Series-Parallel Circuits Questions

• Bleeder current is the total current left after the total divider current is subtracted from the total current into the circuit.
• The total power is 10 watts.
• When analyzing series–parallel circuit currents, you should start with the current in the branch farthest from the source.
• R2 is open.
• If the Wheatstone bridge is balanced in the given circuit, the voltage between points A and B (VAB) equals the source voltage (VS).
• The total resistance in the circuit is 1.6 kΩ.
• The power dissipated by R4 is 211 mW.
• The voltmeter will read 18 volts.
• The total resistance in the given circuit can be found using the formula: RT = R1 + R2 || R3 || R4.
• When resistors burn out, they usually short.
• The voltage across R3 is 20 volts.
• The voltage across R1 is 175 volts.
• When a load resistance is connected to the output of a voltage divider circuit, the source current increases.
• The current through R1 is 17 mA.
• A Wheatstone bridge may be used to determine the value of an unknown resistance.
• A loaded voltage divider is a common application of a series-parallel circuit.
• Opens and shorts are typical problems that occur in electric circuits.
• Attaching a 6 kΩ load to a voltage divider will cause a smaller decrease in the output voltage than will attaching a 5 kΩ load.
• In the given circuit, the Thevenin voltage equals 6 V.
• The voltage out when a 10 kΩ load is connected is 5.7 volts.