Question 1

In this number pair reasoning question, four pairs are given where the second number is related to the first number. Select the odd pair that does not follow the same square pattern as the others.

Accepted Answer

Introduction / Context: This question tests recognition of patterns in number pairs. Each option shows a pair where the first number is linked to the second number by some rule. Your task is to identify which pair does not follow the same rule. Such pair based patterns often involve squares, cubes, or small arithmetic operations and are standard in quantitative aptitude and reasoning sections. Given Data / Assumptions: - The pairs given are 12 – 121, 14 – 169, 16 – 215, and 18 – 289.- The second number in each pair is close to the square of a number near the first value.- We assume a relationship involving perfect squares. Concept / Approach: One natural observation is that 121 is 11^2, 169 is 13^2, and 289 is 17^2. These are squares of odd numbers that are 1 less than the first number in each pair. To confirm, we test whether each second number is equal to the square of (first number minus 1). If three pairs follow this pattern and one does not, the non matching pair is the odd one out. Step-by-Step Solution: Step 1: For 12 – 121, compute (12 − 1)^2. This gives 11^2 = 121, which matches the second number.Step 2: For 14 – 169, compute (14 − 1)^2. This gives 13^2 = 169, again matching the second number.Step 3: For 18 – 289, compute (18 − 1)^2. This gives 17^2 = 289, which again matches the second number.Step 4: For 16 – 215, compute (16 − 1)^2. This gives 15^2 = 225, while the second number is 215, which does not match.Step 5: Thus, three pairs follow the rule second number = (first number − 1)^2, but one pair does not. Verification / Alternative check: Another quick check is to compare how far each second number is from the nearest perfect square. 121, 169, and 289 are themselves perfect squares. However, 215 lies between 14^2 = 196 and 15^2 = 225 and is not a perfect square, confirming that the relation breaks for this pair. Why Other Options Are Wrong: 12 – 121: Correctly follows second = (12 − 1)^2.14 – 169: Correctly follows second = (14 − 1)^2.18 – 289: Correctly follows second = (18 − 1)^2. Common Pitfalls: Some candidates try to relate the second number directly to the first by simple multiplication or addition and miss the square pattern. When numbers such as 121, 169, and 289 appear, it is a strong hint to think in terms of perfect squares. Final Answer: The odd pair is 16 – 215 because its second number is not equal to the square of one less than the first number, unlike the other three pairs.

Question 2

In this alphabet series reasoning question, select the odd group of letters from the given alternatives based on the backward step pattern between letters.

Accepted Answer

Introduction / Context: This non verbal reasoning question is based on patterns in groups of three letters. Each option contains three letters in a specific order. Your task is to identify which group does not follow the same alphabetic step pattern as the others. Such questions train candidates to work comfortably with forward and backward sequences in the English alphabet. Given Data / Assumptions: - The letter groups are HFD, SQO, ZXV, and BZU.- All letters belong to the English alphabet.- We will examine how the letters move from left to right in each group. Concept / Approach: A structured approach is to convert each letter into its alphabet position and then compute the difference between consecutive letters. If three groups show a constant pattern, such as a fixed step of minus 2 when moving backward through the alphabet, and one group does not, that non matching group is the odd one out. We apply this technique to all four groups. Step-by-Step Solution: Step 1: For HFD, positions are H = 8, F = 6, D = 4. Differences are minus 2 and minus 2, so the sequence moves backward by 2 each time.Step 2: For SQO, positions are S = 19, Q = 17, O = 15. Differences are minus 2 and minus 2 again, so it matches the same backward step pattern.Step 3: For ZXV, positions are Z = 26, X = 24, V = 22. Differences are minus 2 and minus 2, also fitting the pattern.Step 4: For BZU, positions are B = 2, Z = 26, U = 21. Differences are plus 24 and minus 5, which do not follow a constant backward step of minus 2.Step 5: Therefore, three groups show a uniform backward movement of minus 2, while BZU has irregular jumps. Verification / Alternative check: You can also observe that HFD, SQO, and ZXV can each be read as a simple backward run skipping one letter between each term. In contrast, BZU jumps from B to Z across almost the entire alphabet and then drops suddenly to U, which clearly breaks the pattern. Why Other Options Are Wrong: HFD: Regular backward sequence with step minus 2.SQO: Also a backward sequence with the same step.ZXV: Again follows the minus 2 backward pattern. Common Pitfalls: Some candidates check only whether the letters are moving backward and ignore the size of the jump. The size of the step is crucial here, because all three correct groups share both the direction and the step size. Final Answer: The odd letter group is BZU because it does not follow the constant backward minus 2 step pattern that the other groups follow.

Question 3

In the following question, four groups of three numbers are given. In each group, the second and third numbers are related to the first number by a simple arithmetic rule. Three groups follow the same pattern of equal differences, and one group brea…

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Introduction / Context: This is an aptitude question based on simple number patterns and arithmetic progressions. You are given several groups of three numbers, and in each group the second and third numbers are linked to the first by a clear rule. Your task is to identify which group does not follow the same pattern as the others. Such odd one out problems test observational skills and understanding of basic arithmetic sequences. Given Data / Assumptions: - Options are groups: (10, 12, 14), (12, 14, 16), (18, 20, 22), (24, 26, 30), and (30, 32, 34). - In each group there are exactly three numbers. - We assume that in most groups the numbers follow the same simple rule based on equal differences from term to term. - Exactly one group breaks this consistent pattern and is the odd one out. Concept / Approach: The most direct approach is to treat each group as a three term arithmetic progression. In an arithmetic progression, the difference between the first and second term is equal to the difference between the second and third term. If three groups show the same constant difference and one group shows a different structure, then that different group will be the required odd one out. Step-by-Step Solution: Step 1: For (10, 12, 14), the difference between 10 and 12 is +2, and between 12 and 14 is also +2.Step 2: For (12, 14, 16), the difference between 12 and 14 is +2, and between 14 and 16 is again +2.Step 3: For (18, 20, 22), the difference between 18 and 20 is +2, and between 20 and 22 is also +2.Step 4: For (30, 32, 34), the difference between 30 and 32 is +2, and between 32 and 34 is +2, so this group also forms an arithmetic progression with common difference 2.Step 5: For (24, 26, 30), the difference between 24 and 26 is +2, but between 26 and 30 it becomes +4, which breaks the equal difference pattern.Step 6: Therefore, (24, 26, 30) is not a proper three term arithmetic progression with common difference 2, and it is the odd group out. Verification / Alternative check: An alternative way is to write each group as first term plus a common difference. In four groups, the second term is first + 2 and the third term is first + 4. Only in the group (24, 26, 30) the third term is first + 6. This confirms that the pattern is broken only in this group, so the selection is correct. Why Other Options Are Wrong: (10, 12, 14), (12, 14, 16), (18, 20, 22), and (30, 32, 34) all have equal differences of +2 between consecutive terms. They are perfect examples of three term arithmetic progressions with common difference 2. Because they follow the same rule, these four groups cannot be considered odd ones out in this reasoning question. Common Pitfalls: Students sometimes look for complicated rules such as products or sums, when a simple difference pattern is enough. Another mistake is to check only the first two numbers and forget to check the difference between the second and third numbers. Always verify both gaps in each triple so that you do not accidentally select a correct progression as the odd one. Focusing on equal differences quickly reveals that (24, 26, 30) is the only inconsistent group. Final Answer: (24, 26, 30)

Question 4

In the following question, names of common plane figures are given. Three of them are specific types of quadrilaterals, while one is a general term that can have any number of sides. Select the figure which is different from the other three (odd one…

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Introduction / Context: This is a conceptual geometry question from aptitude that checks your understanding of basic plane figures. You are given several shape names and asked to identify which one does not belong to the same specific group. Recognising the difference between special quadrilaterals and a broad geometric category is useful for school mathematics as well as many competitive exams. Given Data / Assumptions: - The options are Square, Rectangle, Rhombus, Polygon, and Parallelogram. - Square, Rectangle, Rhombus, and Parallelogram are all specific types of quadrilaterals with four sides. - The term Polygon is a general word that refers to any closed figure made of straight line segments with three or more sides. - Exactly one option is not a specific quadrilateral type and will be the odd one out. Concept / Approach: The key idea is to classify each figure by the number of sides and by how specific the definition is. Quadrilaterals have exactly four sides. A Square is a special quadrilateral with all sides equal and all angles right angles. A Rectangle has opposite sides equal and all angles right angles. A Rhombus has all sides equal but angles need not be right angles. A Parallelogram has opposite sides parallel and equal. In contrast, Polygon is a very general term that describes any many sided figure, not just four sided ones, so it stands apart from the rest. Step-by-Step Solution: Step 1: A Square is a quadrilateral with four equal sides and four right angles.Step 2: A Rectangle is a quadrilateral with opposite sides equal and four right angles.Step 3: A Rhombus is a quadrilateral with all sides equal but angles are not fixed to 90 degrees.Step 4: A Parallelogram is a quadrilateral with opposite sides parallel and equal in length.Step 5: Polygon is any closed plane figure made from straight line segments with three or more sides; examples include triangles, pentagons, hexagons, and quadrilaterals.Step 6: Since Polygon is a broad category that includes many shapes and is not restricted to four sided figures, it is different from the other specific quadrilaterals. Verification / Alternative check: You can also visualise the hierarchy of figures. All Squares, Rectangles, Rhombuses, and Parallelograms are quadrilaterals, and at the same time all quadrilaterals are polygons. So four options are special cases within the polygon family, but only Polygon is the parent category. The parent category is more general and therefore naturally becomes the odd one out among its specific subtypes. Why Other Options Are Wrong: Square is not the odd one out because it is a clear, specific type of quadrilateral. Rectangle is also a specific quadrilateral with well defined properties. Rhombus and Parallelogram are again special quadrilaterals with four sides and distinct geometric definitions. Since these four names describe particular types of quadrilaterals, they form one group and cannot be treated as the odd term in this list. Common Pitfalls: Some learners confuse Polygon with Quadrilateral and think both are equally specific. However, a quadrilateral is a polygon with exactly four sides, whereas Polygon is more general and can have three, four, five, or more sides. Remembering this hierarchy is helpful when dealing with classification questions. Always check whether a word is a broad family name or a very specific member of that family. Final Answer: Polygon

Question 5

In the following question, each option shows a group of three letters. In three of the groups, the letters are arranged in a regular increasing alphabet pattern, while one group breaks this pattern. Select the odd group of letters from the given alt…

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Introduction / Context: This question belongs to the verbal reasoning and letter series category. You are given several triplets of English letters and asked to find which triplet does not follow the same alphabet pattern as the others. Questions of this type improve your ability to recognise regular sequences and build strong foundations for coding decoding, series, and analogy problems in competitive exams. Given Data / Assumptions: - Options are WYA, MNO, ACE, EGI, and DFH. - We use standard alphabet positions: A = 1, B = 2, ..., Z = 26. - In most groups the letters move forward in the alphabet with a fixed step between consecutive letters. - Exactly one group breaks the rule of smooth forward progression and will be the odd one out. Concept / Approach: The main idea is to calculate the difference in alphabet positions between successive letters in each triplet. For a regular pattern, the difference between the first and second letter should be constant, and the same difference should appear between the second and third letter. By comparing these differences across all options, we can see which group does not follow the same structure as the rest. Step-by-Step Solution: Step 1: For MNO, positions are M = 13, N = 14, O = 15, so differences are +1 and +1. It is a simple sequence of three consecutive letters.Step 2: For ACE, positions are A = 1, C = 3, E = 5, so differences are +2 and +2, a regular step of 2.Step 3: For EGI, positions are E = 5, G = 7, I = 9, giving +2 and +2 again, so EGI follows the same style of regular forward jumps.Step 4: For DFH, positions are D = 4, F = 6, H = 8, again giving +2 and +2, so this triplet is also in a regular increasing pattern.Step 5: For WYA, positions are W = 23, Y = 25, A = 1. The difference from W to Y is +2, but from Y to A requires wrapping around the alphabet and effectively moves backward from 25 to 1.Step 6: Because WYA does not show a smooth, regular forward movement of letters, it breaks the pattern followed by the other groups and is the odd one out. Verification / Alternative check: You can also verify by reading the sequences mentally. MNO is clearly a run of three consecutive letters. ACE, EGI, and DFH are all evenly spaced forward sequences. WYA, however, feels irregular because after W and Y the sequence unexpectedly jumps to A at the beginning of the alphabet, which is quite different from the others. This confirms that WYA is different in behaviour and should be selected as the odd group. Why Other Options Are Wrong: MNO, ACE, EGI, and DFH are all examples of increasing sequences that move smoothly forward in the alphabet using a small fixed step. They all follow a regular and predictable pattern, which makes them similar. Because they obey the same general rule, none of them can be considered the odd one out in this question. Common Pitfalls: Sometimes students overcomplicate these questions by searching for hidden coding schemes when a simple difference pattern is enough. Another common mistake is to ignore wrap around behaviour at Z and A, which is what makes WYA irregular. Always check whether the letters in a group move forward consistently and compare that behaviour across all options. This habit will help you quickly solve many letter based odd one out questions. Final Answer: WYA

Question 6

In the following question, four numbers are given. Three of them have a digit sum equal to 9, while one number has a different digit sum. Select the number whose digit sum is not equal to 9 (odd number out).

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Introduction / Context: This is a number based reasoning question that uses the idea of digit sums. In many aptitude problems, examiners hide patterns in the sum of digits of numbers rather than in the numbers themselves. Here, three numbers share a common digit sum and one does not. Your task is to detect this hidden rule and identify the number that breaks it. Given Data / Assumptions: - The options are 243, 264, 333, 405, and 522. - The digit sum of a number is obtained by adding all its digits together. - In most options, the digit sum equals 9. - Exactly one number has a digit sum different from 9, making it the odd one out. Concept / Approach: The main approach is to compute the sum of digits for each number and then compare the results. Digit sum is a useful tool because it often reveals divisibility by 3 or 9 and can show hidden regularities across several numbers. Once you know the common digit sum, you can quickly spot which number does not fit this pattern. Step-by-Step Solution: Step 1: For 243, digit sum is 2 + 4 + 3 = 9.Step 2: For 333, digit sum is 3 + 3 + 3 = 9.Step 3: For 405, digit sum is 4 + 0 + 5 = 9.Step 4: For 522, digit sum is 5 + 2 + 2 = 9.Step 5: For 264, digit sum is 2 + 6 + 4 = 12, which is not equal to 9.Step 6: Since all numbers except 264 have digit sum 9, 264 is the only one that breaks the pattern. Verification / Alternative check: Digit sum 9 also implies divisibility by 9. So 243, 333, 405, and 522 are all divisible by 9. Checking 264, we see that 264 divided by 9 does not give an integer, because 9 * 29 = 261 and 9 * 30 = 270. The remainder confirms that 264 is not a multiple of 9. This alternative view supports our earlier conclusion that 264 is the odd one out based on the digit sum rule. Why Other Options Are Wrong: 243, 333, 405, and 522 all share the common property that their digits add up to 9. This automatically links them through the same divisibility rule. Because they follow the same pattern, these four numbers belong to one group and cannot be selected as the odd number in this question. Common Pitfalls: A common mistake is to look for more complicated algebraic relationships between the numbers instead of starting with simple checks like digit sums and divisibility. Another error is miscalculating the sums under exam pressure. Practising digit sum operations improves speed and accuracy, which helps in many other questions involving divisibility by 3 and 9 as well. Final Answer: 264

Question 7

In the following question, four three digit numbers are given. Three of these numbers are not divisible by 3, while one number is divisible by 3. Select the number which is divisible by 3 (odd number out).

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Introduction / Context: This is a basic number theory question from aptitude that focuses on divisibility by 3. You are given several three digit numbers and asked to identify which one behaves differently from the others. The key is to use the well known rule for divisibility by 3, which allows you to answer very quickly once you practice it. Given Data / Assumptions: - The options are 369, 257, 346, 628, and 517. - We recall that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. - Exactly one number in the list is a multiple of 3, while the others are not. - That single multiple of 3 will be the odd one out. Concept / Approach: Instead of performing full division, the most efficient approach is to apply the digit sum test. This test is a standard technique for recognising multiples of 3 and 9. By summing the digits of each number and checking whether the sum is divisible by 3, we can quickly classify each option and identify the special number that does not match the rest. Step-by-Step Solution: Step 1: For 369, digit sum is 3 + 6 + 9 = 18, which is divisible by 3.Step 2: For 257, digit sum is 2 + 5 + 7 = 14, which is not divisible by 3.Step 3: For 346, digit sum is 3 + 4 + 6 = 13, which is not divisible by 3.Step 4: For 628, digit sum is 6 + 2 + 8 = 16, which is not divisible by 3.Step 5: For 517, digit sum is 5 + 1 + 7 = 13, which is also not divisible by 3.Step 6: Therefore, 369 is the only number whose digit sum is divisible by 3, so 369 is the only multiple of 3 in the list and is the odd number out. Verification / Alternative check: We can also verify directly by dividing 369 by 3. We obtain 369 / 3 = 123 exactly, confirming that it is divisible by 3. For the other numbers, quick mental checks show that no exact integer quotient results when dividing by 3, because their digit sums are not multiples of 3. This alternative check supports our conclusion that 369 is special among the given numbers. Why Other Options Are Wrong: 257, 346, 628, and 517 all have digit sums that are not multiples of 3. This means they are not divisible by 3 and are consistent with each other. Because they share the same divisibility property, these four numbers form one group and cannot be treated as the odd one out in this question. Common Pitfalls: Some learners forget to use the digit sum rule and attempt to perform time consuming long division for each number. Others may miscalculate the sums, especially when working quickly under exam conditions. Training yourself to apply digit sum rules accurately and efficiently will save time across the entire quantitative section of an exam and reduce the chance of silly mistakes. Final Answer: 369

Question 8

In the following question, names of animals are given. Three of them are large wild cats, while one is a large bird that cannot fly. Select the animal which is different from the other three (odd one out).

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Introduction / Context: This is a simple general knowledge and classification question about animals. The examiner gives you a list of animal names and asks you to identify which one does not belong to the same broad group as the others. Such questions test your basic awareness of animal types and their main characteristics, which is often covered in school level biology and GK sections of competitive exams. Given Data / Assumptions: - The options are Tiger, Ostrich, Lion, Cheetah, and Leopard. - Tiger, Lion, Cheetah, and Leopard are all big cats and carnivorous mammals belonging to the family Felidae. - Ostrich is a large bird that cannot fly and belongs to a completely different class of animals (Aves). - Exactly one animal is not a big cat, and that animal is the odd one out. Concept / Approach: The easiest way to approach this question is to classify each animal by broad type: mammal versus bird and then further by family. The big cats share many common features such as sharp claws, strong jaws, and a carnivorous diet. Ostrich, on the other hand, is a flightless bird with feathers and a very different body structure. The animal that does not fit the big cat group will be the one that you must select as different. Step-by-Step Solution: Step 1: Tiger is a large carnivorous mammal and a classic example of a big cat.Step 2: Lion is also a big cat, known for living in prides and having a mane in the case of male lions.Step 3: Cheetah is another big cat, famous for its extraordinary running speed and spotted coat.Step 4: Leopard is again a big cat, known for its rosette patterned spots and climbing ability.Step 5: Ostrich, however, is a very large bird that cannot fly. It has feathers, lays eggs, and belongs to a different biological class.Step 6: Thus, Ostrich is the only non feline animal among the options and is the odd one out. Verification / Alternative check: You can verify your reasoning by thinking about their habitats, feeding behaviour, and physical structure. Tiger, Lion, Cheetah, and Leopard are predators with similar body shapes and hunting habits. Ostrich, on the other hand, has a long neck, long legs, and uses speed for running rather than for hunting like a cat. It feeds mainly on plants and small creatures and has completely different anatomy, which confirms that it belongs to a different group. Why Other Options Are Wrong: Tiger, Lion, Cheetah, and Leopard all belong to the big cat family and are classified as large carnivorous mammals. They share many common traits and are often studied together in zoology and GK. Because they form a natural group, none of them can be considered the odd one out when compared with a bird like Ostrich. Common Pitfalls: Sometimes candidates focus on secondary details such as speed or habitat and may temporarily be confused between Cheetah and the others. However, for odd one out questions at this level, examiners typically use broad and clear categories like birds versus mammals or domestic versus wild. When you focus on fundamental classifications, the correct answer becomes obvious and quick to identify. Final Answer: Ostrich

Question 9

In the following question, four number pairs are given. In each pair, the number on the right side is related to the number on the left side by a simple addition rule. Three pairs show the same increase of 1, while one pair shows a different increas…

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Introduction / Context: This is a basic number reasoning question involving simple differences between pairs of numbers. You are given several number pairs where each right hand number is obtained from the left hand number using a rule. In such odd one out questions, most pairs follow a common rule and one pair breaks it. Recognising this difference is important for mastering number relationships and series questions in aptitude tests. Given Data / Assumptions: - The options are 11 – 12, 13 – 14, 17 – 18, 19 – 21, and 21 – 22. - In most pairs, the right number is obtained by adding 1 to the left number. - Exactly one pair does not follow the pattern of a difference equal to 1 between the two numbers. Concept / Approach: The approach is straightforward. For each pair, subtract the left number from the right number and note the difference. If most pairs have a difference of 1 and one pair has a different difference, that different pair will be the odd one out. This type of pattern is common in elementary number series and can be solved very quickly once you are comfortable with simple subtraction. Step-by-Step Solution: Step 1: For 11 – 12, difference is 12 - 11 = 1.Step 2: For 13 – 14, difference is 14 - 13 = 1.Step 3: For 17 – 18, difference is 18 - 17 = 1.Step 4: For 21 – 22, difference is 22 - 21 = 1.Step 5: For 19 – 21, difference is 21 - 19 = 2, which is not equal to 1.Step 6: Since only the pair 19 – 21 shows an increase of 2 rather than 1, it breaks the common rule and is the odd one out. Verification / Alternative check: You can also look at these as mini sequences of consecutive integers. 11, 12 and 13, 14 and 17, 18 and 21, 22 are all consecutive numbers. However, 19, 21 are not consecutive because 20 is missing between them. This gap of 2 confirms that 19 – 21 behaves differently from the other pairs, which all maintain a gap of 1. Why Other Options Are Wrong: The pairs 11 – 12, 13 – 14, 17 – 18, and 21 – 22 all share the property that the second number is exactly one more than the first number. They represent successive integers with no number skipped in between. Since they follow the same simple rule, these four pairs form the main pattern and therefore cannot be selected as the odd pair. Common Pitfalls: Because the numbers are small and close to each other, some students may read quickly and overlook the two step jump in 19 – 21. Another potential mistake is to search for complex multiplication or factor relationships when a simple difference check is sufficient. In exam conditions, always start with the simplest possible pattern such as addition or subtraction before considering more complex rules. Final Answer: 19 – 21

Question 10

In the following question, groups of three letters are given. Three of these groups have letters with a fixed gap of 2 between consecutive letters in the alphabet, while one group has consecutive letters with a gap of 1. Select the odd group of lett…

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Introduction / Context: This question is from the letter series and alphabetical reasoning part of aptitude. You are given several triplets of letters and asked to find which one does not follow the same spacing rule as the others. Such questions are very common and help train you to notice regular steps and patterns in the alphabet, which are later used in coding decoding and sequence based problems. Given Data / Assumptions: - The options are JKL, EGI, OQS, KMO, and BDF. - We use positions A = 1, B = 2, ..., Z = 26. - In most groups, the difference between consecutive letters is +2, that is, there is one letter between them in the alphabet. Concept / Approach: The method is to convert each letter to its numerical position and compute the difference between the first and second letters and between the second and third letters. For a regular pattern, these differences should be equal and match across multiple options. The group which has a different spacing, such as consecutive letters with a gap of 1, will be the odd one out. Step-by-Step Solution: Step 1: For EGI, positions are E = 5, G = 7, I = 9. Differences are 7 - 5 = 2 and 9 - 7 = 2, so this group follows a +2, +2 pattern.Step 2: For OQS, positions are O = 15, Q = 17, S = 19. Differences are again +2 and +2, so OQS also follows the same pattern.Step 3: For KMO, positions are K = 11, M = 13, O = 15. Differences are 13 - 11 = 2 and 15 - 13 = 2, so KMO fits the +2, +2 rule.Step 4: For BDF, positions are B = 2, D = 4, F = 6. Differences are 4 - 2 = 2 and 6 - 4 = 2, so BDF also follows the same gap of 2.Step 5: For JKL, positions are J = 10, K = 11, L = 12. Here the differences are 11 - 10 = 1 and 12 - 11 = 1, so the letters are consecutive with gap 1, not 2.Step 6: Therefore, JKL is the only triplet that does not have a constant gap of 2 between letters and is the odd one out. Verification / Alternative check: You can read the sequences aloud to sense the rhythm. E, G, I; O, Q, S; K, M, O; and B, D, F all sound like letters with one letter skipped between each step. J, K, L feels different because the letters are immediate neighbours with no letter skipped. This difference in rhythm confirms that JKL is the group that does not match the spacing pattern of the others. Why Other Options Are Wrong: EGI, OQS, KMO, and BDF all share the exact same structure, where each letter is followed by another letter that is two positions ahead in the alphabet. Because they all follow the +2, +2 rule, they belong to the same family of patterns. None of them can be considered odd when compared with a triplet like JKL that uses a completely different spacing. Common Pitfalls: Students sometimes focus only on whether letters are increasing and ignore the exact step size. As a result, they may wrongly treat JKL as similar to the others. To avoid this, always check the numeric difference between letters and compare that difference across options. This small habit dramatically improves accuracy in letter series and coding questions. Final Answer: JKL

Question 11

In the following question, four groups of three numbers are given. In each group the second and third numbers are related to the first number by multiplication. In most groups, the second number is twice the first and the third number is three times…

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Introduction / Context: This is a numerical reasoning question involving simple multiples and proportional relationships. Each option contains three numbers, and the second and third numbers are generated from the first using some multiplication rule. Such questions test your ability to detect how numbers are scaled and to spot the one group that does not follow the same multiplication pattern as the others. Given Data / Assumptions: - The options are (5, 10, 15), (7, 14, 21), (6, 12, 18), (8, 16, 28), and (9, 18, 27). - In most groups, the second number is 2 times the first number and the third number is 3 times the first number. - Exactly one group does not obey this 2 times and 3 times rule and must be chosen as the odd one out. Concept / Approach: The method is to take the first number of each group and check whether the second and third numbers can be written as multiples of that first number with factors 2 and 3 respectively. When a group fits the pattern first, 2 times first, 3 times first, it follows the rule. When it does not, it breaks the pattern. This simple form of proportional reasoning is very common in aptitude tests. Step-by-Step Solution: Step 1: For (5, 10, 15), the second number is 2 * 5 = 10, and the third number is 3 * 5 = 15, so the pattern holds.Step 2: For (7, 14, 21), the second number is 2 * 7 = 14, and the third number is 3 * 7 = 21, so this group also fits the same rule.Step 3: For (6, 12, 18), we have 2 * 6 = 12 and 3 * 6 = 18, so this group continues the same pattern.Step 4: For (9, 18, 27), we have 2 * 9 = 18 and 3 * 9 = 27, so this group fits the rule as well.Step 5: For (8, 16, 28), the second number is 2 * 8 = 16, but the third number should be 3 * 8 = 24 to follow the rule, whereas the given number is 28.Step 6: Since only the third number in the group (8, 16, 28) does not equal 3 times the first number, this group breaks the pattern and is the odd one out. Verification / Alternative check: We can also think in terms of ratios. In four groups, the ratios of the three numbers are 1 : 2 : 3. In the group (8, 16, 28), the ratios simplify to 8 : 16 : 28, which is 1 : 2 : 3.5 after dividing all terms by 8. The presence of 3.5 instead of 3 makes this group inconsistent with the simple integer multiple pattern of the others. Why Other Options Are Wrong: The groups (5, 10, 15), (7, 14, 21), (6, 12, 18), and (9, 18, 27) all satisfy the mapping first number, twice first, and thrice first. Because they share this exact structure, they belong to one family of patterns. None of these groups can be considered the odd one out when compared with a group like (8, 16, 28) that does not match the expected ratios. Common Pitfalls: Under time pressure, some students may focus only on whether the second number is twice the first and forget to verify the third number. Others may miscalculate 3 times the first number in their head. To avoid these errors, always check both second and third numbers systematically. Building this careful habit will help you solve many proportional reasoning and number pattern questions accurately. Final Answer: (8, 16, 28)

Question 12

In the following question, names of Indian cities are given. Three of these cities are important seaports located on the coast of India, while one city is an inland state capital that is not a major seaport. Select the city which is different from t…

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Introduction / Context: This general knowledge question focuses on Indian geography and important port cities. You are asked to distinguish between coastal seaport cities and an inland city. This type of odd one out question tests awareness of major locations in India, especially those relevant to trade, transport, and economic activity. Given Data / Assumptions: - The options are Vishakhapatnam, Mumbai, Kochi, Bhubaneshwar, and Chennai. - Vishakhapatnam, Mumbai, Kochi, and Chennai are significant coastal cities with major seaports used for maritime trade. - Bhubaneshwar is the capital of Odisha and is located inland, not directly on the seacoast as a primary port city. - Exactly one city is not a major seaport, and that city is the odd one out. Concept / Approach: The key idea is to classify each city by whether it has a major sea harbour and lies on the coastline. Port cities play a crucial role in import and export activities, whereas inland capitals may have administrative importance but not seaport facilities. By remembering which cities are frequently mentioned as ports in school geography and current affairs, we can quickly identify which city in the list does not fit the seaport category. Step-by-Step Solution: Step 1: Mumbai is India's leading western coastal metropolis and has one of the busiest ports in the country.Step 2: Kochi is a well known seaport on the south west coast of India in the state of Kerala.Step 3: Vishakhapatnam is a major port city on the eastern coast of India, located in Andhra Pradesh.Step 4: Chennai is an important eastern coastal city in Tamil Nadu with a major seaport.Step 5: Bhubaneshwar, however, is an inland city and the capital of Odisha. It is not itself the main sea harbour of the state; that role is taken by port towns such as Paradip.Step 6: Therefore, Bhubaneshwar is the only city in the list that is not a major seaport city on the coast and is the odd one out. Verification / Alternative check: You can verify by recalling maps or common news references. Mumbai, Kochi, Vishakhapatnam, and Chennai are all frequently mentioned in the context of shipping, navy bases, and maritime trade. Bhubaneshwar is instead known for temples, administration, education, and its role as a political capital of Odisha. It is not typically associated with sea harbours in textbooks or current affairs, which confirms that it stands apart from the port cities. Why Other Options Are Wrong: Vishakhapatnam, Mumbai, Kochi, and Chennai all qualify as major seaport cities. They have coastal locations and extensive port infrastructure. Because these four share the common feature of being maritime gateways, they form a natural group. None of them can be considered the odd one out when compared with an inland capital like Bhubaneshwar. Common Pitfalls: Some students may misremember geographic locations or confuse nearby coastal and inland cities. For example, they may mistakenly think that any large city in a coastal state must be a port. To avoid such errors, it is useful to memorise the names of a few key ports on each coast. When you know which cities are primary harbours, identifying the odd inland city in such questions becomes quick and reliable. Final Answer: Bhubaneshwar

Question 13

In the following question, each option shows a group of three lowercase letters. In three groups, the pattern of letters is vowel–consonant–vowel, while in one group the last letter is a consonant. Select the group which does not follow the vowel–co…

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Introduction / Context: This question belongs to the verbal reasoning category and deals with simple letter patterns. Instead of focusing on alphabetical positions, it uses the classification of letters into vowels and consonants. You are asked to identify which three letter group does not follow the same vowel–consonant–vowel structure as the others. Such pattern recognition is common in odd one out and series questions in aptitude exams. Given Data / Assumptions: - The options are eno, iqa, ubu, olr, and afa. - The English vowels are a, e, i, o, u, and all other English letters are consonants. - In most groups, the first and third letters are vowels, while the middle letter is a consonant, giving a vowel–consonant–vowel structure. - Exactly one group does not follow this vowel–consonant–vowel pattern and is the odd one out. Concept / Approach: The straightforward method is to classify each letter in every group as a vowel or a consonant and then note the pattern. A group that follows vowel–consonant–vowel will look like V–C–V. The group that breaks this structure will show a different pattern such as vowel–consonant–consonant. Once the patterns are written out clearly, it becomes easy to identify which group is different from the others. Step-by-Step Solution: Step 1: For eno, letters are e, n, o. Here e is a vowel, n is a consonant, and o is a vowel. Pattern is V–C–V.Step 2: For iqa, letters are i, q, a. Here i is a vowel, q is a consonant, and a is a vowel. Pattern is V–C–V.Step 3: For ubu, letters are u, b, u. Here u is a vowel, b is a consonant, and u is a vowel. Pattern is again V–C–V.Step 4: For afa, letters are a, f, a. Here a is a vowel, f is a consonant, and a is a vowel. Pattern is V–C–V.Step 5: For olr, letters are o, l, r. Here o is a vowel, but both l and r are consonants. Pattern is V–C–C, not V–C–V.Step 6: Therefore, olr is the only group that does not end with a vowel and breaks the vowel–consonant–vowel pattern, making it the odd one out. Verification / Alternative check: Another way to check is to focus first on the last letter of each group. In eno, iqa, ubu, and afa, the last letter is a vowel. In olr, the last letter r is a consonant. Since the first four groups share the pattern vowel at the beginning and vowel at the end, while olr does not, this confirms that olr stands apart from the rest. Why Other Options Are Wrong: eno, iqa, ubu, and afa each have the first and last letters as vowels and the middle letter as a consonant. This consistent V–C–V pattern joins them together as one family of letter groups. Because they follow the same structure, none of these four can be considered the odd one out in this question. Common Pitfalls: Students sometimes rush and misclassify letters, especially if they are not comfortable with vowels and consonants. Another mistake is to look for complex alphabetic differences when a simple vowel consonant classification is enough. To improve accuracy, always take a second to mark V or C under each letter when dealing with such pattern questions. This small step reduces confusion and quickly reveals the odd element. Final Answer: olr

Question 14

In the following question, four four digit numbers are given. In three of these numbers, the sum of the digits is a multiple of 9, while in one number the sum of the digits is not a multiple of 9. Select the number whose digit sum is not divisible b…

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Introduction / Context: This number reasoning question uses the concept of digit sums and divisibility by 9. You are asked to find which four digit number behaves differently from the others when you apply the rule for multiples of 9. This type of question is common in aptitude tests because it checks whether you know and can quickly apply divisibility rules without long division. Given Data / Assumptions: - The options are 2691, 9900, 5632, 2790, and 4509. - For divisibility by 9, a number is a multiple of 9 if the sum of its digits is a multiple of 9. - In most options, the sum of the digits equals 18, which is a multiple of 9. - Exactly one option has a digit sum that is not a multiple of 9, making it the odd one out. Concept / Approach: The approach is to calculate the digit sum for each four digit number and then check whether that sum is divisible by 9. When the digit sum is 9, 18, 27, or any other multiple of 9, the original number is divisible by 9. The single number that does not satisfy this condition will be the answer. This simple procedure is much faster than performing full division for each option. Step-by-Step Solution: Step 1: For 2691, digit sum is 2 + 6 + 9 + 1 = 18, which is divisible by 9.Step 2: For 9900, digit sum is 9 + 9 + 0 + 0 = 18, again divisible by 9.Step 3: For 2790, digit sum is 2 + 7 + 9 + 0 = 18, also a multiple of 9.Step 4: For 4509, digit sum is 4 + 5 + 0 + 9 = 18, again a multiple of 9.Step 5: For 5632, digit sum is 5 + 6 + 3 + 2 = 16, which is not divisible by 9.Step 6: Therefore, 5632 is the only number whose digit sum is not a multiple of 9 and is the odd one out. Verification / Alternative check: We can quickly cross check by division. 2691, 9900, 2790, and 4509 are all divisible by 9, because their digit sums are 18. For example, 2790 divided by 9 is 310. For 5632, dividing by 9 will not produce an integer. The remainder in such an attempt confirms that 5632 is not a multiple of 9, matching the conclusion from the digit sum method. Why Other Options Are Wrong: 2691, 9900, 2790, and 4509 all share the same property that their digits sum to 18. This links them through the divisibility rule for 9 and places them in the same category of numbers. Because they match on the key property being tested, none of these four can be considered the odd number out. Common Pitfalls: Students sometimes miscalculate digit sums when working quickly, for example adding 2 + 6 + 9 + 1 incorrectly. Another common error is to confuse the rules for divisibility by 3 and 9, although both use digit sums. To avoid these mistakes, practise computing digit sums carefully and remember that for 9, the sum itself must be a multiple of 9. This greatly simplifies many questions involving large numbers. Final Answer: 5632

Question 15

In the following question, four three digit numbers are given. In three of these numbers, the value is a multiple of 12, while one number is not a multiple of 12. Select the number which is not divisible by 12 (odd number out).

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Introduction / Context: This numerical reasoning question focuses on identifying multiples of 12. You are given several three digit numbers and must find which one is not divisible by 12. Such questions improve your familiarity with divisibility tests and common multiples and are often seen in quantitative aptitude sections. Given Data / Assumptions: - The options are 308, 108, 288, 240, and 156. - A number is divisible by 12 if it is divisible by both 3 and 4, since 12 = 3 * 4. - In most options, the numbers are clean multiples of 12. - Exactly one number is not a multiple of 12 and must be selected as the odd one out. Concept / Approach: The efficient way to approach this is to use divisibility rules for 3 and 4. A number is divisible by 3 if its digit sum is divisible by 3. A number is divisible by 4 if the last two digits form a number that is divisible by 4. If both conditions hold, the number is divisible by 12. Applying these checks to each option is much faster than performing full division for all numbers. Step-by-Step Solution: Step 1: Check 108. Digit sum is 1 + 0 + 8 = 9, divisible by 3. Last two digits 08 form 8, which is divisible by 4. So 108 is divisible by 12.Step 2: Check 288. Digit sum is 2 + 8 + 8 = 18, divisible by 3. Last two digits 88 give 88, which is divisible by 4 (since 4 * 22 = 88). So 288 is a multiple of 12.Step 3: Check 240. Digit sum is 2 + 4 + 0 = 6, divisible by 3. Last two digits 40 form 40, which is divisible by 4. So 240 is also a multiple of 12.Step 4: Check 156. Digit sum is 1 + 5 + 6 = 12, divisible by 3. Last two digits 56 form 56, which is divisible by 4. So 156 is a multiple of 12.Step 5: Check 308. Digit sum is 3 + 0 + 8 = 11, which is not divisible by 3, so 308 is not divisible by 3.Step 6: Since 308 fails the divisibility by 3 test, it cannot be divisible by 12, and therefore it is the only non multiple of 12 in the list. Verification / Alternative check: As a verification, you can perform quick mental division. 108, 288, 240, and 156 are all familiar multiples of 12 from tables, such as 12 * 9 = 108 and 12 * 13 = 156. For 308, trying 12 * 25 = 300 and 12 * 26 = 312 shows that 308 is between these multiples and not equal to any. Thus, 308 is not divisible by 12, confirming our result from the divisibility rule method. Why Other Options Are Wrong: 108, 288, 240, and 156 all pass both divisibility tests for 3 and 4 and are therefore multiples of 12. Because they share the same property, they form one consistent group. None of them can be considered the odd one out when compared with 308, which clearly fails the 12 multiple criteria. Common Pitfalls: Students often forget that 12 requires divisibility by both 3 and 4, not just one of them. Another common error is to miscalculate digit sums or to check only one of the conditions. By systematically applying both tests and double checking arithmetic, you can avoid these mistakes and handle similar questions with confidence. Final Answer: 308

Question 16

In the following question, scientific terms related to the Earth are given. Three of them are names of different spheres of the Earth's environment, while one refers to an internal layer. Select the term which is different from the other three (odd …

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Introduction / Context: This general science and geography question tests your understanding of the structure of the Earth and its environmental layers. You are given scientific terms, some of which describe the outer spheres where life, land, and water exist, while one term describes an internal layer of the Earth. Recognising this distinction is important for school level geography and many competitive exams that include Earth science topics. Given Data / Assumptions: - The options are Lithosphere, Hydrosphere, Biosphere, Mantle, and Atmosphere. - Lithosphere, Hydrosphere, Biosphere, and Atmosphere are commonly described as spheres that form parts of the Earth's environment at or near the surface. - Mantle is an internal layer of the Earth located below the crust and above the core, not part of the external environmental spheres. - Exactly one term refers to the internal structure rather than an external sphere and is therefore the odd one out. Concept / Approach: The idea is to distinguish between environmental spheres that describe where land, water, air, and life occur and the internal layers that describe the Earth's physical structure. Spheres like Lithosphere and Hydrosphere are conceptual regions that cover certain kinds of matter or activity. The Mantle, however, is a solid or semi molten layer inside the Earth, not a sphere of interaction on the surface. Identifying that difference helps you choose the correct odd term. Step-by-Step Solution: Step 1: Lithosphere refers to the rigid outer shell of the Earth, including the crust and uppermost mantle, and is often discussed as the rocky sphere.Step 2: Hydrosphere covers all the water on Earth, including oceans, rivers, lakes, and groundwater, and is known as the water sphere.Step 3: Biosphere is the sphere where life exists, including all living organisms and their interactions with land, water, and air.Step 4: Atmosphere is the envelope of gases surrounding the Earth, forming the air sphere.Step 5: Mantle is the layer of hot rock between the Earth's crust and core; it is part of the internal structure and not described as a sphere like the others.Step 6: Since Mantle describes an internal layer and the other terms describe external spheres, Mantle is the odd one out. Verification / Alternative check: Textbooks usually group Lithosphere, Hydrosphere, Biosphere, and Atmosphere together when discussing the environment and the conditions necessary for life. Mantle appears in chapters that describe the internal layers of the Earth. Because Mantle is never grouped with the environmental spheres in this way, it clearly belongs to a different classification, confirming that it is the term that does not belong with the others. Why Other Options Are Wrong: Lithosphere, Hydrosphere, Biosphere, and Atmosphere are all conceptual spheres that help explain different aspects of the Earth's environment. They interact at the surface and near surface levels and are commonly used together when describing ecological and environmental systems. Since they share this role, none of them can be treated as the odd one in this list. Common Pitfalls: Some learners may confuse Lithosphere with Mantle because both involve solid rock. However, Lithosphere is considered an outer shell, while Mantle is a deeper internal layer. To avoid confusion, always keep in mind that the environmental spheres (bio, hydro, atmo, litho) describe where life and processes occur at or near the surface, whereas Mantle and core refer to the internal structure of the planet. Final Answer: Mantle

Question 17

In the following question, pairs of letters are given. In three of these pairs, the second letter is immediately before the first letter in the alphabet, while in one pair the gap between the two letters is larger. Select the pair which does not sho…

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Introduction / Context: This question belongs to the letter series and coding decoding type of reasoning. You are given pairs of letters and asked to determine which pair does not display the same relationship between its letters. The focus is on whether the second letter is just one step before the first letter in the alphabet or separated by a larger gap. Identifying such patterns is useful for many alphabet based reasoning problems. Given Data / Assumptions: - The options are WT, SR, ED, KJ, and QP. - We use the standard English alphabet positions A = 1, B = 2, ..., Z = 26. - In most pairs, the second letter is the immediate predecessor of the first letter (difference of 1 in reverse order). - Exactly one pair has a larger gap, and that pair is the odd one out. Concept / Approach: The approach is to calculate the numerical difference between the positions of the letters in each pair. If the first letter has position x and the second letter has position y, then for consecutive letters in reverse order we should have x - y = 1. The pair where the difference is not equal to 1 will be the odd one. This is a straightforward application of alphabet positions and differences. Step-by-Step Solution: Step 1: For SR, S is position 19 and R is position 18. Difference is 19 - 18 = 1, so R is immediately before S.Step 2: For ED, E is position 5 and D is position 4. Difference is 5 - 4 = 1, so D is immediately before E.Step 3: For KJ, K is position 11 and J is position 10. Difference is 11 - 10 = 1, so J is immediately before K.Step 4: For QP, Q is position 17 and P is position 16. Difference is 17 - 16 = 1, so P is immediately before Q.Step 5: For WT, W is position 23 and T is position 20. Difference is 23 - 20 = 3, so T is three letters before W rather than just one.Step 6: Since only WT has a gap of 3 instead of 1, WT does not represent consecutive letters in reverse order and is the odd pair out. Verification / Alternative check: You can verify quickly by writing the alphabet from A to Z and marking the pairs. For S and R, E and D, K and J, and Q and P, the letters stand next to each other in reverse order. For W and T, however, there are letters U and V between them, showing that they are not consecutive. This visual check confirms that WT is different from the other pairs. Why Other Options Are Wrong: SR, ED, KJ, and QP all show a simple reverse consecutive relation: the second letter comes immediately before the first in the alphabet. Because they share this identical structure, these four pairs form a consistent pattern. None of them can be selected as the odd one out when compared with WT, which has a larger gap. Common Pitfalls: Many students do not explicitly calculate alphabet positions and rely only on mental pictures of the alphabet, which can cause them to miss small differences. Another pitfall is to focus only on the fact that all pairs are in reverse order, without checking whether they are immediately consecutive. To avoid such mistakes, always count the number of letters between the two characters when dealing with letter pair questions. Final Answer: WT

Question 18

In this aptitude question, you are asked to find the odd number from the following set of alternatives, where three of the numbers are perfect cubes and one number does not follow that perfect cube pattern: 27, 8, 64 and 124.

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Introduction / Context: This question is a classic odd one out problem from the aptitude section. You are given four numbers and you must identify which number does not share the same mathematical property as the others. Specifically, this problem focuses on the concept of perfect cubes, which is very common in number system questions in competitive examinations and reasoning tests. Given Data / Assumptions: The given numbers are 27, 8, 64 and 124. All numbers are positive integers. We assume that the intended pattern relates to basic powers of integers such as squares or cubes. Concept / Approach: The main idea is to test whether each number is a perfect cube. A perfect cube is an integer that can be expressed as n^3 for some integer n. If three numbers are perfect cubes and one is not, then the non cube number will be the odd one out. We do not need advanced number theory here, only familiarity with basic cubes of small integers like 2, 3, 4 and 5. Step-by-Step Solution: Step 1: Check 27. We know 3^3 = 27, so 27 is a perfect cube.Step 2: Check 8. We know 2^3 = 8, so 8 is a perfect cube.Step 3: Check 64. We know 4^3 = 64, so 64 is a perfect cube.Step 4: Check 124. There is no integer n such that n^3 = 124. We know 4^3 = 64 and 5^3 = 125, so 124 lies between 4^3 and 5^3 and therefore it is not a perfect cube.Step 5: Since three numbers are perfect cubes and one number is not, the non cube must be the odd one out. Verification / Alternative check: As another quick check, list nearby cubes: 2^3 = 8, 3^3 = 27, 4^3 = 64 and 5^3 = 125. We see that 124 is just one less than 125, so it cannot be a perfect cube. This confirms that 124 is the only number that fails the perfect cube test among the given options. Why Other Options Are Wrong: 27 is wrong as the odd one out because it is a perfect cube, equal to 3^3, so it fits the pattern. 8 is wrong because it is also a perfect cube, equal to 2^3, so it matches the pattern of the majority of the numbers. 64 is wrong as the odd one out because it is again a perfect cube, equal to 4^3, and therefore follows the same property as 8 and 27. Common Pitfalls: Many learners may quickly focus only on the size of the numbers or their even and odd nature rather than checking powers. For example, they might mistakenly think that 27 is different because it is the only odd number, but the actual intended pattern is about perfect cubes. Ignoring mathematical properties like squares and cubes is a frequent mistake in number based reasoning questions. It is also possible for someone to confuse 124 with 125 and assume it is a cube, which is not correct. Final Answer: The only number that is not a perfect cube is 124, so 124 is the correct odd one out.

Question 19

In this aptitude based odd one out question, you must select the number that does not follow the same divisibility property as the other three numbers from the set 5306, 2147, 4205 and 4308.

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Introduction / Context: This question belongs to the odd one out category within quantitative aptitude. The goal is to analyze the given four numbers and identify the one that does not satisfy a common numerical property that the other three share. Such questions often check divisibility, parity, or simple number patterns. Here, the focus is on divisibility by 5, which is an important and very basic concept used frequently in competitive exams. Given Data / Assumptions: The four given numbers are 5306, 2147, 4205 and 4308. All numbers are positive integers. We assume that a simple divisibility rule or pattern is involved. Concept / Approach: One of the fastest approaches in odd one out problems with large integers is to first check basic divisibility rules. The divisibility rule for 5 is very straightforward: a number is divisible by 5 if and only if its last digit is 0 or 5. Therefore, we can focus only on the unit digit of each number. If one number is divisible by 5 and the others are not, that number will be the odd one out; likewise, if three numbers are divisible by 5 and one is not, then the non multiple of 5 is the odd one out. Step-by-Step Solution: Step 1: Check the last digit of 5306. The unit digit is 6, so 5306 is not divisible by 5.Step 2: Check the last digit of 2147. The unit digit is 7, so 2147 is not divisible by 5.Step 3: Check the last digit of 4205. The unit digit is 5, so 4205 is divisible by 5.Step 4: Check the last digit of 4308. The unit digit is 8, so 4308 is not divisible by 5.Step 5: We see that exactly one number, 4205, is divisible by 5. The other three numbers are not divisible by 5. Therefore 4205 is different from the others and is the odd one out. Verification / Alternative check: You can verify by direct division: 4205 / 5 = 841, which is an integer. On the other hand, 5306 / 5, 2147 / 5 and 4308 / 5 do not give integer results. Thus the pattern is confirmed: only 4205 is a multiple of 5 among the four given numbers. Why Other Options Are Wrong: 5306 is not the odd one out because it is a non multiple of 5 and shares this property with 2147 and 4308. 2147 is also a non multiple of 5 and therefore is similar to 5306 and 4308, not unique. 4308 is again a non multiple of 5, so it follows the same divisibility pattern as 5306 and 2147. Common Pitfalls: Sometimes candidates may get distracted by the size or parity of the numbers, such as checking whether the numbers are even or odd. However, that does not isolate a single number here because both even and odd numbers appear more than once. The key is to look for a property that only one number possesses, such as divisibility by 5 in this case. Another common mistake is to overcomplicate the problem by seeking complex patterns instead of applying basic divisibility rules. Final Answer: The only number that is divisible by 5 is 4205, so 4205 is the correct odd one out.

Question 20

In this verbal reasoning odd one out question, you must identify which city name among Washington, New York, Las Vegas and Sydney does not belong to the same country as the others.

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Introduction / Context: This is a general knowledge and verbal reasoning odd one out question involving well known city names. Such questions often test a candidate awareness of world geography and the ability to group items according to a common attribute, such as country, continent, or political status. Here, three cities are from the same country, while one city is from a different country and continent. Given Data / Assumptions: The options are Washington, New York, Las Vegas and Sydney. We interpret Washington as a major city in the United States, not as the broader state name. We assume standard geographical knowledge of countries and continents. Concept / Approach: The core concept is categorization by country. We check which cities belong to the same nation. Washington, New York and Las Vegas are all famous cities in the United States of America. Sydney, on the other hand, is a major city in Australia. Therefore, the odd one out is the city that does not belong to the United States. This type of question reinforces basic world geography and city country mapping which is useful for many competitive examinations. Step-by-Step Solution: Step 1: Washington is the capital city of the United States of America.Step 2: New York is a major city in the United States, located in the state of New York.Step 3: Las Vegas is also a city in the United States, located in the state of Nevada.Step 4: Sydney is a major coastal city in Australia and is not part of the United States; it is located in the state of New South Wales.Step 5: Since three cities are in the United States and one city is in Australia, the city that does not belong to the United States is the odd one out. Verification / Alternative check: You can verify the classification by recalling common country city pairs: Washington USA, New York USA, Las Vegas USA, Sydney Australia. This quick mental mapping confirms that Sydney stands apart by country and continent. Therefore, the geographical criterion unambiguously identifies Sydney as the odd city out. Why Other Options Are Wrong: Washington is not the odd one out because it belongs to the United States, just like New York and Las Vegas. New York is again a United States city and shares the same national identity as Washington and Las Vegas. Las Vegas is in the United States as well and therefore belongs to the same group as Washington and New York. Common Pitfalls: Some learners might overthink the question and consider population size, coastal location, or capital city status. While Washington is a capital and New York is a large financial hub, these differences do not isolate a single city in a consistent way. The cleaner and more reliable classification is by country. Failing to use the country based grouping may lead to confusion or subjective interpretations. Always look for an objective property that clearly separates one option from the rest. Final Answer: Only Sydney is a city in Australia, whereas Washington, New York and Las Vegas are cities in the United States of America, so Sydney is the odd one out.

Odd Man Out and Series Questions