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A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :

Correct Answer: 12 days

Explanation:


(A + B)'s 1 day's work = 1 + 1 = 1 .
15 10 6



Work done by A and B in 2 days = 1 x 2 = 1 .
6 3



Remaining work = 1 - 1 = 2 .
3 3



Now, 1 work is done by A in 1 day.
15



2 work will be done by a in 15 x 2 = 10 days.
3 3


Hence, the total time taken = (10 + 2) = 12 days.


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