Seven-segment display mapping For a standard seven-segment display (segments labeled a, b, c, d, e, f, g), which segments must be turned ON to display the decimal digit 6?
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Ab, c, d, e, f, and g
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Ba, c, d, e, f, and g
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Ca, b, c, d, and f
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Db, c, d, e, and f
Answer
Correct Answer: a, c, d, e, f, and g
Explanation
Introduction / Context:Seven-segment displays represent decimal digits by illuminating specific segments. Knowing which segments correspond to each digit is crucial when designing decoders (for example, BCD-to-7-segment) or when debugging display wiring and logic.
Given Data / Assumptions:
- Segments are labeled a through g, with the usual arrangement: a is top, b is upper-right, c is lower-right, d is bottom, e is lower-left, f is upper-left, g is middle.
- We assume a common, non-stylized font used in textbooks and IC datasheets.
Concept / Approach:The digit 6 typically lights every segment except b. It shows the top bar (a), both left bars (f, e), the middle bar (g), the bottom bar (d), and the lower-right bar (c). The upper-right bar (b) remains off to distinguish 6 from 8 and 0.
Step-by-Step Solution:
List the standard mappings: 0 → a b c d e f; 1 → b c; 2 → a b d e g; 3 → a b c d g; 4 → b c f g; 5 → a c d f g; 6 → a c d e f g; 7 → a b c; 8 → a b c d e f g; 9 → a b c d f g.From the mapping, digit 6 requires segments a, c, d, e, f, g.Verify visually: forms a closed loop on left side with both left segments lit and the top, middle, bottom, and lower-right segments lit.Confirm that b is OFF so the shape differs from 8 and 0.Verification / Alternative check:Consult any BCD-to-7-segment truth table (common-anode or common-cathode; the active level differs but the logical mapping is the same). Digit 6 has b = OFF in the standard glyph.
Why Other Options Are Wrong:
- b, c, d, e, f, g: Missing a (top bar), so not a 6.
- a, b, c, d, and f: Missing g and e, shape becomes closer to 9 or malformed.
- b, c, d, e, f: Missing a and g, does not create a 6.
Common Pitfalls:Confusing common-anode vs common-cathode wiring (active levels invert) and mislabeling segments, especially b and c.
Final Answer:a, c, d, e, f, and g