. Any other b preserves this order.

Why Other Options Are Wrong:

• Sashi/Sunita/Shekhar: Each is defined as Bindu plus a positive number, hence older than Bindu.
• None of these: Not applicable because Bindu is explicitly the youngest among the listed names.

Common Pitfalls:Mixing up “older than” direction or forgetting to propagate differences correctly (e.g., computing Sashi as Sunita − 2).

Final Answer:Bindu