Difficulty: Medium
Correct Answer: Either the output of FF0 or the input of FF1 may be shorted to ground.
Explanation:
Introduction / Context:
This question tests practical debugging of ripple or chained JK flip-flops. With J = K = 1, each JK device toggles on its clock edge. If the next stage's clock pin never sees transitions, that stage cannot toggle. Recognizing whether the issue is at the driving node (previous flip-flop output) or at the receiving node (next flip-flop clock input) is essential for rapid fault isolation.
Given Data / Assumptions:
Concept / Approach:
For FF1 to toggle, its clock input must receive transitions. If its clock node is stuck LOW while Q0 is known to toggle, there is likely a fault between Q0 and FF1.C. The two most probable hard faults are a short-to-ground at the driving node (FF0.Q0) or at the receiving node (FF1.C), either of which will clamp the signal line LOW and prevent edges from reaching FF1.
Step-by-Step Solution:
Verification / Alternative check:
An ohmmeter (with power off) often reveals a near-0 Ω path to ground on the affected node. Visual inspection for solder bridges or damaged vias also helps. Replacing the offending IC or repairing the short restores clock edges at FF1.C and Q1 toggling returns.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming a logic design error when the probe already shows a hardware-level short; overlooking that a stuck clock pin will prevent any downstream activity even with correct J–K settings.
Final Answer:
Either the output of FF0 or the input of FF1 may be shorted to ground.
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