Counter (digital-ramp) ADC scaling: For a counter-type (digital-ramp) ADC, how does the worst-case conversion time change when you add one more bit of resolution (increase N by 1)? Choose the most accurate trend.

Difficulty: Easy

Correct Answer: doubles

Explanation:


Introduction / Context:
In a counter-type (digital-ramp) ADC, a binary counter drives a DAC. The system increases the count until the DAC output just exceeds the analog input; the count at that moment is latched as the conversion result. This architecture’s conversion time depends on how many DAC codes must be tried sequentially.


Given Data / Assumptions:

  • N-bit resolution; codes range from 0 to 2^N − 1.
  • Clock period is fixed; one code step per clock.
  • Worst case occurs when input is near full-scale, requiring nearly all counts.


Concept / Approach:
Worst-case conversion time is proportional to the number of codes to test. For N bits, that is approximately 2^N clock periods. Increasing resolution by one bit doubles the number of possible counts (2^(N+1) vs 2^N), so the worst-case time doubles. Average time also scales proportionally, though exact factors depend on input distribution and start-from-zero or tracking variants.


Step-by-Step Solution:
1) Codes to test (worst case) ≈ 2^N.2) Conversion time T_worst ≈ 2^N * Tclk.3) Increase N → N + 1 → T_worst(new) ≈ 2^(N+1) * Tclk.4) Therefore, T_worst(new) / T_worst(old) ≈ 2 → time doubles.


Verification / Alternative check:
Compare 8-bit vs 9-bit: 256 vs 512 counts in the worst case; time per conversion doubles at the same clock.


Why Other Options Are Wrong:
Tripling is unsupported by the code-count relationship. Decrease options contradict the monotonic increase of code count with more bits.


Common Pitfalls:
Confusing counter-type with SAR (which scales ~linearly with N comparisons, not exponentially with 2^N codes); forgetting clock-rate changes can mask the doubling if the system clocks faster.


Final Answer:
doubles

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