For a 6-input OR gate in combinational logic, identify the single input pattern that yields an output of 0 (logic low).
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A111111
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B000111
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C111000
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D000000
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ENone of the above
Answer
Correct Answer: 000000
Explanation
Introduction / Context:OR gates produce a logic 1 when any input is 1. The only time an OR gate outputs 0 is when every input is 0. This property generalizes regardless of the number of inputs (2, 4, 6, or more).
Given Data / Assumptions:
- The gate is an ideal 6-input OR.
- Binary inputs are either 0 or 1.
- No wired-logic or inversion is present.
Concept / Approach:The Boolean expression for an OR gate is Y = A + B + C + D + E + F. Y equals 0 only if A=B=C=D=E=F=0; any single 1 makes Y=1. This aligns with the inclusive definition of the OR operator.
Step-by-Step Solution:
Write the function: Y = A + B + C + D + E + F.Evaluate candidate words; if any bit is 1, Y becomes 1.Therefore, only 000000 produces Y=0.Verification / Alternative check:Truth tables for OR confirm a single 0-output row where all inputs are 0; all other rows output 1.
Why Other Options Are Wrong:
- 000111, 111000, 111111: each contains ones; the OR outputs 1.
- None of the above: incorrect because 000000 is correct.
Common Pitfalls:Confusing OR with NOR or assuming exclusive OR semantics; mixing up active-high vs active-low conventions.
Final Answer:000000