Determine three fractions from sum and comparative conditions (set 2): The sum of three fractions is 2 11/24. The greatest divided by the smallest equals 7/6, and this quotient exceeds the middle fraction by 1/3. Find the three fractions.

Introduction / Context:
This is a restatement of the prior problem with the same conditions and numbers. We again use two comparative constraints along with a total-sum requirement to fix the three unknown fractions uniquely. The method mirrors proportional reasoning and sum balancing.

Given Data / Assumptions:

• Total sum = 2 11/24 = 59/24.
• (Greatest)/(Smallest) = 7/6.
• Middle = 7/6 − 1/3 = 5/6.

Concept / Approach:
Let smallest = x, greatest = (7/6)x, middle = 5/6. Solve x from the sum equation, then compute the other two fractions, and verify all constraints, including the quotient and the additive total.

Step-by-Step Solution:

Verification / Alternative check:

Why Other Options Are Wrong:

• All other sets fail either the exact sum or the exact quotient/middle relationship.

Common Pitfalls:

• Miscalculating the mixed fraction 2 11/24.
• Confusing the phrase “greater by 1/3” and applying it to the wrong quantity.

Final Answer: