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A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:

Correct Answer: 25 days

Explanation:


(A + B)'s 1 day's work = 1
10



C's 1 day's work = 1
50



(A + B + C)'s 1 day's work = 1 + 1 = 6 = 3 . .... (i)
10 50 50 25


A's 1 day's work = (B + C)'s 1 day's work .... (ii)



From (i) and (ii), we get: 2 x (A's 1 day's work) = 3
25



⟹ A's 1 day's work = 3 .
50



∴ B's 1 day's work 1 - 3 = 2 = 1 .
10 50 50 25


So, B alone could do the work in 25 days.


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