C#.NET — Trace the output of this instance-method call. namespace CuriousTabConsoleApplication { class Sample { int i; float j; public void SetData(int i, float j) { this.i = i; this.j = j; } public void Display() { Console.WriteLine(i + " " + j); } } class MyProgram { static void Main(string[] args) { Sample s1 = new Sample(); s1.SetData(36, 5.4f); s1.Display(); } } } What will be printed?

Difficulty: Easy

Correct Answer: 36 5.4

Explanation:


Introduction / Context:
This question reinforces understanding of instance fields, the this reference, and default numeric formatting when writing to the console in C#.



Given Data / Assumptions:

  • Fields: int i; float j;
  • SetData assigns i = 36, j = 5.4f via this.
  • Display prints i and j separated by a space.


Concept / Approach:
After SetData, the object s1 holds i = 36 and j = 5.4. Console.WriteLine concatenates numeric to string via ToString(); float.ToString() with default format usually prints a minimal precise representation like 5.4 (culture permitting), not 5.400000.



Step-by-Step Solution:

Call s1.SetData(36, 5.4f) → fields set.Call s1.Display() → writes i + " " + j → "36 5.4".


Verification / Alternative check:
Run the exact code in a default console app; you will see 36 5.4. If you require fixed decimals, you would use j.ToString("F6").



Why Other Options Are Wrong:
(a) prints defaults which do not apply after SetData. (c) shows six decimals which is not the default. (d) truncates the float which doesn’t happen automatically.



Common Pitfalls:
Assuming float prints with six decimals by default (that is a formatting choice, not the default behavior).



Final Answer:
36 5.4

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