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A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

Correct Answer: 15 days

Explanation:


A's 2 day's work = 1 x 2 = 1 .
20 10



(A + B + C)'s 1 day's work = 1 + 1 + 1 = 6 = 1 .
20 30 60 60 10



Work done in 3 days = 1 + 1 = 1 .
10 10 5



Now, 1 work is done in 3 days.
5


∴ Whole work will be done in (3 x 5) = 15 days.


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