Series branch current identity: In a simple series circuit carrying 17 mA, the current through any series element (for example, resistor R1) equals the branch current, i.e., 17 mA. Judge whether this statement is correct.

Introduction / Context:
Distinguishing series from parallel behavior is critical. In series connections, the same current flows sequentially through each component. This principle holds regardless of individual resistance values and is the reason voltage, not current, divides among series elements.

Given Data / Assumptions:

• Series circuit with a measured or known branch current of 17 mA.
• Resistor R1 is one element in that series branch.
• Ideal wires and components for the conceptual statement.

Concept / Approach:
By definition, a series connection provides only one path for current. Kirchhoff’s Current Law at the node between series elements states that the current entering equals the current leaving. Therefore, the same 17 mA passes through every series element, including R1. Voltages differ by resistance (V = I * R), but current is identical in series.

Step-by-Step Solution:

Verification / Alternative check:
Measure current with an ammeter inserted at different series points; readings are equal (accounting for meter insertion effects). SPICE simulations confirm equal series currents.

Why Other Options Are Wrong:

• Incorrect / depends on tolerance / only DC: Tolerance affects voltage division; the current equality holds for DC and AC in purely series resistive paths.
• True only if R1 is smallest: Value does not change current equality; it changes voltage drop.

Common Pitfalls:
Assuming different currents through different series parts; confusing with parallel branches where current divides.

Final Answer:
Correct