A leaves mid-way; B finishes the remainder A can do a job in 10 days and B in 20 days. They start together, but after 5 days A leaves. In how many days will B complete the remaining work?

Difficulty: Easy

Correct Answer: 5 days

Explanation:


Introduction / Context:
When one worker leaves part-way, compute the completed fraction so far, then divide the remainder by the staying worker’s rate.



Given Data / Assumptions:

  • A: 10 days ⇒ 1/10 per day.
  • B: 20 days ⇒ 1/20 per day.
  • They work together for the first 5 days.


Concept / Approach:
Together rate = 1/10 + 1/20 = 3/20 per day. Remaining = 1 − (3/20)*5.



Step-by-Step Solution:

Work in first 5 days = (3/20) * 5 = 15/20 = 3/4Remaining = 1 − 3/4 = 1/4B’s rate = 1/20 ⇒ time = (1/4) / (1/20) = 5 days


Verification / Alternative check:
Total job = 3/4 + (1/4) = 1. Timings are consistent.



Why Other Options Are Wrong:
6, 8, 10 contradict B’s fixed rate of 1/20 for a quarter job.



Common Pitfalls:
Adding 5 directly to an option instead of calculating the leftover fraction properly.



Final Answer:
5 days

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