Convert the decimal number 67₁₀ to its octal representation (showing the correctly base-tagged form).

Difficulty: Easy

Correct Answer: 1038

Explanation:


Introduction / Context:
Base conversion is a staple skill in digital systems. Octal is convenient because each octal digit corresponds to three binary bits, providing a compact representation of binary values (especially in early microprocessor documentation and permissions in operating systems). Here we convert a base-10 integer to base 8.


Given Data / Assumptions:

  • Decimal input n = 67.
  • Target base = 8 (octal).
  • Output expressed with an explicit base tag 8.


Concept / Approach:

Use repeated division by the target base and collect remainders. For octal, divide by 8; the remainders (0–7) form digits from least to most significant when read in reverse order of computation. This algorithm mirrors positional weighting in base systems.


Step-by-Step Solution:

1) 67 / 8 = 8 remainder 3 → least significant octal digit = 3.2) 8 / 8 = 1 remainder 0 → next digit = 0.3) 1 / 8 = 0 remainder 1 → most significant digit = 1.4) Reading remainders backward gives 103, hence 1038.


Verification / Alternative check:

Decimal check: 18^2 + 08^1 + 3*8^0 = 64 + 0 + 3 = 67, confirming correctness.


Why Other Options Are Wrong:

1008 represents 64, not 67. 1098 exceeds digit range (digit 9 is invalid in octal). 998 is invalid (9 not allowed). 'None of the above' is wrong because 1038 is correct.


Common Pitfalls:

Forgetting to reverse the remainder order, or mistakenly using base 2/16 groupings instead of base 8 division.


Final Answer:

1038

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