C#.NET — Trace the output of this instance-method call. namespace CuriousTabConsoleApplication { class Sample { int i; float j; public void SetData(int i, float j) { this.i = i; this.j = j; } public void Display() { Console.WriteLine(i + " " + j); } } class MyProgram { static void Main(string[] args) { Sample s1 = new Sample(); s1.SetData(36, 5.4f); s1.Display(); } } } What will be printed?
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A0 0.0
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B36 5.4
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C36 5.400000
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D36 5
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ENone of the above
Answer
Correct Answer: 36 5.4
Explanation
Introduction / Context:This question reinforces understanding of instance fields, the this reference, and default numeric formatting when writing to the console in C#.
Given Data / Assumptions:
- Fields: int i; float j;
- SetData assigns i = 36, j = 5.4f via this.
- Display prints i and j separated by a space.
Concept / Approach:After SetData, the object s1 holds i = 36 and j = 5.4. Console.WriteLine concatenates numeric to string via ToString(); float.ToString() with default format usually prints a minimal precise representation like 5.4 (culture permitting), not 5.400000.
Step-by-Step Solution:
Call s1.SetData(36, 5.4f) → fields set.Call s1.Display() → writes i + " " + j → "36 5.4".Verification / Alternative check:Run the exact code in a default console app; you will see 36 5.4. If you require fixed decimals, you would use j.ToString("F6").
Why Other Options Are Wrong:(a) prints defaults which do not apply after SetData. (c) shows six decimals which is not the default. (d) truncates the float which doesn’t happen automatically.
Common Pitfalls:Assuming float prints with six decimals by default (that is a formatting choice, not the default behavior).
Final Answer:36 5.4