Question 1

In this profession-based odd-man-out question, four items are given: Neurologist, Dentist, Architect and Paediatrician. Three of these are medical specialists, while one is a professional from a completely different field (building design). Which op…

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Introduction / Context: This question is a verbal odd-man-out problem related to professions. The four options in the stem are Neurologist, Dentist, Architect and Paediatrician, which correspond to choices A, B, C and D. In competitive exams, such questions check whether you can classify professions into broader categories like medical, engineering or arts. Here, three professions belong to the field of medicine, while one belongs to architecture and building design. Given Data / Assumptions: Neurologist is a medical doctor specializing in the nervous system. Dentist is a medical professional dealing with teeth and oral health. Paediatrician is a medical doctor specializing in children’s health. Architect is a professional who designs buildings and structures, not a medical practitioner. The options A, B, C and D correspond to Neurologist, Dentist, Architect and Paediatrician respectively. Concept / Approach: The concept is grouping professions by domain. Neurologist, Dentist and Paediatrician all require medical degrees and treat patients. Architect, however, belongs to the field of engineering and design, working with plans, drawings and buildings. By separating medical professions from non-medical ones, we can clearly see which item does not fit the main group. Therefore, the profession that is not a medical specialist is the odd one out, and its corresponding option is the correct answer. Step-by-Step Solution: Step 1: Identify Neurologist as a medical professional focusing on disorders of the brain, spinal cord and nerves. Step 2: Identify Dentist as a medical professional who treats teeth and oral cavity problems. Step 3: Identify Paediatrician as a medical doctor who treats infants and children. Step 4: Identify Architect as a professional who designs buildings, prepares construction plans and works in the field of architecture. Step 5: Observe that Neurologist, Dentist and Paediatrician all belong to medicine, whereas Architect does not. Step 6: Map the professions to options: A = Neurologist, B = Dentist, C = Architect and D = Paediatrician. Therefore, option C is the odd one out. Verification / Alternative check: You can also verify by imagining typical workplaces. Neurologists, Dentists and Paediatricians work in hospitals, clinics or medical centers and treat patients. Architects, on the other hand, generally work in architectural firms, construction companies or design studios and deal with drawings and buildings instead of diagnosing and treating patients. This clear difference in job activities confirms that Architect is the odd profession among the four and that option C is correct. Why Other Options Are Wrong: Option A (Neurologist) represents a doctor and fits into the group of medical specialists, so it is not the odd one out. Option B (Dentist) is also a medical professional dealing with health issues, fitting the medical group perfectly. Option D (Paediatrician) again is a medical doctor who treats children and belongs to the same domain as Neurologist and Dentist. Option C (Architect) is from a different profession altogether and does not belong to the medical field. Common Pitfalls: A common mistake is to focus on how common or familiar a profession is instead of its domain. Some students may pick Dentist simply because it feels different from Neurologist and Paediatrician in terms of specialization, but all three are still doctors. The correct approach is to identify whether the professions are all in the same broad field or not. Another pitfall is forgetting the mapping between the words in the stem and the options A, B, C and D, which can lead to confusion even if the odd profession has been correctly identified. Final Answer: The non-medical profession and therefore the odd one out is Architect, represented by option C.

Question 2

In this alphabet pair odd-man-out question, four pairs are given: KP, MN, HR and GT. For three of these pairs, the sum of the alphabetical positions of the two letters is 27, while in one pair the sum is different. Which option represents the odd pa…

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Introduction / Context: This question is an alphabet-based odd-man-out problem. The pairs given in the stem are KP, MN, HR and GT, mapped to options A, B, C and D. Such questions often involve the numerical positions of letters in the English alphabet (A=1, B=2 and so on). Here, three of the pairs have a constant sum of positions, whereas one pair has a different total. The goal is to find the pair whose positional sum does not match that of the others. Given Data / Assumptions: Option A represents KP. Option B represents MN. Option C represents HR. Option D represents GT. Alphabet positions: A=1, B=2, ..., Z=26. In three pairs, the sum of the positions of the two letters is 27. One pair has a sum that is not equal to 27 and is therefore the odd one out. Concept / Approach: The concept is to convert letters to their numeric positions and compute the sum for each pair. If three sums are equal (here, 27) and one sum is different, the pair with the different sum is the odd pair. This method is straightforward and commonly used in alphabet reasoning questions. It helps you identify hidden numerical patterns behind letter combinations. Step-by-Step Solution: Step 1: For KP, K is the 11th letter and P is the 16th letter. Sum = 11 + 16 = 27. Step 2: For MN, M is the 13th letter and N is the 14th letter. Sum = 13 + 14 = 27. Step 3: For GT, G is the 7th letter and T is the 20th letter. Sum = 7 + 20 = 27. Step 4: For HR, H is the 8th letter and R is the 18th letter. Sum = 8 + 18 = 26. Step 5: Observe that three sums are 27 (KP, MN, GT), while HR has a sum of 26, which is different. Step 6: Conclude that the pair represented by option C (HR) is the odd one out. Verification / Alternative check: To verify, note that pairs whose positions add to 27 may be viewed as forming a near-symmetric pattern, since 27 is one more than 26, the total number of letters. KP, MN and GT all satisfy this special sum. HR, with a sum of 26, breaks this consistency. Rechecking the numeric positions (K=11, P=16, M=13, N=14, G=7, T=20, H=8, R=18) confirms that the calculations are correct and that HR is structurally different from the rest. Why Other Options Are Wrong: Option A (KP) has a positional sum of 27 and fits with options B and D in the main pattern. Option B (MN) also sums to 27 and belongs to the same group as KP and GT. Option D (GT) again sums to 27, so it is consistent with the pattern shared by KP and MN. Option C (HR) alone has a sum of 26, making it different and therefore the correct odd-man-out choice. Common Pitfalls: A common mistake is to miscount the position of letters like K, M or R, which can distort the sums. Another pitfall is to look at the differences between letters instead of their sums, which does not reveal a clear and consistent pattern here. In exam situations, it is useful to confirm both the numeric positions and the addition to avoid arithmetic slips. Once you see that three pairs share the same total and one does not, the correct answer becomes obvious. Final Answer: The letter pair whose positional sum is different and is therefore the odd one out is HR, represented by option C.

Question 3

In this numerical odd-man-out question on number pairs, four pairs are given: 16–28, 20–30, 30–40 and 40–50. In three of these pairs, the difference between the second and first number is 10, whereas in one pair the difference is 12. Which option re…

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Introduction / Context: This question is an odd-man-out problem involving simple number pairs. The pairs mentioned in the stem are 16–28, 20–30, 30–40 and 40–50, mapped to options A, B, C and D. In many basic aptitude questions, relationships between two numbers in a pair are often based on a constant difference, such as adding a fixed number. Here, three of the pairs have a difference of 10 between the second and first number, while one pair has a different difference. The task is to find which pair breaks the constant-difference pattern. Given Data / Assumptions: Option A represents the pair 16–28. Option B represents the pair 20–30. Option C represents the pair 30–40. Option D represents the pair 40–50. In three pairs, second number − first number = 10. One pair has a difference not equal to 10 and is the odd one out. Concept / Approach: The core concept is checking the difference between numbers in each pair. If the difference is constant in three cases and different in one case, the inconsistent pair is the odd one. The pattern in this question is simple addition, so no advanced calculations are required. This type of question tests attention to detail and basic arithmetic accuracy rather than complex reasoning. Step-by-Step Solution: Step 1: For 16–28, compute 28 − 16 = 12. Step 2: For 20–30, compute 30 − 20 = 10. Step 3: For 30–40, compute 40 − 30 = 10. Step 4: For 40–50, compute 50 − 40 = 10. Step 5: Observe that three pairs have a difference of 10, while the pair 16–28 has a difference of 12. Step 6: Conclude that the pair in option A is the odd one out. Verification / Alternative check: An alternative view is to consider how you would generate the second number from the first. For options B, C and D, you can obtain the second number by adding 10 to the first (20 + 10 = 30, 30 + 10 = 40 and 40 + 10 = 50). However, for option A, adding 10 to 16 gives 26, not 28. To get 28 from 16, you must add 12 instead. This confirms that the first pair does not follow the same rule as the others. Why Other Options Are Wrong: Option B (20–30) follows the rule second = first + 10 and therefore fits into the main group of consistent pairs. Option C (30–40) also follows the same rule, with a difference of 10 between the two numbers. Option D (40–50) again maintains the constant difference of 10 and is not the odd one out. Option A (16–28) uses a difference of 12 instead of 10 and therefore breaks the pattern. Common Pitfalls: A common mistake is to overthink the pattern and attempt more complicated operations such as multiplication or ratios, when a simple difference check is sufficient. Another pitfall is arithmetic error, such as miscalculating 28 − 16 or 30 − 20 under time pressure. In odd-man-out questions, always test the simplest numeric relationships first, such as addition or subtraction, and carefully verify the calculations. Final Answer: The pair that does not follow the constant difference of 10 and is therefore the odd one out is 16–28, represented by option A.

Question 4

In the following question, four types of road vehicles are given. Select the one which is different from the other three (odd one out).

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Introduction / Context: This aptitude question is a classic odd one out reasoning problem based on common vehicles. Such questions are frequently asked in competitive exams to test a candidate ability to recognise categories, shared properties, and basic general knowledge about everyday objects. The task is to identify which option does not belong to the same group as the others based on a simple and logical classification rule. Given Data / Assumptions: - We are given five options that are all related to transport on roads. - The options are Car, Jeep, Van, Cycle, and Bus. - We assume all terms refer to their usual everyday meaning as common modes of transport. - We have to pick exactly one option that is different from the other three or four in an objective and logical way. Concept / Approach: The key idea in odd one out questions is to look for a shared feature among most options and then identify which option does not share that feature. Here, we look at whether the vehicle is motorised or non motorised, how many wheels it usually has, and how it is powered. We focus on the most natural and exam friendly classification, which in this case is motor vehicles versus vehicles driven by human effort. Step-by-Step Solution: Step 1: List the options clearly as Car, Jeep, Van, Cycle, and Bus.Step 2: Note that a Car is a motor vehicle with an engine, usually four wheeled and powered by fuel or electricity.Step 3: A Jeep is also a motor vehicle with an engine, mainly used for road and off road travel, and is powered by fuel.Step 4: A Van is again a motor vehicle designed to carry people or goods, and it has an engine.Step 5: A Bus is a larger motor vehicle used to carry many passengers and is powered by an engine.Step 6: A Cycle, however, is generally a bicycle that does not have an engine and is powered by human pedalling.Step 7: Therefore, four options are motor vehicles, but Cycle is a non motorised vehicle, so Cycle is the odd one out. Verification / Alternative Check: As an additional check, we can group the options into motorised and non motorised categories. Car, Jeep, Van, and Bus are all examples of automobiles that require fuel or electricity to run and are usually registered vehicles. A Cycle does not require any fuel, does not have an engine, and relies on human effort. Since only one option falls into the non motorised category, the classification is clear and unambiguous, confirming that Cycle is the correct choice as the odd one out. Why Other Options Are Wrong: Car is incorrect because it is a motor vehicle, similar in nature to Jeep, Van, and Bus. Jeep is incorrect because it is also an engine powered automobile used for passenger transport. Van is incorrect because it is a powered vehicle used for carrying goods or people, very similar in use to the car and bus. Bus is incorrect because it is another large motor vehicle and fits the same category as the other powered automobiles, not the odd one out. Common Pitfalls: Candidates sometimes overthink simple odd one out questions and look for very advanced or hidden patterns, which is not needed here. Another mistake is to focus on the size of the vehicles, for example thinking that Bus is the odd one out because it is much larger. However, size is less important than the basic distinction between motor vehicles and a manually driven vehicle. Staying focused on simple, clear properties like presence or absence of an engine helps avoid confusion in such reasoning questions. Final Answer: Cycle

Question 5

In the following question, each option shows a group of three letters. Select the group of letters that is different from the other three (odd one out).

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Introduction / Context: This reasoning question is based on patterns in sequences of letters from the English alphabet. Odd one out questions like this test a candidate ability to notice directions of movement in the alphabet and consistent differences between consecutive letters. They are common in aptitude and competitive exams where quick recognition of letter patterns is very important. Given Data / Assumptions: - Five letter groups are given as options: WVU, QPO, GED, LKJ, and RQP. - Each group contains exactly three capital letters in sequence. - We assume standard English alphabetical order from A to Z. - Only one group should break a clear pattern that is followed by the remaining groups. Concept / Approach: The natural way to approach such questions is to look at how letters move in the alphabet from left to right within each group. In many exam problems, three of the options show letters in strict alphabetical order, either forward or backward with a fixed step. We need to check whether the letters in each group move forward or backward and whether the size of the step remains consistent. The group that violates this consistent pattern will be the odd one out. Step-by-Step Solution: Step 1: Consider WVU. W, V, and U are consecutive letters in reverse order, moving backward by 1 step each time.Step 2: In QPO, Q goes to P and then to O. These letters are also in reverse order, again moving backward by 1 step each time.Step 3: In LKJ, L, K, and J are also in strict reverse alphabetical order, each step moving backward by 1 letter.Step 4: In RQP, R, Q, and P follow the same reverse pattern, again going back by 1 letter at each step.Step 5: Now consider GED. From G to E the movement is backward by 2 letters, and from E to D the movement is backward by 1 letter. So the steps are not consistent within this group.Step 6: Since all other groups show a simple and consistent backward step of 1, but GED uses unequal backward steps, GED does not fit the common pattern. Verification / Alternative Check: We can quickly verify the pattern by writing down the alphabet positions. W, V, U are 23, 22, 21. Q, P, O are 17, 16, 15. L, K, J are 12, 11, 10. R, Q, P are 18, 17, 16. Each of these sequences decreases by one at each step. For GED, the positions are 7, 5, 4. The first step is a change of minus 2, followed by minus 1. Because these steps differ, GED is the only group that behaves differently, confirming it as the odd one out. Why Other Options Are Wrong: WVU is not odd because its letters are in a clean reverse sequence with a constant step of minus 1. QPO is not odd because it follows the same backward by one pattern as WVU. LKJ is not odd since it also has three consecutive letters going backward by one. RQP is not odd because it still follows the same reverse alphabetical pattern. Hence none of these break the shared rule. Common Pitfalls: A common mistake in such questions is to look only at the direction of movement, for example simply noticing that all are in reverse order and then guessing randomly. However, this question also uses the size of the step as part of the pattern. Another pitfall is to confuse the positions of letters and miscount the gaps. Writing down or mentally tracking the positions carefully avoids such errors and leads to the correct answer faster. Final Answer: GED

Question 6

In the following question, four whole numbers are given. Three of them are prime numbers and one is composite. Select the composite number (odd one out).

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Introduction / Context: This question tests basic number theory concepts that often appear in aptitude and competitive exams. Specifically, it checks whether the learner can distinguish prime numbers from composite numbers. Recognising prime numbers is an essential skill for many reasoning and quantitative topics, including divisibility, factors, and advanced arithmetic problems. Given Data / Assumptions: - The options are five positive integers: 13, 17, 21, 23, and 19. - We use the standard definition of a prime number as a number greater than 1 with exactly two distinct positive factors, 1 and the number itself. - A composite number has more than two positive factors. - Exactly one number among the options is composite and different from the others. Concept / Approach: The approach is to test each number for primality by checking if it has any divisor other than 1 and itself. Small numbers can be checked quickly by testing divisibility with small primes such as 2, 3, 5, and 7. If a number is divisible by one of these and is larger than that prime, then it is composite. For this question, it is enough to check divisibility by 3 and other small primes, because the numbers are not very large. Step-by-Step Solution: Step 1: Check 13. It is not divisible by 2, 3, or 5. Therefore, 13 is a prime number.Step 2: Check 17. It is not divisible by 2, 3, or 5. Therefore, 17 is a prime number.Step 3: Check 23. It is not divisible by 2, 3, or 5. Therefore, 23 is a prime number.Step 4: Check 19. It is not divisible by 2, 3, or 5. Therefore, 19 is also a prime number.Step 5: Now check 21. It is divisible by 3 because 2 + 1 = 3, which is divisible by 3. We can also write 21 = 3 * 7, so it clearly has factors other than 1 and itself.Step 6: Since 21 is divisible by 3 and 7, it is composite, while all the other options are prime numbers. Therefore, 21 is the odd one out. Verification / Alternative Check: We can verify quickly by listing the factors of each number. The factors of 13 are 1 and 13 only. For 17, the factors are 1 and 17. For 23, the factors are 1 and 23. For 19, the factors are 1 and 19. In contrast, the factors of 21 are 1, 3, 7, and 21, which shows that it is composite. Since exactly one number has more than two factors, our classification is correct and the reasoning is consistent. Why Other Options Are Wrong: 13 is not the odd one out because it is a prime number like 17, 19, and 23. 17 is also a prime and therefore similar to 13, 19, and 23, so it cannot be the unique different option. 23 is prime as well and does not stand out when compared with 13, 17, and 19. 19 is another prime number and therefore fits into the same group as the other primes. Only 21 is composite and therefore qualifies as the odd one out. Common Pitfalls: Students sometimes confuse 21 with a prime number because it is not an obvious multiple like 20 or 24. Another common mistake is to test divisibility only by 2 and 5, forgetting to check for 3 and 7. In exams, always test divisibility by the smallest primes first. If a number is not divisible by any of them, only then treat it as prime. This habit will reduce careless mistakes in similar odd one out questions. Final Answer: 21

Question 7

In the following question, different reading and writing related objects are given. Select the one which is different from the other three (odd word).

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Introduction / Context: This verbal reasoning question checks whether the learner can classify common study and stationery related items correctly. Odd one out problems of this type are designed to test general awareness and logical grouping skills. The aim is to see if you can distinguish between reading material and writing tools that are typically used together on a desk or in a classroom. Given Data / Assumptions: - The five options are Novel, Paper, Pencil, Pen, and Notebook. - All of these are items commonly found in an educational or office environment. - A Novel is a type of book that is read for study or enjoyment. - Paper, Pencil, Pen, and Notebook are usually used together as writing and note taking materials. Concept / Approach: The logical approach is to identify which items play the same functional role. In everyday use, Paper, Pencil, Pen, and Notebook are all part of the writing process, where content is created or recorded. A Novel, on the other hand, is already written content that is read. So we can form two broad groups, writing tools and medium versus reading material. The single item that belongs only to the reading category will be the odd one out. Step-by-Step Solution: Step 1: List the items as Novel, Paper, Pencil, Pen, and Notebook.Step 2: Identify the function of a Novel. It is a book containing a long fictional or sometimes non fictional narrative that people read.Step 3: Identify the function of Paper. It is a blank medium on which someone writes, prints, or draws.Step 4: Identify the function of a Pencil and a Pen. Both are instruments used to write or draw on paper or in a notebook.Step 5: A Notebook is a collection of blank pages bound together, again designed for writing, note taking, or drawing.Step 6: Clearly, four items are associated with the act of writing or recording information, while only one item, the Novel, is mainly for reading existing content.Step 7: Therefore Novel is different in purpose and is the odd one out. Verification / Alternative Check: To verify, we can group the options into writing process items versus reading material. Paper, Pencil, Pen, and Notebook are all used together when someone creates notes or writes an essay. A Novel is normally not used to write anything on; instead, it is the final product of writing that the reader consumes. Since there is exactly one reading only item, while the others support writing, the classification is consistent and confirms our answer. Why Other Options Are Wrong: Paper is wrong as the odd one out because it is clearly used with pencils and pens for writing. Pencil is wrong because it is a writing tool, just like a pen and closely connected to paper and notebooks. Pen is wrong since it shares the same function and context as pencil and paper in writing tasks. Notebook is wrong as the odd one out because it is again a writing medium and part of the same group of stationery items used for note taking and recording information. Common Pitfalls: Some learners may focus only on the physical form of the items and get distracted by size or material instead of usage. Others might consider that a notebook is larger than a single sheet of paper and pick it as different. However, aptitude questions usually expect the candidate to look at the primary functional use, not just physical characteristics. Remember to classify by role and purpose to avoid these common mistakes. Final Answer: Novel

Question 8

In the following question, each option shows a group of four letters following a pattern. Select the group of letters that does not follow the same pattern as the others (odd one out).

Accepted Answer

Introduction / Context: This question is a letter based odd one out problem, which is common in reasoning and mental ability sections of aptitude tests. The idea is to examine how letters change within each group and to find a consistent alphabet based pattern. Once the pattern is understood for most options, we can quickly see which group does not follow it and therefore must be selected as the answer. Given Data / Assumptions: - The options are acDD, egHH, ikLL, QSTt, and moPP. - We assume standard alphabetical positions for letters A to Z, where A is 1, B is 2, and so on. - Capital and small letters are considered the same in terms of alphabet position, but their case can still be part of the pattern if needed. - Exactly one option breaks the main rule followed by the others. Concept / Approach: Each group has two lower case letters followed by two repeated upper case letters in most options. The first two letters appear to skip one letter in between, and the last two letters repeat a letter that comes immediately after the second letter of the group. The strategy is to check whether each group follows this pattern regarding alphabet positions and case. The group that does not match this structure is the odd one out. Step-by-Step Solution: Step 1: Consider acDD. Starting from a to c, one letter b is skipped, so there is a gap of 2 positions. The next letter after c is d, which appears twice as DD in upper case, so this fits the pattern.Step 2: Consider egHH. From e to g, one letter f is skipped, again a gap of 2. The next letter after g is h, which appears twice as HH, so this also fits the same pattern.Step 3: Consider ikLL. From i to k, one letter j is skipped, again a difference of 2 positions. The next letter after k is l, which appears twice as LL. This again follows the rule.Step 4: Consider moPP. From m to o, the letter n is skipped, again a gap of 2. The next letter after o is p, which appears twice as PP, so moPP also follows the same pattern.Step 5: Now examine QSTt. Here, Q and S are capital letters, not lower case, and from Q to S the gap is also 2 letters, but the repeated letter is t in a different case, not exactly matching the pattern of two identical upper case letters that immediately follow the second letter.Step 6: Therefore QSTt does not consistently match the structure of the other four options and is the odd one out. Verification / Alternative Check: We can verify by writing alphabet positions. For acDD, a is 1, c is 3, D is 4. For egHH, e is 5, g is 7, H is 8. For ikLL, i is 9, k is 11, L is 12. For moPP, m is 13, o is 15, P is 16. In all these, the positions follow the pattern first letter, first plus two, then repeated letter equal to second plus one. In QSTt, Q is 17, S is 19, T is 20, but the final t is lower case and breaks the consistent formation style. This confirms that QSTt is different from the others. Why Other Options Are Wrong: acDD is not odd because it perfectly follows the skip one, then repeat next letter pattern. egHH is also consistent with the same rule. ikLL continues the same structure and so it cannot be the odd one out. moPP also matches the pattern of using two lower case letters with a gap of two, followed by two identical upper case letters one step ahead of the second letter. Since these four fit nicely into a single rule, they are not correct choices for the odd one out. Common Pitfalls: Some learners may ignore letter case entirely and only look at positions, which can make QSTt appear similar at first glance. Others may focus only on the first two letters, see that all have a gap of two, and mistakenly think there is no difference. In pattern based questions, it is important to look at the full structure, including repetition, letter case, and relative positions. Careful observation prevents wrong guesses and improves accuracy in exam situations. Final Answer: QSTt

Question 9

In the following question, each option shows a pair of numbers. In three of the pairs the second number is 25 more than the first number. Select the pair that does not follow this rule (odd number pair).

Accepted Answer

Introduction / Context: This is a numerical reasoning question focused on identifying a consistent relationship between two numbers in each pair. Odd one out problems like this are common in aptitude tests because they quickly check whether the candidate can recognise a simple arithmetic pattern such as a constant difference between numbers. The goal is to find which pair breaks the shared rule and therefore stands out as different. Given Data / Assumptions: - The number pairs are 65 - 90, 73 - 97, 112 - 137, 162 - 187, and 45 - 70. - Each option shows two numbers separated by a hyphen, which indicates a relationship between the first and second number. - We assume basic arithmetic operations such as addition and subtraction are used to connect the numbers in each pair. - Exactly one pair does not fit the common rule that the other pairs follow. Concept / Approach: The most direct approach is to check the difference between the second and first number in every pair. If three or four pairs show the same difference, that difference defines the main pattern. Any pair with a different difference value will then be the odd one out. This type of reasoning builds confidence with sequences and simple linear relations, which appear frequently in quantitative aptitude sections. Step-by-Step Solution: Step 1: For 65 - 90, compute 90 - 65. The result is 25.Step 2: For 112 - 137, compute 137 - 112. The result is also 25.Step 3: For 162 - 187, compute 187 - 162. The result again is 25.Step 4: For 45 - 70, compute 70 - 45. This difference is 25 as well.Step 5: Now consider 73 - 97. Compute 97 - 73. The result is 24, not 25.Step 6: Since four of the pairs show a difference of exactly 25 but the pair 73 - 97 shows a difference of only 24, 73 - 97 does not follow the rule and is the odd one out. Verification / Alternative Check: To verify quickly, we can also check by mental addition. Adding 25 to the first number in each pair should give the second number if the pair follows the rule. For 65, 65 + 25 = 90. For 112, 112 + 25 = 137. For 162, 162 + 25 = 187. For 45, 45 + 25 = 70. However, for 73, 73 + 25 = 98, which is not equal to 97. This alternative perspective confirms that 73 - 97 does not fit the pattern and so must be the correct answer as the odd one out. Why Other Options Are Wrong: 65 - 90 is not odd because the second number is exactly 25 greater than the first number. 112 - 137 is also consistent with the pattern since the difference is 25. 162 - 187 follows the same rule with a difference of 25. 45 - 70 again shows a difference of 25 and fits the main pattern. None of these pairs break the rule, so they cannot be chosen as the odd one out. Common Pitfalls: Candidates sometimes miscalculate simple differences, especially under time pressure, and may think that 97 - 73 equals 25. Another mistake is to look for more complicated relationships such as ratios or squares when a simple constant difference is enough. In exam settings, always test for basic operations like addition and subtraction first, because they are often used to create these straightforward odd one out questions. Final Answer: 73 - 97

Question 10

In the following question, names of colours are given. Select the colour that is different from the other three (odd one out).

Accepted Answer

Introduction / Context: This verbal reasoning question tests basic knowledge of colours and the ability to classify them logically. Odd one out questions about colours are common in aptitude tests because they combine simple general knowledge with pattern recognition. The focus here is on identifying which colour does not belong to the same natural group as the others, based on well known colour properties. Given Data / Assumptions: - The five options are Red, Brown, Green, Yellow, and Blue. - All are common colour names used in daily life and in basic school level science. - We consider the standard rainbow or spectrum colours, often remembered as a set of pure hues. - Exactly one colour does not behave like a pure spectrum colour in the way the others do. Concept / Approach: Many exam questions use the idea of pure spectrum colours, which are the colours that appear in a prism or a rainbow. Typical examples include Red, Orange, Yellow, Green, Blue, Indigo, and Violet. Brown, however, is usually treated as a mixture or a shade rather than a pure spectral colour. Therefore, a natural approach is to separate spectrum colours from mixed or derived colours and see which option does not fit the spectral group. Step-by-Step Solution: Step 1: Identify which of the options are commonly regarded as spectrum colours. Red, Yellow, Green, and Blue all appear in the standard rainbow list.Step 2: Recognise that Brown is not part of the typical spectrum sequence. It is formed by mixing other colours, often including red and green or other combinations.Step 3: Group Red, Yellow, Green, and Blue together as pure or primary and secondary spectral hues.Step 4: Observe that Brown is fundamentally different in that it is a composite shade rather than a pure spectral hue.Step 5: Since exactly one option is a non spectral, mixed shade while the others are well known spectrum colours, Brown is the odd one out. Verification / Alternative Check: Another way to verify is to recall that in school level science demonstrations, when white light passes through a prism, colours like Red, Yellow, Green, and Blue appear in order, but Brown does not appear as a distinct band. Brown is produced by combining other colours and usually needs a context such as a darker background or surrounding colours. The fact that Brown relies on mixing, whereas the others stand alone as spectral hues, confirms it as the odd one out in this list. Why Other Options Are Wrong: Red is not the odd one out because it is a core spectrum colour and groups naturally with Yellow, Green, and Blue. Green is also a key spectrum colour and often used as a primary colour in digital displays. Yellow appears prominently in the rainbow and therefore belongs in the same group. Blue is another fundamental spectrum colour seen both in the rainbow and in basic colour theory. Each of these four shares the property of being a pure spectral hue, so none of them can be classified as the odd one out here. Common Pitfalls: Sometimes test takers may think of frequency or psychological impact and overcomplicate the pattern. Others may decide that Yellow is odd because it appears brighter, which is subjective. In reasoning questions, the expected solution is usually based on clear, objective categories, such as spectral versus non spectral colours. Remember to look for standard scientific or widely taught groupings rather than personal impressions of brightness or preference. Final Answer: Brown

Question 11

In the following question, each option is a group of four letters. In three of the options the first two letters move forward in the alphabet and the last two letters move backward. Select the group that does not follow this pattern (odd one out).

Accepted Answer

Introduction / Context: This is a letter pattern recognition question, a common type in logical reasoning and mental ability tests. The options show groups of four letters in which the positions of the letters in the alphabet follow a particular movement. The candidate needs to identify the consistent rule used in most groups and then pick the group that does not follow that rule, which becomes the odd one out. Given Data / Assumptions: - The options are FIHG, CGEF, JMLK, VYXW, and SVUT. - We assume standard English alphabetical order from A to Z with positions A = 1, B = 2, and so on. - Each group has four letters and may combine forward and backward movement in the alphabet. - Exactly one group breaks the main pattern followed by the others. Concept / Approach: The pattern can often be found by checking the numerical difference between consecutive letters. Here, a useful idea is that in many groups two letters increasing by a fixed amount are followed by two letters that decrease by a smaller fixed amount. By converting letters to positions and calculating differences, we can compare all the options and see which one behaves differently. Letter based odd one out questions reward systematic checking rather than guesswork. Step-by-Step Solution: Step 1: For FIHG, the positions are F = 6, I = 9, H = 8, G = 7. The first movement is from 6 to 9, which is +3. The next movements are 9 to 8 and 8 to 7, both equal to minus 1.Step 2: For JMLK, the positions are J = 10, M = 13, L = 12, K = 11. The change 10 to 13 is +3, then 13 to 12 is minus 1, and 12 to 11 is minus 1, the same pattern as in FIHG.Step 3: For VYXW, V = 22, Y = 25, X = 24, W = 23. This gives changes of +3, then minus 1, then minus 1. Again, it follows the same pattern.Step 4: For SVUT, S = 19, V = 22, U = 21, T = 20. The differences are +3, then minus 1, then minus 1. So this group also follows the same rule.Step 5: For CGEF, C = 3, G = 7, E = 5, F = 6. The movement from C to G is +4, not +3. Then the movement from E to F is +1, not minus 1. So the pattern is different here.Step 6: Therefore, CGEF does not follow the +3, then minus 1, minus 1 pattern that appears in the other groups and is the odd one out. Verification / Alternative Check: We can also visualise this by writing each group as forward then backward. FIHG can be seen as F to I moving forward and then stepping back from I to H and H to G. JMLK and VYXW behave the same way. SVUT continues this structure, which confirms a strong, shared pattern. CGEF, however, does not have a balanced forward then backward arrangement; it has a larger jump forward and then ends with two letters that are not both moving backward. This mismatch confirms that CGEF is different from the other four groups. Why Other Options Are Wrong: FIHG is not odd because the movements between letters match the required pattern exactly. JMLK is also fully consistent with the rule and fits neatly with FIHG. VYXW again keeps the same difference structure and therefore cannot be the odd one out. SVUT follows the same pattern of a three step forward move followed by two one step backward moves, so it clearly belongs to the main group. Only CGEF fails to follow this structure and so is the correct answer as the odd one out. Common Pitfalls: A frequent mistake is to look only at whether letters are increasing or decreasing without checking the actual size of the step. Another pitfall is to consider only the first two letters in each group and ignore what happens in the last two positions. To avoid such errors, always compute the differences between all neighbouring letters. That extra care ensures you see the complete pattern and correctly identify the odd one out choice in letter based reasoning questions. Final Answer: CGEF

Question 12

In the following question, names of outdoor and indoor games are given. Select the game that is different from the other three (odd one out).

Accepted Answer

Introduction / Context: This odd one out question is based on common games and sports, a regular topic in verbal and logical reasoning tests. It checks whether the learner can classify activities according to where and how they are typically played. The central idea here is to distinguish between large field based team sports and indoor board games that have very different playing conditions and equipment. Given Data / Assumptions: - The options are Football, Hockey, Carrom, Cricket, and Badminton. - Football, Hockey, and Cricket are well known outdoor field sports played on large grounds. - Carrom is a tabletop or board game usually played indoors. - Badminton is usually played on a court, which can be indoors or outdoors, but it is still a physical racket sport. Concept / Approach: A practical way to approach this problem is to identify the basic nature of each game. Field sports involve teams, running, and a large playing area. Board games like Carrom are played on a small board, usually sitting at a table, and involve minimal physical movement. By grouping games into field sports versus board or indoor table games, we can see which one does not belong to the same group as the others. Step-by-Step Solution: Step 1: Consider Football. It is a field sport played on a large ground with two teams and a ball.Step 2: Consider Hockey. It is also a field or turf sport played outdoors or in a large indoor arena, again with two teams competing.Step 3: Consider Cricket. Cricket is another field game, played on a large ground with bats, a ball, and two teams.Step 4: Consider Badminton. Badminton is a racket sport played on a court with a net and shuttlecock; it is a physically active game similar in nature to other sports.Step 5: Consider Carrom. Carrom is a tabletop board game played by flicking striker coins to hit carrom men into pockets. It is normally played sitting down and does not require a full sized field or court.Step 6: Since four of the options are physical sports played on grounds or courts, but Carrom is a board game, Carrom is clearly the odd one out. Verification / Alternative Check: We can verify the classification by thinking about the equipment and venue. Football, Hockey, and Cricket require a ground, goalposts or wickets, and a ball. Badminton needs a court with a net and rackets. All these are considered physical sports under the category of games and athletics. Carrom, however, requires a carrom board, small wooden or plastic coins, and a striker. It is grouped under indoor or parlour games rather than outdoor sports. This clear distinction confirms that Carrom is the odd one out. Why Other Options Are Wrong: Football is not the odd one out because it aligns with Hockey and Cricket as a popular field game. Hockey similarly shares the traits of a team sport on a large playing area. Cricket is again a classic outdoor team sport, and although it is different in rules, it belongs with Football and Hockey in the same broad category. Badminton, while played on a court rather than a field, is still an athletic sport involving continuous movement and physical activity. Thus these four options belong together and are not the odd one out. Common Pitfalls: Students may sometimes pick Badminton as different because it uses a racket instead of a ball, but the standard exam logic focuses on whether a game is a sport or a board game. Another pitfall is to overanalyse the number of players, but that can vary widely across all sports. The safest approach is to consider whether the game is a physical field or court sport or a tabletop game. This leads to the correct choice without confusion. Final Answer: Carrom

Question 13

In the following question, each option shows a series of three English letters in increasing order. Select the group that does not follow the same spacing pattern as the others (odd letters).

Accepted Answer

Introduction / Context: This letter series question checks how well the learner can observe and compare patterns in alphabetical sequences. Odd one out problems of this style are very common in reasoning tests, especially in sections dealing with sequences and series. The key idea is to notice the step size between letters in each option and find which one does not match the common rule. Given Data / Assumptions: - The options are ACE, FHJ, QTW, KMO, and PRT. - Each group contains three letters in English alphabetical order, not jumbled words. - We use standard positions where A is 1, B is 2, and so on up to Z as 26. - Exactly one letter group does not maintain the same step size pattern as the other groups. Concept / Approach: In many exam problems, letter sequences are formed by skipping a fixed number of letters between consecutive characters. Here, we need to compute how many letters are skipped between the first and second letter and between the second and third letter in each group. If four groups show a step of plus 2 between letters, but one shows a different spacing, that one will be the odd one out. Step-by-Step Solution: Step 1: Consider ACE. The positions are A = 1, C = 3, E = 5. From A to C, the step is +2, and from C to E, the step is also +2.Step 2: Consider FHJ. The positions are F = 6, H = 8, J = 10. From F to H and from H to J, both steps are +2, so this matches ACE.Step 3: Consider KMO. The positions are K = 11, M = 13, O = 15. Again, both movements are +2, matching the same pattern.Step 4: Consider PRT. The positions are P = 16, R = 18, T = 20. This also follows a consistent +2 step pattern between consecutive letters.Step 5: Now consider QTW. The positions are Q = 17, T = 20, W = 23. From Q to T the step is +3, and from T to W the step is also +3, not +2.Step 6: Since ACE, FHJ, KMO, and PRT all use a step of +2, but QTW uses a step of +3, QTW is the group that does not follow the common pattern. Verification / Alternative Check: We can verify again by counting letters directly in the alphabet. For example, starting from A and moving two steps forward gives C, then another two steps gives E. The same behavior is seen with F to H to J, K to M to O, and P to R to T. In contrast, starting at Q, moving two steps forward would produce S, not T, so QST would follow the plus 2 pattern, but QTW moves three steps from Q to T and another three to W. This confirms that QTW does not belong with the other sequences and must be the odd one out. Why Other Options Are Wrong: ACE is not the odd one out because its letters are separated by a constant gap of two positions, matching the base pattern. FHJ also maintains the same gap and therefore fits neatly into the group. KMO continues this rule with a step of two between letters. PRT again follows the plus two pattern and is fully consistent with the majority. Since these four share the same type of regular spacing, none of them can be chosen as the odd one out. Common Pitfalls: Test takers sometimes look only at whether letters are in alphabetical order and overlook the size of the step between them. Another pitfall is to be distracted by the visual appearance of letters or to think that rare letters like Q and W must automatically be odd. The correct approach is always to compute the numerical differences between letter positions. That method avoids guesswork and makes series based odd one out questions much easier to solve accurately. Final Answer: QTW

Question 14

In the following question, four multiples of 11 are given. Three of them are not perfect squares, and one is a perfect square. Select the odd number from the given alternatives.

Accepted Answer

Introduction / Context: This numerical reasoning question involves identifying a special property among multiples of 11. Odd one out problems like this check understanding of factors, squares, and basic number relationships. Recognising perfect squares is especially important in many competitive exams, since squares often appear in algebra, geometry, and data interpretation questions. Given Data / Assumptions: - The options given are 121, 44, 66, 111, and 132. - Each of these numbers is a multiple of 11, so they all share a basic factor based property. - A perfect square is an integer that can be written as n * n for some integer n. - Exactly one of these multiples of 11 is also a perfect square, which makes it the odd one out. Concept / Approach: The main concept here is to identify which number is a perfect square. Every option is a multiple of 11, so simply checking divisibility by 11 will not help us separate them. Instead, we need to see which number can be written as the square of an integer. We can quickly test the nearby square numbers and see whether any match the given options. The number that is a perfect square while the others are not will be the answer. Step-by-Step Solution: Step 1: List some square numbers close to our options. For example, 10^2 = 100, 11^2 = 121, and 12^2 = 144.Step 2: Notice that 121 appears exactly as 11^2. Therefore 121 is a perfect square and a multiple of 11.Step 3: Examine 44. It is equal to 4 * 11. There is no integer n such that n * n = 44, so it is not a perfect square.Step 4: Examine 66. It is 6 * 11 and again does not equal any integer square.Step 5: Examine 111. It is 11 * 10 plus 1, but it is not equal to n * n for any integer n, so it is not a perfect square.Step 6: Examine 132. It is 12 * 11 and again not equal to any integer square.Step 7: Since only 121 is both a multiple of 11 and a perfect square, it is different from the others and is the odd one out. Verification / Alternative Check: We can also verify by considering the square roots. The square root of 121 is exactly 11, an integer. The approximate square root of 44 is a little above 6, but not an integer. The square root of 66 is between 8 and 9, but not an integer. The square root of 111 is a little more than 10, and again not an integer. The square root of 132 is between 11 and 12, but not an integer. Since only 121 gives an integer square root, it confirms that 121 is the only perfect square in the list and is therefore the odd one out. Why Other Options Are Wrong: 44 is not correct as the odd one out because, although it is a multiple of 11, it lacks the special square property and is just like 66, 111, and 132 in this respect. 66 is also a non square multiple of 11 and so does not stand out in this group. 111 is again a multiple of 11 but not a perfect square, so it remains in the main category. 132 is similar, as it is only a regular multiple of 11. Only 121 has the distinct property of being 11 * 11, which the question is designed to highlight. Common Pitfalls: Sometimes students focus only on the number of digits and might be tempted to choose 44 or 66 because they are two digit numbers, or 111 because it looks special with repeated digits. However, the test setter expects you to recognise the perfect square pattern. To avoid mistakes, always recall common squares like 11^2 = 121 and 12^2 = 144 and compare them with the options provided. This small habit can significantly improve accuracy in questions about square numbers and odd one out patterns. Final Answer: 121

Question 15

In the following question, each option is a group of four letters. Three groups are random letter combinations, while one forms a meaningful English word. Select the odd one out.

Accepted Answer

Introduction / Context: This odd one out question is based on vocabulary and pattern recognition. In many reasoning tests, examiners mix random letter combinations with one or more meaningful English words. The task is then to identify which option has a clear meaning in everyday language, distinguishing it from meaningless strings of characters. This kind of question checks both word recognition and attention to detail. Given Data / Assumptions: - The options are CZHK, MLAG, XVBU, SEND, and TRQP. - All options are four letter strings written in capital letters. - We assume normal English vocabulary without using abbreviations or codes. - Exactly one option is a meaningful, commonly used English word, while the others are not. Concept / Approach: The most straightforward approach is to read each option and check if it forms a valid English word. Random letter combinations will not carry meaning, while actual words will be familiar from daily use, reading, or communication. The one meaningful word can then be identified as the odd one out because it belongs to a different category than the other options, which are simply sequences of letters with no standard dictionary meaning. Step-by-Step Solution: Step 1: Look at CZHK. It does not form any standard English word and appears to be a random arrangement of letters.Step 2: Look at MLAG. Again, it does not correspond to a common English word and looks like another random combination.Step 3: Look at XVBU. This also does not match any known English word and is likely meaningless as a normal word.Step 4: Look at TRQP. This sequence does not form any standard English word either and appears random.Step 5: Now examine SEND. This is a very common English verb used in daily communication, meaning to cause something to go to another person or place.Step 6: Since only SEND has a clear dictionary meaning while the other four options are random letter sequences, SEND is the odd one out. Verification / Alternative Check: To verify, we can think of how these letter groups would be used in a sentence. We can easily use SEND in many sentences such as Send the message or Send the parcel, which confirms that it is a meaningful word. In contrast, it is not possible to insert CZHK, MLAG, XVBU, or TRQP into a normal sentence without them sounding like codes or nonsense fragments. This confirms that SEND belongs to a completely different category and must be chosen as the unique odd one out option. Why Other Options Are Wrong: CZHK is wrong as the odd one out because it has no standard meaning and matches the pattern of random letters. MLAG is also just a sequence of letters without dictionary meaning, so it belongs with CZHK and the other non words. XVBU has no simple pronunciation or meaning and therefore is not special in this list. TRQP again is meaningless as a normal English word and fits the same group of random sequences. Since all four of these are similar in having no meaning, none can be the odd one out. Common Pitfalls: A common pitfall is overthinking the letter arrangements and trying to find hidden patterns such as alphabetical jumps or codes where the examiner simply wants you to notice a real word. Another mistake is to assume that any option with a familiar letter pattern, such as starting with a common consonant, must be special. In vocabulary based odd one out questions, the safest strategy is to focus on clear dictionary words. This way, SEND stands out immediately while the other options remain just letter clusters. Final Answer: SEND

Question 16

In the following question, names of wild animals are given. Three belong to the cat family and one does not. Select the animal that is different from the other three (odd one out).

Accepted Answer

Introduction / Context: This general knowledge based odd one out question focuses on animal classification. It tests whether the learner can recognise which animals belong to the cat family and which do not. Such questions are popular in reasoning and biology awareness sections because they rely on basic zoology that students often learn in school, such as grouping animals by family or type. Given Data / Assumptions: - The options are Lion, Panther, Tiger, Wolf, and Leopard. - Lion, Panther, Tiger, and Leopard are all big cats and belong to the family Felidae. - Wolf is a wild animal but belongs to the dog family, known as Canidae. - We assume the common biological classification of animals into families based on their characteristics. Concept / Approach: To solve this, we need to understand that animals can be grouped into families such as cats and dogs based on body structure, behavior, and evolutionary relationships. The first step is to identify which animals are big cats. Lions, tigers, panthers, and leopards are classic examples of big cats with similar body types and hunting styles. A wolf, however, is a wild dog and not part of the cat family. The one animal that does not fit into the cat family will be the odd one out. Step-by-Step Solution: Step 1: Consider Lion. Lions are large carnivorous animals that clearly belong to the cat family.Step 2: Consider Panther. Panther is a common name used for big cats such as leopards or jaguars, again part of the cat family.Step 3: Consider Tiger. Tigers are another well known big cat species with stripes and powerful bodies.Step 4: Consider Leopard. Leopards are spotted big cats, again belonging to the Felidae family.Step 5: Consider Wolf. A wolf is a wild canine animal known for living and hunting in packs.Step 6: Since Lion, Panther, Tiger, and Leopard are all big cats, while Wolf is a dog like animal from a different family, Wolf is the odd one out. Verification / Alternative Check: We can verify by recalling common phrases and classifications. Lions, tigers, panthers, and leopards appear together in lists and documentaries about big cats. They share traits such as retractable claws, cat like faces, and similar hunting styles. Wolves, however, are grouped with animals like dogs, foxes, and coyotes. They have different physical features, including non retractable claws and a different skull structure. This clear difference confirms that Wolf does not belong to the big cat group and must be the odd one out. Why Other Options Are Wrong: Lion is not the odd one out because it is a classic member of the cat family. Panther is not odd because it is simply another type of big cat. Tiger also fits the same family and therefore is similar to Lion and Panther. Leopard again is a big cat and behaves very much like the others in hunting and movement. These four together form a single category, so none of them can be selected as the odd one out. Common Pitfalls: Some learners may feel confused by the word Panther because it is sometimes used loosely in popular media, but it still refers to big cats. Another pitfall is focusing on size or color alone instead of family classification. Remember that odd one out questions typically rely on scientific or widely accepted categories, such as animal families. By using that classification, the correct answer becomes clear and misunderstandings are avoided. Final Answer: Wolf

Question 17

In the following question, each option shows a pair of numbers separated by a comma. In three of the pairs the second number is one less than the cube of the first number. Select the pair that does not follow this rule (odd pair).

Accepted Answer

Introduction / Context: This numerical reasoning question involves a relationship between two numbers in each pair based on cubes. Odd one out questions of this type are used in aptitude exams to test whether candidates can quickly identify arithmetic patterns like squares and cubes. Recognising these patterns helps in many areas of mathematics, including sequences, algebra, and problem solving. Given Data / Assumptions: - The options are the pairs 5,124; 7,342; 3,26; 2,15; and 4,63. - The first number in each pair is a small positive integer. - The second number is related to the cube of the first number in some way. - Exactly one pair does not follow the same rule that the other pairs follow. Concept / Approach: The pattern described is that in three of the pairs, the second number equals the cube of the first number minus 1. That is, if the first number is n, the second number should be n^3 - 1. To apply this approach, we compute the cube of the first number in each pair and then subtract 1, and compare the result with the given second number. The pair in which this relation does not hold will be the odd one out. Step-by-Step Solution: Step 1: For the pair 5,124, compute the cube of 5. We get 5^3 = 5 * 5 * 5 = 125. Subtract 1 to get 125 - 1 = 124, which matches the second number.Step 2: For 7,342, compute the cube of 7. We get 7^3 = 343. Subtract 1 to get 343 - 1 = 342, which again matches the second number.Step 3: For 3,26, compute the cube of 3. We get 3^3 = 27. Subtract 1 to get 27 - 1 = 26, which matches the second number.Step 4: For 4,63, compute the cube of 4. We get 4^3 = 64. Subtract 1 to get 64 - 1 = 63, which matches the second number.Step 5: For 2,15, compute the cube of 2. We get 2^3 = 8. Subtract 1 to get 8 - 1 = 7, which does not match the second number 15.Step 6: Since four pairs correctly follow the rule second number = first number cubed minus 1, and only the pair 2,15 fails to match this rule, 2,15 is the odd one out. Verification / Alternative Check: We can verify this pattern by writing the relationship explicitly for each valid pair. For 5,124 we have 124 = 5^3 - 1. For 7,342 we have 342 = 7^3 - 1. For 3,26 we have 26 = 3^3 - 1. For 4,63 we have 63 = 4^3 - 1. For 2,15 the relation would require 15 to be equal to 2^3 - 1, but 2^3 - 1 = 7, not 15. Therefore this pair does not satisfy the same mathematical rule and is correctly identified as the odd one out. Why Other Options Are Wrong: 5,124 is not wrong because it fits the pattern exactly, with 124 equal to 5^3 - 1. 7,342 also fits perfectly since 342 equals 7^3 - 1. 3,26 matches the rule with 26 equal to 3^3 - 1. 4,63 again respects the relation because 63 equals 4^3 - 1. All of these share the same cube minus one structure and so belong to the main group of consistent pairs. Common Pitfalls: A common mistake is to assume that the relation is second number equals first number squared or some other operation, and then to give up when the numbers do not match. Another pitfall is doing cube calculations incorrectly under time pressure. To avoid errors, always compute n^3 carefully, then subtract 1, and compare the result with the given second number. Understanding the cube relation used in this question improves overall skill with powers and patterns in aptitude tests. Final Answer: 2,15

Question 18

In the following question, each option shows a group of three English letters. In three of the groups the letters are consecutive in alphabetical order. Select the group that does not follow this rule (odd letters).

Accepted Answer

Introduction / Context: This logical reasoning question uses short alphabet sequences to test pattern recognition. Odd one out problems based on letters often rely on whether the letters are consecutive in alphabetical order. Candidates need to check if each group of letters forms a natural sequence or if there is a break in the pattern. The one that does not follow the same rule becomes the answer. Given Data / Assumptions: - The options are LMN, PPQ, RST, VWX, and DEF. - Each option consists of three capital letters from the English alphabet. - Consecutive letters mean that each letter follows directly after the previous one in alphabetical order, such as D, E, F. - Exactly one group does not form such a simple consecutive sequence of three distinct letters. Concept / Approach: The main idea is to see whether each option is of the form X, Y, Z where Y = X plus one letter in the alphabet and Z = Y plus one letter. If all three letters are different and appear one after another in alphabetical order, that option fits the main pattern. Any option that repeats a letter or does not follow this strict ordering of three consecutive letters is the odd one out. Step-by-Step Solution: Step 1: Examine LMN. The letters L, M, and N follow each other directly in the alphabet, so LMN is a perfect consecutive sequence.Step 2: Examine RST. The letters R, S, and T are again consecutive letters, making another correct alphabetical sequence.Step 3: Examine VWX. The letters V, W, and X follow one another in order, so this is also a correct sequence.Step 4: Examine DEF. The letters D, E, and F are clearly consecutive letters as well.Step 5: Examine PPQ. Here the letters are P, P, and Q. P is repeated and then followed by Q. This does not form a sequence of three distinct consecutive letters.Step 6: Since LMN, RST, VWX, and DEF are all sequences of three distinct consecutive letters, while PPQ has repetition and does not match the pattern, PPQ is the odd one out. Verification / Alternative Check: A quick check is to assign positions. L, M, N are 12, 13, 14. R, S, T are 18, 19, 20. V, W, X are 22, 23, 24. D, E, F are 4, 5, 6. In each case, we have a simple pattern of plus 1 between letters. For PPQ, the positions are P = 16, P = 16, Q = 17. The jump from the first P to the second P is zero, not plus 1, and only the last step is plus 1. This breaks the rule and confirms PPQ as the odd group. Why Other Options Are Wrong: LMN is not odd because it forms a perfect consecutive series of three letters. RST is also fully consistent with the expected pattern. VWX is again a correct set of consecutive letters, so it belongs with the main group. DEF remains another clear example of three letters that follow each other directly. Since all of these match the pattern of three distinct consecutive letters, none of them can be selected as the odd one out. Common Pitfalls: Some students may focus only on whether Q appears, thinking it is unusual, but that is not the intended rule. Others may overlook the repetition in PPQ because they are scanning quickly. The correct habit is to check each position carefully and confirm that the sequence is strictly increasing by one letter. Recognising this structure makes similar alphabet based odd one out questions much easier to answer correctly in exams. Final Answer: PPQ

Question 19

In the following question, four positive integers are given. Three of them are prime numbers and one is composite. Select the composite number (odd one out).

Accepted Answer

Introduction / Context: This odd one out question again focuses on prime and composite numbers, a very important concept in quantitative aptitude. Recognising primes quickly is useful not only in simple classification questions but also in topics like factorisation, modular arithmetic, and number series. The task here is to spot the one composite number among four prime numbers. Given Data / Assumptions: - The options are 80, 17, 13, 31, and 19. - A prime number is greater than 1 and has exactly two positive divisors, 1 and itself. - A composite number has more than two positive divisors. - Exactly one number in the given list is composite, and that number is the odd one out. Concept / Approach: The most efficient strategy is to check each number for divisibility by small primes such as 2, 3, 5, and 7. If a number is divisible by any of these and is larger than the divisor, it is composite. Small primes like 13, 17, 19, and 31 are well known and often memorised, so identifying them is usually quick. The remaining number that clearly has many factors is the one we should select as the odd one out. Step-by-Step Solution: Step 1: Examine 17. It is not divisible by 2, 3, 5, or 7. Therefore, 17 is a prime number.Step 2: Examine 13. It is not divisible by 2, 3, or 5, so it is also a prime number.Step 3: Examine 31. It is not divisible by 2, 3, or 5. It is also not divisible by 7, so 31 is a prime number.Step 4: Examine 19. It is not divisible by 2, 3, or 5, which makes it another prime number.Step 5: Examine 80. It is clearly divisible by 2, since 80 = 2 * 40. It is also divisible by 4, 5, 8, 10, and other numbers. Therefore 80 has many factors and is a composite number.Step 6: Since 17, 13, 31, and 19 are primes while 80 is composite, 80 is the only number that does not belong to the prime group and is the odd one out. Verification / Alternative Check: We can verify by listing factors. The factors of 80 include 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. This confirms that 80 is composite. For 17, the only factors are 1 and 17. For 13, the only factors are 1 and 13. For 31, the only factors are 1 and 31. For 19, the only factors are 1 and 19. Since only 80 has more than two factors, it is correctly identified as the odd one out. Why Other Options Are Wrong: 17 is not the odd one out because it is a prime and shares this property with 13, 19, and 31. 13 is also prime and fits into the same category. 31 is prime, so it belongs with the other primes. 19 is again prime and therefore not unique in this list. All four of these behave similarly as prime numbers, so none can be chosen as the odd one out. Common Pitfalls: Under exam pressure, some candidates might mistakenly classify 19 or 31 as composite because they do not quickly recall their prime status. Others may focus on the size of the numbers instead of checking divisibility. A good practice is to quickly test divisibility by small primes whenever you see an odd one out question based on numbers. This approach ensures that you correctly identify composite numbers like 80 versus prime numbers in the options. Final Answer: 80

Question 20

In the following question, names of common kitchen items are given. Three are pieces of cutlery used for eating, and one is a serving dish. Select the odd word from the given alternatives.

Accepted Answer

Introduction / Context: This odd one out question tests everyday knowledge of kitchen items and tableware. It is a type of classification question frequently used in reasoning and general awareness sections. The task is to distinguish between items used directly to eat food and items used to hold or serve food. Recognising this distinction helps in quickly identifying the option that belongs to a different functional category. Given Data / Assumptions: - The options are Knife, Fork, Plate, Spoon, and Chopsticks. - Knife, Fork, Spoon, and Chopsticks are typical eating implements or pieces of cutlery. - A Plate is usually used to hold and serve food, not to put food into the mouth directly. - We assume standard dining usage of these items in a household or restaurant setting. Concept / Approach: A simple and effective approach is to group items based on their primary function at the dining table. Cutlery items are instruments used to cut, pick up, or carry food to the mouth. Serving ware items, like plates, bowls, and trays, hold the food but are not used as tools to eat with. By identifying which option is serving ware rather than cutlery, we can locate the odd one out easily and accurately. Step-by-Step Solution: Step 1: Consider Knife. A knife is a piece of cutlery used mainly to cut food into smaller pieces.Step 2: Consider Fork. A fork is used to pick up and hold food, and it functions as a cutlery item.Step 3: Consider Spoon. A spoon is used to scoop liquids and small food items and is clearly part of the cutlery group.Step 4: Consider Chopsticks. Chopsticks are used to pick up and eat food, serving as cutlery especially in many Asian cuisines.Step 5: Consider Plate. A plate is a flat dish on which food is served and placed, but it is not used to put food directly into the mouth.Step 6: Since Knife, Fork, Spoon, and Chopsticks are all direct eating implements, while Plate is serving ware, Plate is the item that does not belong with the others. Verification / Alternative Check: To verify, imagine setting a dining table. You usually place plates on the table and then add cutlery such as knives, forks, spoons, and sometimes chopsticks next to the plate. The plate stays under the food, while cutlery items are held in the hand during eating. This physical difference in how the items are used confirms that Plate belongs to a different category from the other four, and so Plate is correctly identified as the odd one out. Why Other Options Are Wrong: Knife is not the odd one out because it functions like Fork, Spoon, and Chopsticks as an eating instrument. Fork is another common piece of cutlery and clearly matches the Knife and Spoon in use. Spoon also belongs to the same group as it is used for eating and serving small portions. Chopsticks belong with the other cutlery items because they are used to pick up food and bring it to the mouth. Since all four are eating tools, none of them can be the odd item here. Common Pitfalls: One possible mistake is to focus on cultural usage and think that Chopsticks are different simply because they are less common in some regions. However, the exam logic is based on function, not regional familiarity. Another pitfall is to group items visually by shape rather than by use. In reasoning questions, always prioritise functional classification. When you do, it becomes clear that Plate, as serving ware, is the correct odd one out choice. Final Answer: Plate

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