Let the total length of pencil = L cm
Then, black part = L/8
? Remaining part = L - L/8 = 7L/ 8
and White part = (7L/8)/2 = 7L/8
? Remaining part = L - (L/8 + 7L/16) = 7L/16
? length of blue part = 7L/16
According to the question,
7L/16 = 31/2
? 7L/16 = 7/2
? L =8
Total length of the rod = 330 cm
Length of a piece = 13.2 cm.
Required number of pieces = Total length/Length of a piece ;
Required number of pieces = 330/13.2 = 25
27 x 1.2 x 5.5262 x 0.6
= 27 x [(12 - 1) / 9] x [(55262 - 5526)/9000] x (6/9)
= (27 x 11)/9 x (49736/9000) x (6/9)
= 1094192 / 9000
= 121.576888...
= 121.5768
Let the length of lamppost = L m
Then,first part = L/3
and second part = (3/8) x L/3 = L/8
and third part = 6 m 50 cm = 6.50 m
First part + second part + Third part = length of lamppost
? L/3 + L/8 + 6.5 = L
? L - L/3 - L/8 =6.5
? (24L - 8L - 3L)/24 = 6.5
? 13L/24 = 6.5
? L = (65.x 24)/13 = 12 m
If the required fraction be N.
Then, (N x N) / (1/N) = 1826/27
? N3 = 512 / 27
? N = 8/3 = 22/3
Let man's salary be Rs. N
Money spend on food =N/7
Money spends on clothing = (N - N/7) x 1/2 = (6N/7) x (1/2) =3N/7
Money spend on entertainment = (N - N/7 - 3N/7)/3 = (7N - 4N)/7 = N/7
Now, money left =600
? N - N/7 - 3N/7 - N/7 = 600
? 7N - 5N/7 = 600
? N = 600 x 7/2 = Rs. 2100
? Money spend on entertainment = 1/7 x 2100 = Rs. 300
Number of male voters = 4/10 of 1575 = 4/10 x 1575 = 630
Number of female voters=1575 - 630 = 945
Now, total votes that candidate got = (6/10) x 630 + (4/10) x 945 = 378 + 378 = 756
Let the population of village = N
Then, adult's population = 5N/8
and adult females = 1/2 x 5N/8 = 5N/16
? illiterate females = 4/5 of adult female population
? 400 = 4/5 x 5N/16
? N = (400 x 16)/4
? N = 1600
Total number of students participated = (B/4 + 3G/4)
? Required percentage= (B/4 + 3G/4) / (B+G) x 100%
Clearly, given data is inadequate.
Time required for service before overhauling = 2/3h = 40 min in 45 days
and time required for service after overhualing =2/3h= 40 min in 60 days
Now,LCM of 45 and 60 = 180 days
time required for service before overhauling is 180 days = 40 x 4 = 160 min
and time required for service before overhauling is 180 days =40 x 3 = 120 min
? fraction of time saved = 160 - 120/160 =40/160 = 1/4
Length of each piece = 31/4 = 13/4 m
Maximum pieces that can be cut = 30/(13/4) = 9
? Rope left = 30 - 13/4 x 9 = 120 - 117/4 = 3/4 m
? Required fraction = 3/4/30 = 1/4
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