Difficulty: Easy
Correct Answer: 2) The call s.fun(1, 5) will work correctly. 4) The call Sample.fun(1, 5) cannot work since fun() is not static.
Explanation:
Introduction / Context:
This scenario distinguishes between instance members and static members in C#. It also touches on accessibility of fields and arrays declared as public.
Given Data / Assumptions:
Concept / Approach:
Instance members must be accessed through an instance (object). Static members are accessed via the type name. Public accessibility allows direct access, but that does not change instance vs. static binding rules.
Step-by-Step Solution:
Verification / Alternative check:
Attempt to compile Sample.fun(1, 5); the compiler reports that an object reference is required for the non-static field, method, or property.
Why Other Options Are Wrong:
They include false statements (1, 3, 5) or omit the valid statement 2.
Common Pitfalls:
Confusing 'public' with 'static'; public only controls accessibility, not whether a member belongs to the instance or the type.
Final Answer:
2) The call s.fun(1, 5) will work correctly. 4) The call Sample.fun(1, 5) cannot work since fun() is not static.
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